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An ionized helium atom has a mass of \(6.6 \times 10^{-27} \mathrm{kg}\) and a speed of \(4.4 \times 10^{5} \mathrm{m} / \mathrm{s}\) . It moves perpendicular to a \(0.75-\mathrm{T}\) magnetic field on a circular path that has a 0.012 -m radius. Determine whether the charge of the ionized atom is \(+e\) or \(+2 e .\)

Short Answer

Expert verified
The charge of the ionized atom is \(+2e\).

Step by step solution

01

Write Down Known Quantities

First, note down the known quantities from the problem:- Mass of helium atom, \( m = 6.6 \times 10^{-27} \; \text{kg} \)- Speed of helium atom, \( v = 4.4 \times 10^5 \; \text{m/s} \)- Magnetic field strength, \( B = 0.75 \; \text{T} \)- Radius of the path, \( r = 0.012 \; \text{m} \)
02

Apply the Centripetal Force Equation

The centripetal force required to keep the ion moving in a circle is provided by the magnetic force. Therefore, we equate the magnetic force to the centripetal force:\[F_c = F_B \m \cdot a_c = q \cdot v \cdot B\]where \( a_c = \frac{v^2}{r} \) is the centripetal acceleration.
03

Solve for Charge \( q \)

Substitute for the centripetal acceleration into the force equation:\[\frac{m \cdot v^2}{r} = q \cdot v \cdot B\]Now solve for \( q \):\[q = \frac{m \cdot v}{r \cdot B}\]Substitute the known values:\[q = \frac{(6.6 \times 10^{-27} \; \text{kg}) \cdot (4.4 \times 10^5 \; \text{m/s})}{(0.012 \; \text{m}) \cdot (0.75 \; \text{T})}\]
04

Calculate the Value of \( q \)

Calculate the expression:\[q = \frac{6.6 \times 10^{-27} \cdot 4.4 \times 10^5}{0.012 \times 0.75}\]\[q = \frac{2.904 \times 10^{-21}}{0.009} \approx 3.227 \times 10^{-19} \; \text{C}\]
05

Compare with Fundamental Charge

The fundamental charge \( e \) is approximately \( 1.6 \times 10^{-19} \; \text{C} \). Therefore, compare:- If \( q = e \), then \( q = 1.6 \times 10^{-19} \; \text{C} \)- If \( q = 2e \), then \( q = 3.2 \times 10^{-19} \; \text{C} \)Since our calculated value of \( 3.227 \times 10^{-19} \; \text{C} \) is closer to \( 3.2 \times 10^{-19} \; \text{C} \), we conclude that the charge is \( +2e \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
In physics, centripetal force is essential for understanding how objects move in a circular path. This force is directed towards the center of the circle around which the object is moving. It acts as the "pull" that keeps the object from flying off in a straight line, maintaining its circular motion.
Centripetal force can be calculated using the formula: \[ F_c = \frac{m \cdot v^2}{r} \]where:
  • \( F_c \) is the centripetal force,
  • \( m \) is the mass of the object,
  • \( v \) is the speed of the object,
  • \( r \) is the radius of the circle.

The force required for circular motion is supplied by a variety of sources. For example, gravitational forces, tension in strings, or, in our case, magnetic forces. In the problem of the helium ion, the magnetic force acts as the centripetal force that keeps the ion moving in its circular path.
Charge of Ions
Ions are atoms or molecules that possess an electric charge, either positive or negative, due to the loss or gain of electrons. The charge of an ion is an important property in fields such as chemistry and physics because it influences how ions interact in magnetic and electric fields.
For the helium ion, its charge is denoted as either single \(+e\) or doubly charged \(+2e\). Here, \( e \) represents the fundamental charge of an electron which is about \( 1.6 \times 10^{-19} \; \text{C}\).
To determine the charge of the helium ion in the given problem, the magnetic force acting on the ion is compared to the centripetal force. The calculation showed that the charge is closer to \(+2e\), indicating that the helium ion in this problem is doubly ionized.
Circular Motion
Circular motion refers to the movement of an object along the circumference of a circle. This type of motion can be uniform or non-uniform depending on the constancy of the speed of the object. Uniform circular motion happens when an object moves with a constant speed along a circular path.
In the context of the helium ion, the ion is undergoing uniform circular motion under the influence of a perpendicular magnetic field. This implies that the speed of the ion is constant while its direction is continuously changing, providing the necessary centripetal acceleration.
The radius, speed, and the magnitude of the centripetal force determine the nature of this motion, which in this problem, leads to a circular path with a given radius.
Helium Ion
A helium ion is an atom of helium that has lost one or more of its electrons, resulting in a positively charged particle. Helium, which is the second lightest and second most abundant element in the universe, typically forms ions by losing electrons.
In this specific exercise, we are dealing with a helium ion that has been ionized twice, meaning it lost two electrons, forming \(+2e\) charge.
Ionized helium, often referred to as alpha particles in certain contexts, is used in various scientific applications due to its unique properties such as stability and penetration ability.
Understanding the charge and movement of helium ions in magnetic and electric fields is important for applications like mass spectrometry and plasma physics.

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Most popular questions from this chapter

ssm A piece of copper wire has a resistance per unit length of \(5.90 \times 10^{-3} \Omega / \mathrm{m}\) . The wire is wound into a thin, flat coil of many turns that has a radius of 0.140 \(\mathrm{m}\) . The ends of the wire are connected to a \(12.0-\mathrm{V}\) battery. Find the magnetic field strength at the center of the coil.

A positively charged particle of mass \(7.2 \times 10^{-8} \mathrm{kg}\) is traveling due east with a speed of 85 \(\mathrm{m} / \mathrm{s}\) and enters a \(0.31-\mathrm{T}\) uniform magnetic field. The particle moves through one- quarter of a circle in a time of \(2.2 \times 10^{-3} \mathrm{s}\) , at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge.

Two infinitely long, straight wires are parallel and separated by a distance of one meter. They carry currents in the same direction. Wire 1 carries four times the current that wire 2 carries. On a line drawn perpendicular to both wires, locate the spot (relative to wire 1) where the net magnetic field is zero. Assume that wire 1 lies to the left of wire 2 and note that there are three regions to consider on this line: to the left of wire 1, between wire 1 and wire 2, and to the right of wire 2.

The two conducting rails in the drawing are tilted upward so they each make an angle of \(30.0^{\circ}\) with respect to the ground. The vertical magnetic field has a magnitude of 0.050 T. The \(0.20-\mathrm{kg}\) aluminum rod (length \(=1.6 \mathrm{m} )\) slides without friction down the rails at a constant velocity. How much current flows through the rod?

The ion source in a mass spectrometer produces both singly and doubly ionized species, \(\mathrm{X}^{+}\) and \(\mathrm{X}^{2+}\) . The difference in mass between these species is too small to be detected. Both species are accelerated through the same electric potential difference, and both experience the same magnetic ficld, which causes them to move on circular paths. The radius of the path for the species \(X^{+}\) is \(r_{1},\) while the radius for species \(X^{2+}\) is \(r_{2}\) . Find the ratio \(r_{1} / r_{2}\) of the radii.

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