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The space shuttle travels at a speed of about \(7.6 \times 10^{3} \mathrm{m} / \mathrm{s}\) . The blink of an astronaut's eye lasts about 110 \(\mathrm{ms}\) . How many football fields (length \(=91.4 \mathrm{m} )\) does the shuttle cover in the blink of an eye?

Short Answer

Expert verified
The shuttle covers about 9.15 football fields in the blink of an eye.

Step by step solution

01

Understand the problem

We need to find out how many football fields (each 91.4 meters long) the space shuttle travels in the blink of an astronaut's eye, which takes 110 milliseconds. The shuttle's speed is given as \(7.6 \times 10^{3}\) meters per second.
02

Convert time to seconds

Convert 110 milliseconds into seconds by dividing by 1000, since there are 1000 milliseconds in a second. \[ 110 \text{ ms} = \frac{110}{1000} \text{ s} = 0.11 \text{ s} \]
03

Calculate distance traveled

Using the speed of the shuttle, determine the distance it covers in 0.11 seconds. Use the formula: \( \text{distance} = \text{speed} \times \text{time} \). Substitute the known values: \[ \text{distance} = 7.6 \times 10^{3} \text{ m/s} \times 0.11 \text{ s} = 836 \text{ meters} \]
04

Calculate the number of football fields

To find the number of football fields the shuttle travels, divide the distance by the length of one football field. Each field is 91.4 meters long: \[ \text{Number of football fields} = \frac{836}{91.4} \approx 9.15 \]
05

Interpret the result

The shuttle covers approximately 9.15 football fields in the blink of an astronaut's eye.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed and velocity calculations
When dealing with problems in physics, speed and velocity are fundamental concepts. Speed is a scalar quantity, which simply means it is the measure of how fast an object moves, regardless of its direction. It is defined as the distance covered per unit of time.
In mathematical terms, speed is calculated using the formula:
  • \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \)
Velocity, on the other hand, is a vector quantity. This means it doesn't only account for how fast something moves, but also in what direction. For this reason, velocity can have different calculations compared to speed when direction is involved. In problems like the one with the space shuttle, we're often more focused on speed since direction isn't always a factor.
As seen in our shuttle problem, the speed was given as \(7.6 \times 10^{3} \) meters per second. To find the distance travelled in a specific time frame, such as the blink of an eye, we multiply the speed by the duration of time. This allows us to solve for missing variables in different scenarios.
Unit conversion in physics
Unit conversion in physics is crucial for solving problems where quantities are given in different units. It's essential to have all measurements in the same unit system to perform calculations effectively. Usually, physics problems use SI (International System of Units), which ensures uniformity.
In the exercise, time is originally provided in milliseconds (ms), but our speed is given in meters per second (m/s). To align these for calculation, we must convert the time from milliseconds to seconds. This is done easily by dividing the milliseconds by 1000, as there are 1000 milliseconds in a second:
  • \( 110 \text{ ms} = \frac{110}{1000} \text{ s} = 0.11 \text{ s} \)
This simple conversion is a useful skill because incorrect units can lead to wrong interpretations or results. Always double-check to ensure you are converting correctly, particularly in exams or real-world applications where precision is key.
Distance and displacement concepts
In physics, understanding the difference between distance and displacement is key. While they might seem similar, these two concepts have distinctive meanings.
**Distance** refers to the total length of the path traveled by an object, irrespective of direction. It is always positive and scalar, meaning it has no direction associated with it.
On the other hand, **displacement** is a vector quantity that considers the change in position of an object. It has both magnitude and direction.
  • For instance, even if you walk in a complete circle returning to your starting point, your displacement is zero because there's no overall change in position.
In our problem, we calculated the **distance** the shuttle covers in a blink of an eye. We found it to be approximately 836 meters. Since direction was not specified or needed, we operated purely with distance. Knowing when to consider displacement over distance is vital for more complex problems that include directional movement.

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Most popular questions from this chapter

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 86.0 \(\mathrm{m} / \mathrm{s}^{2}\) for 1.70 seconds, at which point its fuel abruptly runs out. Air resistance has no effect on its flight. What maximum altitude (above the ground) will the rocket reach?

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