Chapter 2: Problem 83
A golfer rides in a golf cart an average speed of 3.10 \(\mathrm{m} / \mathrm{s}\) for 28.0 s. She then gets out of the cart and starts walking at an average speed of 1.30 \(\mathrm{m} / \mathrm{s}\) . For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 1.80 \(\mathrm{m} / \mathrm{s} ?\)
Short Answer
Step by step solution
Understand the Problem
Calculate Distance Traveled in the Cart
Setup the Average Speed Equation
Solve for Walking Time
Verify the Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Speed Calculation
To calculate speed, the formula is straightforward:
- Speed = Distance / Time
Distance Formula
- Distance = Speed × Time
This formula is highly useful for breaking down problems into smaller, manageable parts, allowing you to understand each segment of a journey or movement. By calculating distances for each phase of a trip, you can effectively sum them up for total distance traveled, a necessary component when figuring out average speed over an entire journey.
Equations of Motion
The equation we use to find the total average speed (for ride and walk combined) is:
- Average Speed = Total Distance / Total Time
Rewriting the equation with known values, you get: \[ \frac{86.8 + 1.30t}{28.0 + t} = 1.80 \]Solving such equations usually involves restructuring them to isolate the unknown variable, which requires basic algebra to solve for \( t \).
Problem-Solving Steps
Here’s how the given problem was approached:
- Step 1: Identify what's being asked. In the problem, the question is: How long must the golfer walk?
- Step 2: Calculate what you already know. Here, we found the distance traveled by cart using the speed and time.
- Step 3: Incorporate known variables into a comprehensive equation for average speed.
- Step 4: Algebraically solve the equation for the desired variable (the walking time, \( t \)).
- Step 5: Double-check by plugging the solution back into the original context to confirm accuracy.