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A 550-W space heater is designed for operation in Germany, where household electrical outlets supply 230 V (rms) service. What is the power output of the heater when plugged into a 120-V (rms) electrical outlet in a house in the United States? Ignore the effects of temperature on the heater鈥檚 resistance.

Short Answer

Expert verified
The heater's power output in a 120-V outlet is approximately 149.7 W.

Step by step solution

01

Understand the relationship between power and resistance

Power in an electrical circuit is given by the formula \( P = \frac{V^2}{R} \), where \( P \) is power, \( V \) is the voltage, and \( R \) is the resistance. The power a device uses depends on the voltage and its resistance.
02

Calculate the resistance of the heater

First, we need to find the resistance \( R \) of the heater while it's operating in Germany. Using the formula \( P = \frac{V^2}{R} \), and given \( P = 550 \) W and \( V = 230 \) V, we rearrange to solve for \( R \):\[ R = \frac{V^2}{P} = \frac{230^2}{550} \].Calculating this gives us:\[ R \approx 96.18 \text{ ohms} \].
03

Calculate the power output in a 120-V outlet

Now that we have the resistance \( R = 96.18 \) ohms, we can find the power output when the heater is plugged into a 120-V outlet using the formula \( P' = \frac{V'^2}{R} \), with \( V' = 120 \) V:\[ P' = \frac{120^2}{96.18} \].Calculating this gives:\[ P' \approx 149.7 \text{ W} \].
04

Interpret the result

The calculated power output of the heater is approximately 149.7 W when plugged into a 120-V outlet. This tells us that the heater performs with much less power and produces less heat compared to when used with its intended 230 V.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental principle in understanding electrical circuits. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points. This can be expressed mathematically as \( V = IR \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance of the conductor.
  • Voltage \( V \) is the electric potential difference.
  • Current \( I \) is the flow of electrical charge.
  • Resistance \( R \) is the opposition to the flow of current.

Ohm's Law helps us understand how changing the voltage or resistance affects the current.
In our exercise, understanding this relationship allows us to calculate the electrical resistance of the heater based on its power rating and operating voltage.
Electrical Resistance
Electrical resistance is an important property of materials that affects how they conduct electricity. It鈥檚 measured in ohms (\( \Omega \)) and dictates how much current will flow for a given voltage. In simpler terms, resistance is what limits the flow of electric current. High resistance means less current flows, whereas low resistance means more current flows for the same voltage.
Resistance is calculated using the formula \( R = \frac{V}{I} \). However, in our specific exercise, we use a rearranged version: \( R = \frac{V^2}{P} \), where \( P \) represents power.
To find the resistance of the heater in the exercise, we solve \( R = \frac{230^2}{550} \) which results in approximately 96.18 ohms. This calculated resistance tells us how much the heater restricts electric current at its rated power and voltage.
Voltage
Voltage can be thought of as the electrical potential difference or 'pressure' that pushes electric charges through a conductor. It is expressed in volts (V).
  • Voltage is essential for current flow, as it's the driving force that moves electrons through a circuit.
  • In household circuits, voltage can vary based on location, like 230 V in Germany and 120 V in the United States.

In our exercise, the heater was originally designed for a 230 V supply. This means that its power and efficiency are optimized at that voltage. When connected to a 120 V supply, like in the US, the lower voltage results in decreased performance, as seen in the reduced power output.
Power Formula
The power formula is crucial for understanding the performance of electrical devices. It connects power to voltage and resistance in an electrical circuit. The formula \( P = \frac{V^2}{R} \) is used to calculate power (P) when voltage (V) and resistance (R) are known.
  • Power \( P \) is measured in watts (W).
  • \( P \) indicates how much energy a device uses per unit of time.
  • Higher power typically means more energy consumption and heat production.

In our example, the heater's power decreases when connected to a lower voltage of 120 V in the US. We use the formula \( P' = \frac{120^2}{96.18} \) to calculate this reduced power, approximately 149.7 W. This calculation showcases how changes in voltage impact the power output of devices.

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Most popular questions from this chapter

A car battery has a rating of 220 ampere \cdothours (A \(\cdot \mathrm{h} ) .\) This rating is one indication of the total charge that the battery can provide to a circuit before failing. \(\quad\) (a) What is the total charge (in coulombs) that this battery can provide? \(\quad\) (b) Determine the maximum current that the battery can provide for 38 minutes.

The current in a series circuit is 15.0 A. When an additional \(8.00-\Omega\) resistor is inserted in series, the current drops to 12.0 \(\mathrm{A}\) . What is the resistance in the original circuit?

Multiple-Concept Example 9 discusses the physics principles used in this problem. Three resistors, \(2.0,4.0,\) and \(6.0 \Omega,\) are connected in series across a \(24-\mathrm{V}\) battery. Find the power delivered to each resistor.

The total current delivered to a number of devices connected in parallel is the sum of the individual currents in each device. Circuit breakers are resettable automatic switches that protect against a dangerously large total current by 鈥渙pening鈥 to stop the current at a specified safe value. A 1650-W toaster, a 1090-W iron, and a 1250-W microwave oven are turned on in a kitchen. As the drawing shows, they are all connected through a 20-A circuit breaker (which has negligible resistance) to an ac voltage of 120 V. (a) Find the equivalent resistance of the three devices. (b) Obtain the total current delivered by the source and determine whether the breaker will 鈥渙pen鈥 to prevent an accident.

The drawing shows two capacitors that are fully charged \(\left(C_{1}=2.00 \mu F, q_{1}=6.00 \mu C ;\right.\) \(C_{2}=8.00 \mu F, q_{2}=12.0 \mu C ) .\) The switch is closed, and charge flows until equilibrium is reestablished (i.e., until both capacitors have the same voltage across their plates). Find the resulting voltage across either capacitor.

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