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The lengths of three telescopes are \(L_{\mathrm{A}}=455 \mathrm{mm}, L_{\mathrm{B}}=615 \mathrm{mm},\) and \(L_{\mathrm{C}}=824 \mathrm{mm}\) . The focal length of the eyepiece for each telescope is 3.00 \(\mathrm{mm}\) . Find the angular magnification of each telescope.

Short Answer

Expert verified
The angular magnifications are 151.67, 205, and 274.67 for telescopes A, B, and C, respectively.

Step by step solution

01

Understand the Formula

The angular magnification of a telescope is given by the formula \( M = \frac{f_o}{f_e} \), where \( f_o \) is the focal length of the objective lens (in this case, the length of the telescopes) and \( f_e \) is the focal length of the eyepiece.
02

Calculate Magnification for Telescope A

For Telescope A, use \( M_A = \frac{L_A}{f_e} = \frac{455\, \text{mm}}{3.00\, \text{mm}} \). Calculate \( M_A \).
03

Calculate Magnification for Telescope B

For Telescope B, use \( M_B = \frac{L_B}{f_e} = \frac{615\, \text{mm}}{3.00\, \text{mm}} \). Calculate \( M_B \).
04

Calculate Magnification for Telescope C

For Telescope C, use \( M_C = \frac{L_C}{f_e} = \frac{824\, \text{mm}}{3.00\, \text{mm}} \). Calculate \( M_C \).
05

Final Calculations

Perform the divisions for each telescope:1. \( M_A = \frac{455}{3} = 151.67 \)2. \( M_B = \frac{615}{3} = 205 \)3. \( M_C = \frac{824}{3} \approx 274.67 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Magnification
Understanding angular magnification is key when discussing telescopes. Angular magnification tells us how much larger an object appears through the telescope compared to the naked eye. The formula for angular magnification \( M \) is
  • \( M = \frac{f_o}{f_e} \)
where \( f_o \) is the focal length of the objective lens and \( f_e \) is the focal length of the eyepiece.
The higher the angular magnification, the larger the object will appear when viewed through the telescope. This means that a telescope with a higher angular magnification can show more detail of distant objects, making it ideal for stargazing and observing planets.
However, it's important to remember that higher magnification can also lead to a smaller field of view and decreased brightness.
Focal Length
The focal length of a lens is the distance between the lens and the point where it converges light rays to form a sharp image. In telescopes, there are two crucial focal lengths:
  • The focal length of the objective lens, \( f_o \)
  • The focal length of the eyepiece, \( f_e \)
The focal length influences how much the light is bent by the lens. A longer focal length generally results in a higher magnification because it allows you to focus more tightly on a distant object.
In the context of the given exercise, the telescopes have the following total lengths which serve as their objective lens focal lengths:
  • Telescope A: 455 mm
  • Telescope B: 615 mm
  • Telescope C: 824 mm
These lengths significantly impact the telescopes' magnification power.
Objective Lens
The objective lens is the primary lens of a telescope that gathers light from a distant object and focuses it to create an image. The size and focal length of the objective lens play a vital role in determining the light gathering ability and the resolving power of the telescope.
The larger the diameter of the objective lens, the more light it can collect, which is essential for viewing faint celestial objects. Furthermore, the focal length of this lens is directly used in calculating the angular magnification, as described earlier.
In the exercise, the objective lens of each telescope corresponds to the telescopes' total lengths:
  • Telescope A: 455 mm
  • Telescope B: 615 mm
  • Telescope C: 824 mm
Thus, longer telescopes with longer objective lens focal lengths offer higher magnification.
Eyepiece
The eyepiece is the lens through which you view the image created by the objective lens. It further magnifies the image, contributing to the overall magnification of the telescope.
The focal length of the eyepiece \( f_e \) is crucial because it determines how much the image from the objective lens is magnified. A shorter focal length in the eyepiece results in a higher magnification.
In the exercise, each telescope uses an eyepiece with a 3.00 mm focal length, standardized across all the models:
  • Telescope A: Eyepiece focal length = 3.00 mm
  • Telescope B: Eyepiece focal length = 3.00 mm
  • Telescope C: Eyepiece focal length = 3.00 mm
By standardizing the eyepiece focal length, we can clearly attribute differences in magnification to variations in the focal length of the objective lens.

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Most popular questions from this chapter

An object is in front of a converging lens \((f=0.30 \mathrm{m}) .\) The magnification of the lens is \(m=4.0 .\) (a) Relative to the lens, in what direction should the object be moved so that the magnification changes to \(m=-4.0 ? \quad\) (b) Through what distance should the object be moved?

The near point of a naked eye is 25 cm. When placed at the near point and viewed by the naked eye, a tiny object would have an angular size of \(5.2 \times 10^{-5}\) rad. When viewed through a compound microscope, however, it has an angular size of \(-8.8 \times 10^{-3}\) rad. (The minus sign indicates that the image produced by the microscope is inverted.) The objective of the microscope has a focal length of 2.6 cm, and the distance between the objective and the eyepiece is 16 cm. Find the focal length of the eyepiece.

In a compound microscope, the objective has a focal length of 0.60 cm, while the eyepiece has a focal length of 2.0 cm. The separation between the objective and the eyepiece is L 12.0 cm. Another microscope that has the same angular magnification can be constructed by interchanging the two lenses, provided that the distance between the lenses is adjusted to a value \(L^{\prime}\) , Find \(L^{\prime}\)

The far point of a nearsighted person is 6.0 m from her eyes, and she wears contacts that enable her to see distant objects clearly. A tree is 18.0 m away and 2.0 m high. (a) When she looks through the contacts at the tree, what is its image distance? (b) How high is the image formed by the contacts?

(a) For a diverging lens is \((f=-20.0 \mathrm{cm})\) construct a ray diagram to scale and find the image distance for an object that is 20.0 cm from the lens. (b) Determine the magnification of the lens from the diagram.

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