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Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. The initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose that the initial speed of the first arrow is 25.0 \(\mathrm{m} / \mathrm{s}\) sand the second arrow is fired 1.20 \(\mathrm{s}\) after the first. Determine the initial speed of the second arrow.

Short Answer

Expert verified
The initial speed of the second arrow is approximately 13.23 m/s.

Step by step solution

01

Understand the Problem

We have two arrows shot upwards at different times but reaching their maximum height at the same time. We know the initial speed of the first arrow, and our task is to find the initial speed of the second arrow.
02

Equations for Maximum Height

An object thrown upwards reaches its maximum height when its velocity becomes zero. The time to reach this point from the initial speed \(v_0\) is given by \(t_{max} = \frac{v_0}{g}\), where \(g = 9.8 \, \text{m/s}^2\).
03

Calculate Time for First Arrow

Use the formula to find the time at which the first arrow reaches its maximum height. With initial speed \(v_{1} = 25.0 \, \text{m/s}\), calculate \(\)\[ t_{1_{max}} = \frac{25.0 \, \text{m/s}}{9.8 \, \text{m/s}^2} \approx 2.55 \, \text{s} \]
04

Calculate Time for Second Arrow

Since the second arrow is shot 1.2 seconds after the first but reaches its maximum height simultaneously, the time for the second arrow to reach its maximum must be \((t_{1_{max}} - 1.2 \, \text{s})\). Thus, \(t_{2_{max}} = 2.55 \, \text{s} - 1.2 \, \text{s} = 1.35 \, \text{s}\).
05

Determine Initial Speed of Second Arrow

Using \(t_{2_{max}}\) for the second arrow, use the formula \( v_{0} = g \cdot t_{2_{max}} \). Substituting values gives \(\)\[ v_{2} = 9.8 \, \text{m/s}^2 \cdot 1.35 \, \text{s} \approx 13.23 \, \text{m/s} \]
06

Confirm Solution

Re-examine the calculation to confirm that the initial speed ensures both arrows reach their maximum height at the same time. Both arrows have been calculated correctly based on their separate trajectories.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Motion
In the realm of physics, vertical motion refers to the movement of objects in a straight line along the vertical axis. It's a crucial concept for understanding projectile motion, particularly when objects are moving under the influence of gravity alone. In this context, arrows shot vertically are impacted by gravity, pulling them downward at a constant rate of approximately 9.8 meters per second squared. This force is denoted as 'g' in calculations.
When an object is launched upward, it battles the force of gravity, causing its speed to decrease as it ascends. Eventually, it will reach its peak height – the point where its velocity is momentarily zero before it begins its descent back to the ground. With this understanding, one can see how the initial speed and time of launch significantly influence vertical motion. Analyzing such motion requires a solid grasp of kinematics equations.
Kinematics Equations
Kinematics equations are mathematical formulas that describe the motion of objects without considering the forces causing them. These equations are fundamental in solving problems related to vertical motion in physics. There are three key kinematic equations, each assisting in different scenarios involving velocity, time, and displacement. The primary equation used here tackles calculating the time it takes for an object to reach its maximum height.
When dealing with vertical motion, particularly with objects thrown upwards, the time to reach the maximum height can be determined using the formula:
  • \[ t_{max} = \frac{v_0}{g} \]
Here, \(v_0\) is the initial velocity, and \(g\) is the acceleration due to gravity. This equation represents how the starting speed impacts the time required to reach the peak height when an object moves upwards. Understanding these equations enables us to solve complex problems, like the one tackled in the original exercise.
Initial Speed Calculation
Calculating the initial speed of an object in motion is essential for predicting its future position or state. In the context of our problem, identifying the second arrow's initial speed ensures both arrows reach their peak heights simultaneously, despite their different launch times. This calculation hinges upon the concept that the remaining time for the second arrow must be calculated by considering the delay in launch.
The formula connecting initial speed to time elapsed and gravitational force is:
  • \[ v_0 = g \cdot t_{max} \]
Using this formula enables us to back-calculate the necessary initial speed when the time to reach the maximum height is known. As shown in the solution, substituting the known gravitational constant \(9.8 \, \text{m/s}^2\) and the calculated time \(1.35 \, \text{s}\) provides the initial speed \(13.23 \, \text{m/s}\) for the second arrow. Understanding how to manipulate these equations is crucial for finding unknown variables in vertical motion scenarios.

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Most popular questions from this chapter

A hot-air balloon is rising straight up at a constant speed of 7.0 \(\mathrm{m} / \mathrm{s}\) . When the balloon is 12.0 \(\mathrm{m}\) above the ground, a gun fires a pellet straight up from ground level with an initial speed of 30.0 \(\mathrm{m} / \mathrm{s}\) . Along the paths of the balloon and the pellet, there are two places where each of them has the same altitude at the same time. How far above ground are these places?

While standing on a bridge 15.0 \(\mathrm{m}\) above the ground, you drop a stone from rest. When the stone has fallen \(3.20 \mathrm{m},\) you throw a second stone straight down. What initial velocity must you give the second stone if they are both to reach the ground at the same instant? Take the downward direction to be the negative direction.

The leader of a bicycle race is traveling with a constant velocity of \(+11.10 \mathrm{m} / \mathrm{s}\) and is 10.0 \(\mathrm{m}\) ahead of the second-place cyclist. The second-place cyclist has a velocity of \(+9.50 \mathrm{m} / \mathrm{s}\) and an acceleration of \(+1.20 \mathrm{m} / \mathrm{s}^{2}\) . How much time elapses before he catches the leader?

A Boeing 747 Jumbo Jet has a length of 59.7 \(\mathrm{m}\) . The runway on which the plane lands intersects another runway. The width of the inter- section is 25.0 \(\mathrm{m}\) . The plane decelerates through the intersection at a rate of 5.70 \(\mathrm{m} / \mathrm{s}^{2}\) and clears it with a final speed of 45.0 \(\mathrm{m} / \mathrm{s}\) . How much time is needed for the plane to clear the intersection?

You step onto hot beach with your bare feet. A nerve impulse, generated in your foot, travels through your nervous system at an average speed of 110 \(\mathrm{m} / \mathrm{s}\) . How much time does it take for the impulse, which travels a distance of \(1.8 \mathrm{m},\) to reach your brain?

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