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mmh The maximum strength of the earth's magnetic field is about \(6.9 \times 10^{-5} \mathrm{T}\) near the south magnetic pole. In principle, this field could be used with a rotating coil to generate \(60.0 . \mathrm{-Hz}\) ac electricity. What is the minimum number of turns (area per turn \(=0.022 \mathrm{m}^{2}\) ) that the coil must have to produce an rms voltage of 120 \(\mathrm{V}\) ?

Short Answer

Expert verified
The coil must have at least 4020 turns to produce 120 V rms.

Step by step solution

01

Understand the Given Data

The given data is as follows:- Maximum magnetic field strength, \(B = 6.9 \times 10^{-5} \text{ T}\)- Frequency of AC electricity, \(f = 60.0 \text{ Hz}\)- Area per turn of coil, \(A = 0.022 \text{ m}^2\)- Desired RMS voltage, \(V_{\text{rms}} = 120 \text{ V}\)
02

Identify the Required Formula

To find the minimum number of turns needed in the coil, use the formula for the RMS voltage produced by a rotating coil in a magnetic field:\[ V_{\text{rms}} = N \cdot A \cdot B \cdot 2 \pi f \cdot \frac{1}{\sqrt{2}} \]where:- \(N\) is the number of turns.- \(A\) is the area per turn.- \(B\) is the magnetic field strength.- \(f\) is the frequency of the AC electricity.
03

Rearrange the Formula to Solve for N

Rearrange the RMS voltage formula to solve for the number of turns \(N\):\[ N = \frac{V_{\text{rms}} \cdot \sqrt{2}}{A \cdot B \cdot 2 \pi f} \]
04

Substitute Values into the Formula

Substitute the known values into the formula:\[ N = \frac{120 \cdot \sqrt{2}}{0.022 \cdot 6.9 \times 10^{-5} \cdot 2 \pi \cdot 60} \]
05

Calculate the Number of Turns

Calculate the expression inside by approximating each component step by step. **Note** that \(\sqrt{2} \approx 1.414\) and make sure units are consistent.- \(2 \pi \approx 6.283\)- Compute the denominator and numerator separately before dividing.- Final calculation should give you:\[ N \approx 4020 \]
06

Round to Nearest Whole Number

Since the number of coil turns must be a whole number, round the calculated \(N\) to get the minimum number of turns needed, which is typically rounded up to the nearest whole number if not exact.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Strength
Magnetic field strength is a measure of how strong a magnetic field is at a given point. This is an important concept in electromagnetic induction because it affects how much voltage can be generated by a coil in that field.
In our exercise, the maximum strength of the Earth's magnetic field near the south magnetic pole is given as \(6.9 \times 10^{-5} \text{ T}\). The unit "T" stands for Tesla, which measures the intensity of a magnetic field.
This value represents the maximum potential the field can influence objects in its vicinity, such as the coil in our example. Understanding this concept is essential as this is what allows the coil to induce an electromotive force when rotated within the field.
  • The stronger the magnetic field, the greater the induced voltage.
  • Magnetic field strength varies depending on location and source.
Realizing the magnetic field's role helps in predicting and calculating the necessary coil characteristics for desired electrical outputs.
AC Electricity
AC, or alternating current electricity, is a type of electrical current that periodically reverses direction. Unlike direct current (DC), where the flow of electrons is constant in one direction, AC current changes direction in a sinusoidal manner.
In the context of the problem, AC frequency is given as \(60.0 \text{ Hz}\), which means the current changes direction 60 times per second. This frequency is typical for household electric supply in many parts of the world.
Understanding AC electricity is crucial for designing circuits that utilize electromagnetic induction to generate power.
  • AC electricity allows efficient transmission over long distances.
  • The formula for calculating RMS voltage accounts for this sinusoidal behavior, capturing a kind of average of the fluctuating voltages.
Recognizing the nature of AC helps in aligning coil turns and operations to match electrical production demands properly.
Coil Turns Calculation
Calculating the number of turns in a coil is crucial because it directly affects the generated voltage in an electromagnetic induction setup. Our exercise requires solving for coil turns necessary to achieve an RMS voltage of 120 V.
The formula used combines several factors: the area of the coil, the strength of the magnetic field, the frequency of the alternating current, and the RMS voltage desired.
The key formula is rearranged as: \[ N = \frac{V_{\text{rms}} \cdot \sqrt{2}}{A \cdot B \cdot 2 \pi f} \] Where all given values, such as the area (\(A = 0.022 \text{ m}^2\)), magnetic field strength \(B\), and frequency \(f\), are substituted to find \(N\).
  • Greater coil area typically means fewer turns are needed and vice versa.
  • More turns in a coil will increase the induced voltage, given the same magnetic and frequency conditions.
Understanding how to adjust coil designs accordingly is essential for meeting electrical generation needs.
RMS Voltage
RMS, or Root Mean Square voltage, is a key concept in AC electricity that represents the effective voltage value that accomplishes the same amount of work as a direct current (DC) of the same value.
The RMS value is crucial in assessing the usability of AC power systems, as it allows comparisons to DC systems and aids in efficient design and safety assessments. In the problem, the RMS voltage required is 120 V.
The RMS voltage formula in a rotating coil is: \[ V_{\text{rms}} = N \cdot A \cdot B \cdot 2 \pi f \cdot \frac{1}{\sqrt{2}} \] This formula accounts for the sinusoidal nature of AC and computes a practical value for voltage in usage terms.
  • RMS voltage simplifies the comparison between varying AC and constant DC currents.
  • The effective voltage, or RMS, reflects real-world power output better than simply using peak voltage levels.
Understanding RMS voltage ensures that the generated power safely meets usage requirements.

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Most popular questions from this chapter

ssm A generating station is producing \(1.2 \times 10^{6} \mathrm{W}\) of power that is to be sent to a small town located 7.0 \(\mathrm{km}\) away. Each of the two wires that comprise the transmission line has a resistance per kilometer of \(5.0 \times 10^{-2} \Omega / \mathrm{km}\) (a) Find the power used to heat the wires if the power is transmitted at 1200 \(\mathrm{V}\) . (b) A \(100 : 1\) step-up transformer is used to raise the voltage before the power is transmitted. How much power is now used to heat the wires?

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A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is \(45.0 \Omega .\) The area of each turn is \(4.70 \times 10^{-4} \mathrm{~m}^{2} .\) This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be \(8.87 \times 10^{-3} \mathrm{C}\). Find the magnitude of the magnetic field.

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