/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 An inductor has an inductance of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An inductor has an inductance of 0.080 H. The voltage across this inductor is 55 V and has a frequency of 650 Hz. What is the current in the inductor?

Short Answer

Expert verified
The current in the inductor is approximately 0.1684 A.

Step by step solution

01

Identify Given Values

Before solving the problem, we need to identify the given values: the inductance \( L = 0.080 \) H, the voltage \( V = 55 \) V, and the frequency \( f = 650 \) Hz.
02

Calculate Angular Frequency

The angular frequency \( \omega \) can be calculated using the formula \( \omega = 2 \pi f \). Substituting the given frequency, \( \omega = 2 \pi \times 650 \).
03

Substitute and Calculate Angular Frequency

Compute \( \omega \) as \( \omega = 2 \pi \times 650 \approx 4084.07 \) rad/s.
04

Calculate Inductive Reactance

The inductive reactance \( X_L \) is calculated using the formula \( X_L = \omega L \). This gives us \( X_L = 4084.07 \times 0.080 = 326.73 \text{ ohms} \).
05

Determine Current

Using Ohm's Law for AC circuits, \( I = \frac{V}{X_L} \), substitute the values: \( I = \frac{55}{326.73} \).
06

Calculate Current

Compute the current \( I = \frac{55}{326.73} \approx 0.1684 \) A.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductance
Inductance is a fundamental property of electrical circuits, especially when dealing with inductors. It is the ability of an inductor to store energy in a magnetic field when an electric current flows through it. Unlike resistors, which resist the flow of current, inductors resist changes in the current. Inductance, denoted by the symbol \( L \), is measured in henrys (H). One henry is defined as the amount of inductance required to produce an electromotive force of one volt when the current changes at one ampere per second.Inductors are commonly used in electrical circuits for filtering, tuning, and energy storage purposes. In AC circuits, inductance causes the current to lag behind the voltage, which can affect the overall circuit performance. This behavior is particularly important when designing circuits for high-frequency applications.Key points:
  • Inductance is measured in henrys (H).
  • It reflects the inductor's ability to store energy in a magnetic field.
  • Inductance affects the timing between current and voltage in circuits.
Angular Frequency
Angular frequency is a measure of how quickly an AC circuit oscillates. It describes the rate of change of the phase of the waveform, expressed in radians per second (rad/s). The formula for angular frequency \( \omega \) is given by \( \omega = 2 \pi f \), where \( f \) is the frequency of the signal in Hertz (Hz). This formula simply transforms the linear frequency to a rotational speed, appropriate for the sinusoidal nature of AC waveforms. Angular frequency is crucial in understanding how alternating currents vary over time and provides a bridge between time-domain and frequency-domain analyses in electrical engineering.Some basic characteristics include:
  • Expressed in radians per second (rad/s).
  • Calculated using the formula \( \omega = 2 \pi f \).
  • Helps in analyzing sinusoidal signals and AC waveforms.
Inductive Reactance
Inductive reactance is the opposition that an inductor offers to the flow of alternating current. It is similar to resistance but applies specifically to AC circuits. The concept reflects how inductance influences and limits the flow of current depending on the frequency of the AC signal.The formula to calculate inductive reactance \( X_L \) is \( X_L = \omega L \), where \( \omega \) is the angular frequency and \( L \) is the inductance. The result is expressed in ohms (Ω), indicating how many ohms of opposition the inductor puts forward against the current flow.Inductive reactance increases with higher frequencies, meaning that inductors block high-frequency signals more efficiently than low-frequency ones. Consider these definitions:
  • Inductive reactance is measured in ohms (Ω).
  • Calculated as \( X_L = \omega L \).
  • Blocks higher frequencies better than lower frequencies.
Ohm’s Law for AC Circuits
Ohm’s Law for AC circuits is a critical concept that helps find the relationship between voltage, current, and impedance in alternating current systems. Unlike DC circuits, AC circuits involve quantities like reactance and impedance, complicating the basic form of Ohm's Law.The formula \( I = \frac{V}{Z} \) where \( V \) is the voltage, \( I \) is the current, and \( Z \) is the impedance, mirrors the classic Ohm's Law \( V = IR \) for DC circuits but accounts for complex quantities. In purely inductive circuits, impedance \( Z \) is equal to the inductive reactance \( X_L \), thus \( I = \frac{V}{X_L} \). Using this law allows us to accurately calculate how much current flows through an AC circuit given a certain voltage and impedance.Key aspects:
  • AC Ohm’s Law: \( I = \frac{V}{Z} \).
  • Impedance \( Z \) may include resistive and reactive components.
  • In inductive circuits, \( Z \) reduces to \( X_L \) (inductive reactance).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Part a of the drawing shows a resistor and a charged capacitor wired in series. When the switch is closed, the capacitor discharges as charge moves from one plate to the other. Part b shows the amount q of charge remaining on each plate of the capacitor as a function of time. In part c of the drawing, the switch has been removed and an ac generator has been inserted into the circuit. The circuit elements in the drawing have the following values: \(R=18 \Omega, V_{\operatorname{ms}}=24 \mathrm{V}\) for the generator, and \(f=380 \mathrm{Hz}\) for the generator. The time constant for the circuit in part \(a\) is \(\tau=3.0 \times 10^{-4} \mathrm{s}\) . What is the rms current in the circuit in part \(c ?\)

A \(2700-\Omega\) resistor and a \(1.1-\mu \mathrm{F}\) capacitor are connected in series across a generator \(60.0 \mathrm{Hz}, 120 \mathrm{V}\) ). Determine the power delivered to the circuit.

Two identical capacitors are connected in parallel to an ac generator that has a frequency of 610 Hz and produces a voltage of 24 V. The current in the circuit is 0.16 A. What is the capacitance of each capacitor?

A \(63.0-\mu \mathrm{F}\) capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is 4.00 \(\mathrm{V}\) and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches 15.0 \(\mathrm{A}\) . As the generator frequency is increased, at what frequency will the fuse burn out?

A generator is connected to a resistor and a 0.032-H inductor in series. The rms voltage across the generator is 8.0 V. When the generator frequency is set to 130 Hz, the rms voltage across the inductor is 2.6 V. Determine the resistance of the resistor in this circuit.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.