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A telescope has an objective with a refractive power of 1.25 diopters and an eyepiece with a refractive power of 250 diopters. What is the angular magnification of the telescope?

Short Answer

Expert verified
The angular magnification of the telescope is 200.

Step by step solution

01

Understand the Problem

The question provides the refractive power of a telescope's objective and eyepiece. The goal is to determine the angular magnification of the telescope based on these values.
02

Recall the Formula for Angular Magnification

The angular magnification of a telescope can be calculated using the formula: \( M = \frac{P_e}{P_o} \), where \( M \) is the angular magnification, \( P_e \) is the refractive power of the eyepiece, and \( P_o \) is the refractive power of the objective.
03

Substitute the Given Values into the Formula

Substitute the given refractive powers into the magnification formula: \( M = \frac{250}{1.25} \).
04

Perform the Calculation

Calculate the angular magnification by dividing the refractive power of the eyepiece by the refractive power of the objective: \( M = \frac{250}{1.25} = 200 \).
05

Interpret the Result

The calculation shows that the angular magnification of the telescope is 200, meaning that the telescope enlarges the angle of view 200 times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Refractive Power
Refractive power, often expressed in "diopters" (D), is a measure of how much a lens can bend light. It is calculated as the reciprocal of the focal length of the lens in meters. For instance, a lens with a focal length of 1 meter has a refractive power of 1 diopter. A shorter focal length means a higher refractive power, because the lens can bend light more aggressively:
  • A lens with 0.5 meters focal length has 2 diopters.
  • A lens with 2 meters focal length has 0.5 diopters.
Refractive power is essential in the design of various optical instruments, including telescopes, as it determines the ability of lenses to focus light at specific distances. When constructing a telescope, the refractive powers of both the objective lens and eyepiece are crucial for determining the telescope's overall magnification.
Telescope Objective
The telescope objective is the main lens (or mirror in some telescopes) at the front-end of the telescope. Its primary role is to collect and focus light. The objective lens has a specific refractive power, which affects how light is collected and where it is focused. For telescopes:
  • Larger objectives gather more light, which is particularly useful for viewing dim objects like distant stars.
  • The refractive power tells us how the objective bends incoming light to form a clear image.
  • In the example problem, the objective has a refractive power of 1.25 diopters, indicating its capacity to focus at a relatively modest focal length.
This element is critical because it directly impacts the distance over which the light is focused and thereby affects the telescope's overall performance.
Eyepiece
The eyepiece of a telescope serves the crucial function of magnifying the image formed by the objective lens. It is essentially a small lens with high refractive power, which provides detailed views of the magnified image to the observer. Key aspects of an eyepiece include:
  • It determines the telescope's total magnification alongside the objective lens.
  • A high refractive power, as seen in the example's 250 diopter eyepiece, indicates a powerful ability to enlarge the image.
  • The combination of the eyepiece and objective determines how many times larger an object appears through the telescope compared to the naked eye.
The eyepiece must be carefully chosen to match the telescope's focal point to ensure the image is both magnified and clear.
Diopters
Diopters are the unit of measurement for refractive power. Used extensively in the world of optics, diopters dictate how sharply a lens can bend incoming light rays. They are inverse to the focal length in meters:
  • 1 diopter = 1 meter focal length.
  • 5 diopters = 0.2 meter focal length.
This inverse relationship helps in adjusting lenses of different capabilities like those in eyeglasses, cameras, and telescopes. Understanding diopters:
  • Helps in comparing the power of different lenses.
  • Is vital for calculating magnification, particularly in optical instruments like telescopes.
In the telescope example, knowing that the eyepiece has 250 diopters and the objective has 1.25 diopters provides the basis for determining the telescope's angular magnification—a key factor for astronomers and hobbyists alike.

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Most popular questions from this chapter

A farsighted person can read printing as close as 25.0 cm when she wears contacts that have a focal length of 45.4 cm. One day, she forgets her contacts and uses a magnifying glass, as in Figure 26.39b. Its maximum angular magnification is 7.50 for a young person with a normal near point of 25.0 cm. What is the maximum angular magnification that the magnifying glass can provide for her?

A refracting telescope has an angular magnification of 83.00. The length of the barrel is 1.500 m. What are the focal lengths of (a) the objective and (b) the eyepiece?

The distance between an object and its image formed by a diverging lens is 49.0 cm. The focal length of the lens is 233.0 cm. Find (a) the image distance and (b) the object distance.

The back wall of a home aquarium is a mirror that is a distance of 40.0 cm away from the front wall. The walls of the tank are negligibly thin. A fish, swimming midway between the front and back walls, is being viewed by a person looking through the front wall. The index of refraction of air is nair 1.000 and that of water is n water 1.333. (a) Calculate the apparent distance between the fish and the front wall. (b) Calculate the apparent distance between the image of the fish and the front wall. The index of refraction of air is \(n_{\mathrm{air}}=1.000\) and that of water is \(n_{\text { water }}=1.333 .\) (a) Calculate the apparent distance between the fish and the front wall. (b) Calculate the apparent distance between the image of the fish and the front wall.

A microscope for viewing blood cells has an objective with a focal length of 0.50 cm and an eyepiece with a focal length of 2.5 cm. The distance between the objective and eyepiece is 14.0 cm. If a blood cell subtends an angle of 2.1 \(\times 10^{-5}\) rad when viewed with the naked eye at a near point of \(25.0 \mathrm{cm},\) what angle (magnitude only) does it subtend when viewed through the microscope?

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