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A series RCL circuit includes a resistance of \(275 \Omega,\) an inductive reactance of \(648 \Omega,\) and a capacitive reactance of 415\(\Omega .\) The current in the circuit is 0.233 A. What is the voltage of the generator?

Short Answer

Expert verified
The voltage of the generator is approximately 84.03 V.

Step by step solution

01

Determine Total Opposition to Current (Impedance)

In an RCL circuit, the total impedance \( Z \) is given by the formula \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \] where \( R \) is the resistance, \( X_L \) is the inductive reactance, and \( X_C \) is the capacitive reactance. Insert the given values into the formula: \[ Z = \sqrt{275^2 + (648 - 415)^2} \] \[ Z = \sqrt{275^2 + 233^2} \] \[ Z = \sqrt{75625 + 54289} \] \[ Z = \sqrt{129914} \] \[ Z \approx 360.37 \Omega \].
02

Calculate the Voltage of the Generator

The voltage across an RCL circuit can be found using Ohm's Law for AC circuits: \( V = IZ \), where \( I \) is the current and \( Z \) is the impedance. Given that the current \( I = 0.233 \) A, compute the voltage: \[ V = 0.233 \times 360.37 \] \[ V \approx 84.03 \text{ V} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impedance Calculation
In an RCL circuit, calculating the impedance is crucial for determining how the circuit opposes the flow of alternating current. Impedance, denoted as \( Z \), is essentially the total opposition a circuit offers and is a combination of resistance, as well as inductive and capacitive reactance. The formula used for impedance in an RCL series circuit is:
\[ Z = \sqrt{R^2 + (X_L - X_C)^2} \]
Here:
  • \( R \) is the resistance, representing how much the circuit resists the current flow.
  • \( X_L \) is the inductive reactance, the opposition due to the inductor, which increases with frequency.
  • \( X_C \) is the capacitive reactance, the opposition due to the capacitor, which decreases with frequency.

To find \( Z \), first, compute \((X_L - X_C)\) to determine the net reactance, and then use the Pythagorean theorem-like formula above. This calculation essentially sums up the resistive and net reactive effects in a single numerical value showing how the circuit behaves under AC.
Ohm's Law for AC Circuits
Ohm's Law for AC circuits is an extension of the classic Ohm's Law used in DC circuits. It describes the relationship between voltage, current, and impedance in an AC circuit. In formula terms, it is written as:
\[ V = IZ \]
Where:
  • \( V \) is the voltage across the circuit.
  • \( I \) is the current flowing through the circuit.
  • \( Z \) is the impedance.

This formula allows us to calculate the voltage provided by the AC source given the current and total impedance. For instance, if you know the impedance calculated in an RCL circuit, multiplying it by the current gives you the voltage across the circuit.
This application of Ohm's Law is valuable in practical scenarios, such as finding the necessary generator voltage for a specific circuit configuration. The calculation reflects the real-world conditions of AC circuits, including the influence of frequency on reactance components like inductors and capacitors.
Inductive and Capacitive Reactance
In RCL circuits, inductive and capacitive reactance play critical roles in determining the circuit's overall impedance and behavior under alternating current. Let's break these down:
**Inductive Reactance (\(X_L\))**
- It's a measure of an inductor's opposition to changes in current.- Calculated using \( X_L = 2\pi fL \), where \( f \) is the frequency and \( L \) is the inductance.- Higher frequency leads to higher inductive reactance.
**Capacitive Reactance (\(X_C\))**
- It's a measure of a capacitor's opposition to changes in voltage.- Calculated using \( X_C = \frac{1}{2\pi fC} \), where \( C \) is the capacitance.- Higher frequency leads to lower capacitive reactance.
Both reactances show how components behave at different frequencies, pivotal for tuning circuits for specific purposes. Balancing these affects the overall impedance and hence the circuit's current and voltage relationship.

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Most popular questions from this chapter

In one measurement of the body’s bioelectric impedance, values of \(Z=4.50 \times 10^{2} \Omega\) and \(\phi=-9.80^{\circ}\) are obtained for the total impedance and the phase angle, respectively. These values assume that the body's resistance \(R\) is in series with its capacitance \(C\) and that there is no inductance \(L\) . Determine the body's resistance andcapacitive reactance.

A capacitor is attached to a 5.00-Hz generator. The instanta- neous current is observed to reach a maximum value at a certain time. What is the least amount of time that passes before the instantaneous voltage across the capacitor reaches its maximum value?

The capacitance in a series RCL circuit is \(C_{1}=2.60 \mu \mathrm{F}\) , and the corresponding resonant frequency is \(f_{01}=7.30 \mathrm{kHz}\) . The generator frequency is 5.60 \(\mathrm{kHz}\) . What is the value of the capacitance \(C_{2}\) that should be added to the circuit so that the circuit will have a resonant frequency that matches the generator frequency? Note that you must decide whether \(C_{2}\) is added in series or in parallel with \(C_{1} .\)

A series RCL circuit contains only a capacitor \((C=6.60 \mu \mathrm{F})\) an inductor \((L=7.20 \mathrm{mH})\) , and a generator \((\text {peak voltage}=32.0 \mathrm{V}\) frequency \(=1.50 \times 10^{3} \mathrm{Hz}\) . When \(t=0\) s, the instantaneous value of the voltage is zero, and it rises to a maximum one- quarter of a period later. (a) Find the instantaneous value of the voltage across the capacitor/inductor combination when \(t=1.20 \times 10^{-4}\) s. (b) What is the instantaneous value of the current when \(t=1.20 \times 10^{-4}\) s? \((\text { Hint: }\) The instantaneous values of the voltage and current are, respectively, the vertical components of the voltage and current phasors.)

A \(2700-\Omega\) resistor and a \(1.1-\mu \mathrm{F}\) capacitor are connected in series across a generator \(60.0 \mathrm{Hz}, 120 \mathrm{V}\) ). Determine the power delivered to the circuit.

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