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Light that is polarized along the vertical direction is incident on a sheet of polarizing material. Only 94% of the intensity of the light passes through the sheet and strikes a second sheet of polarizing material. No light passes through the second sheet. What angle does the transmission axis of the second sheet make with the vertical?

Short Answer

Expert verified
The transmission axis of the second sheet is at \( 102.34^{\circ} \) with the vertical, meaning \( 12.34^{\circ} \) from the horizontal.

Step by step solution

01

Understand Light Polarization

Light waves can oscillate in different directions. Polarized light has waves vibrating in only one direction. When light passes through a polarizing filter, only the light vibrating in the direction of the filter's transmission axis can pass through.
02

Analyze the Situation

Given that polarized light along the vertical direction passes through the first sheet and 94% of its intensity remains, this means that the first polarizing sheet's axis is very close to the direction of the incoming light but not perfectly aligned.
03

Applying Malus's Law

Malus's Law \[ I = I_0 \cos^2(\theta) \]where \( I \) is the transmitted intensity, \( I_0 \) is the initial intensity, and \( \theta \) is the angle between the light's initial polarization direction and the transmission axis of the polarizer. From the first polarizer, \( \cos^2(\theta) = 0.94 \). Solving, we find \( \theta_1 \approx 12.34^{\circ} \).
04

Determine Transmission Axis of Second Sheet

The second sheet does not allow any light to pass through. For this to happen, it is aligned perpendicular to the direction of the light passing through the first sheet. This means the angle between the first sheet's transmission axis and the second sheet's axis is \( 90^{\circ} - 12.34^{\circ} \).
05

Final Calculation for Angle with Vertical

Since no light passes through the second sheet, this means the second polarizer is at \( 90^{\circ} \) to the light emerging from the first polarizer. Therefore, considering the alignment with the vertical, the angle of the transmission axis of the second sheet with the vertical is \( 12.34^{\circ} + 90^{\circ} = 102.34^{\circ} \), reducing to \( 102.34^{\circ} - 90^{\circ} = 12.34^{\circ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus's Law
Malus's Law is a fundamental principle in understanding polarized light and how it behaves as it passes through polarizing filters. The law states that the intensity of light that passes through a polarizing filter depends on the angle between the light's initial polarization direction and the filter's transmission axis. This relationship can be expressed mathematically as:\[ I = I_0 \cos^2(\theta) \]Where:
  • \( I \) is the transmitted intensity, or the intensity of light after it passes through the filter.
  • \( I_0 \) is the initial intensity, or the intensity of the incoming light before it encounters the filter.
  • \( \theta \) is the angle between the direction of the light's polarization and the transmission axis of the filter.
This means that if the transmission axis is aligned with the light's polarization, all the light passes through. As the angle increases, less light gets through. Once the angle hits 90 degrees, no light is transmitted because the polarization directions are perpendicular to each other.
polarizing filter
A polarizing filter is a special type of filter used in optics to permit light vibrations in one particular direction while absorbing vibrations in other directions. When non-polarized light, which vibrates in multiple directions, encounters a polarizing filter, only the light vibrating parallel to the filter's transmission axis will pass through. This makes the transmitted light "polarized." Polarizing filters are commonly used in photography to reduce reflections, enhance colors, and increase contrast. Similarly, in sunglasses, they help reduce glare by blocking horizontally polarized light that typically reflects off surfaces like water or roads. In practical applications:
  • A polarizing filter can be rotated to adjust the intensity and angle of the light that it transmits.
  • They are essential tools not only in optics but also in enhancing the quality of visual outputs in various displays.
  • Stacking two polarizing filters can provide different effects based on their relative orientation.
Understanding how these filters work helps in appreciating their role in controlling and manipulating light in both everyday technology and scientific research.
transmission axis
The transmission axis of a polarizing filter is a crucial concept in light polarization. It represents the direction in which the light waves are allowed to pass through the filter. When incoming light is polarized, only the components of the light wave parallel to the transmission axis are transmitted. In our exercise, we dealt with two sheets of polarizing material:
  • The first filter's transmission axis allows vertically polarized light to pass through, closely aligned with the incident light's polarization.
  • The light exiting the first filter is partially absorbed if the axis isn't perfectly vertical, leading to a 94% intensity passage.
  • The second filter is set such that its axis is orthogonal to the light coming through the first, completely blocking it as it requires the transmission axis to be perpendicular to the first sheet's exit polarization direction.
Understanding the transmission axis helps explain why selective angles of polarized light get transmitted or blocked. It is essential for manipulating light in environments where directional light filtering is needed. Determining the right orientation is valuable in designing optical systems and applications.

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Most popular questions from this chapter

The average intensity of light emerging from a polarizing sheet is \(0.764 W/ m^{2},\) and the average intensity of the horizontally polarized light incident on the sheet is 0.883 \(W / m^{2}\) . Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Suppose that the light falling on the polarizer in Figure 24.21 is partially polarized (average intensity \(=\bar{S}_{\mathrm{P}}\) ) and partially unpolarized (average intensity \(=\bar{S}_{\mathrm{U}}\) ). The total incident intensity is \(\bar{S}_{\mathrm{P}}+\bar{S}_{\mathrm{U}},\) and the percentage polarization is \(100 \bar{S}_{\mathrm{P}} /\left(\bar{S}_{\mathrm{P}}+\bar{S}_{\mathrm{U}}\right) .\) When the polarizer is rotated in such a situation, the intensity reaching the photocell varies between a minimum value of \(\bar{S}_{\min }\) and a maximum value of \(\bar{S}_{\max }\). Show that the percentage polarization can be expressed as \(100\left(\bar{S}_{\max }-\bar{S}_{\min }\right) /\left(\bar{S}_{\max }+\bar{S}_{\min }\right)\)

A certain type of laser emits light that has a frequency of \(5.2 \times 10^{14} \mathrm{Hz}\) . The light, however, occurs as a series of short pulses, each lasting for a time of \(2.7 \times 10^{-11}\) s. (a) How many wavelengths are there in one pulse? \((b)\) The light enters a pool of water. The frequency of the light remains the same, but the speed of the light slows down to \(2.3 \times 10^{8} \mathrm{m} / \mathrm{s} .\) How many wavelengths are there now in one pulse?

A truck driver is broadcasting at a frequency of 26.965 \(\mathrm{MHz}\) with a CB (citizen's band) radio. Determine the wavelength of the electromagnetic wave being used. The speed of light is \(c=2.9979 \times 10^{8} \mathrm{m} / \mathrm{s} .\)

An electromagnetic wave strikes a \(1.30-cm^{2}\) section of wall perpendicularly. The rms value of the wave's magnetic field is determined to be \(6.80 \times 10^{-4}\) T. How long does it take for the wave to deliver 1850 \(J\) of energy to the wall?

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