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The resistances of the primary and secondary coils of a transformer are 56 and \(14 \Omega,\) respectively. Both coils are made from length of the same copper wire. The circular turns of each coil have the same diameter. Find the turns ratio \(N_{s} / N_{p} .\)

Short Answer

Expert verified
The turns ratio \( \frac{N_s}{N_p} \) is \( \frac{1}{4} \).

Step by step solution

01

Understand the Relationship between Length, Cross-sectional Area, and Resistance

In the given problem, both coils are made from the same copper wire, meaning their volume is the same. Given that resistance \( R \) is directly proportional to the length \( L \) and inversely proportional to the cross-sectional area \( A \), the resistance can be defined as \( R = \rho \frac{L}{A} \), where \( \rho \) is the resistivity of the material. Since the cross-sectional area is constant, if the length is the same, the resistance ratio is equal to the length ratio.
02

Analyze the Coil Resistance Ratio

The resistances of the primary coil and secondary coil are given as 56 \(\Omega\) and 14 \(\Omega\) respectively. Thus, the resistance ratio \( R_{p} / R_{s} \) is \( \frac{56}{14} = 4 \). This indicates that the primary coil is four times longer than the secondary coil because the wire is the same type and has the same cross-sectional area.
03

Determine Length and Turns for Each Coil

Because the resistances are different due to the length, if the primary coil’s wire is longer by a factor of 4 (i.e., \( L_{p} = 4L_{s} \)), then since the cross-sectional area and diameter of their turns are the same, the number of turns \( N \) is directly proportional to the length \( L \) used for the coil. So, \( \frac{N_s}{N_p} = \frac{L_s}{L_p} = \frac{1}{4} \).
04

Calculate the Turns Ratio

Finally, calculate the turns ratio \( \frac{N_s}{N_p} \). Since \( L_{p} = 4L_{s} \), we have that \( N_{p} = 4N_{s} \) which simplifies the turns ratio to \( \frac{N_s}{N_p} = \frac{1}{4} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transformer Coil Resistance
In a transformer, the resistance of the coils plays a crucial role in determining its efficiency and performance. Resistance in electrical circuits is a measure of how much a conductor opposes the flow of electric current. For transformers, coils are essentially long lengths of wire wound into loops. Transformers typically have two coils: the primary and the secondary. The resistance of these coils depends on several factors, including:
  • Material of the wire: Copper is commonly used due to its low resistivity.
  • Length of the wire: Longer wires have higher resistance.
  • Cross-sectional area: Thinner wires have higher resistance for the same length and material.
In the given exercise, the resistance values — 56 Ω for the primary coil and 14 Ω for the secondary coil — indicate that the primary coil offers more resistance than the secondary, largely due to its longer length.
Copper Wire Resistance
Copper is the most common material used for winding coils in transformers because of its high electrical conductivity and optimum balance of cost and availability. Copper wire resistance increases with the length of the wire and decreases with the increase in its cross-sectional area. When two coils are made from the same type of copper wire with the same diameter, variations in their resistances arise primarily from differences in their lengths. Copper wire resistance is affected by:
  • The resistivity of copper, which remains constant under normal working temperatures.
  • Uniformity in cross-sectional area, since it remains the same for both coils in this problem.
  • Environmental factors like temperature, which can affect the resistance slightly, but under typical conditions, copper's resistivity is stable.
Thus, careful calculations that account for the length differences are necessary to understand each coil's resistance properly, as seen in this exercise.
Resistivity and Resistance in Transformers
The concepts of resistivity and resistance are fundamental in electrical engineering and play a significant part in transformer functionality. Resistivity is a material-specific property that quantifies how strongly a given material opposes the flow of electric current. It is denoted by the symbol \( \rho \) and is measured in ohm-meters (Ω·m).The formula to calculate resistance using resistivity is: \[R = \rho \frac{L}{A}\]where:
  • \( R \) is the resistance,
  • \( \rho \) is the resistivity,
  • \( L \) is the length of the wire,
  • \( A \) is the cross-sectional area.
Since transformers utilize coils of copper wire, the resistance of these coils is directly influenced by the copper's resistivity, ensuring that longer wires have more resistance, as shown in the primary coil of our example.
Turns Ratio Calculation in Electricity
The turns ratio in a transformer is vital because it determines the voltage and current transformation between the primary and secondary circuits. It is the ratio of the number of turns in the secondary coil to the number of turns in the primary coil.This can be calculated easily if you know the resistor ratio of the coils along with the type and cross-sectional area of wire used. From the exercise, where both coils are identical in material and diameter, understanding that the primary has four times the resistance of the secondary directly gives us the ratio of lengths of wire used for each coil.Given that length corresponds to turns, we calculate the turns ratio as:\[\frac{N_s}{N_p} = \frac{L_s}{L_p} = \frac{1}{4}\]This turns ratio shows that for every single loop of the copper wire in the secondary coil, there are four in the primary coil. This fundamentally affects the voltage and current levels transformed across the coils, abiding by the principle of energy conservation in electrical transformations.

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Most popular questions from this chapter

The battery charger for an MP3 player contains a step-down trans- former with a turns ratio of 1: 32, so that the voltage of 120 V available at a wall socket can be used to charge the battery pack or operate the player. What voltage does the secondary coil of the transformer provide?

A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius \(r=0.20 \mathrm{m}\) . The normal to the plane of the loop is parallel to a constant magnetic field \(\left(\phi=0^{\circ}\right)\) of magnitude 0.75 \(\mathrm{T}\) . What is the change \(\Delta \Phi\) in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

ssm A generator has a square coil consisting of 248 turns. The coil rotates at 79.1 \(\mathrm{rad} / \mathrm{s}\) in a \(0.170-\mathrm{T}\) magnetic field. The peak output of the generator is 75.0 \(\mathrm{V}\) . What is the length of one side of the coil?

A long, current-carrying solenoid with an air core has 1750 turns per meter of length and a radius of 0.0180 \(\mathrm{m}\) . A coil of 125 turns is wrapped tightly around the outside of the solenoid, so it has virtually the same radius as the solenoid. What is the mutual inductance of this system?

A generator uses a coil that has 100 turns and a \(0.50-\) T magnetic field. The frequency of this generator is 60.0 \(\mathrm{Hz}\) , and its emf has an rms value of 120 \(\mathrm{V}\) . Assuming that each turn of the coil is a square (an approximation), determine the length of the wire from which the coil is made.

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