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Two capacitors have the same plate separation, but one has square plates and the other has circular plates. The square plates are a length \(L\) on each side, and the diameter of the circular plate is \(L .\) The capacitors have the same capacitance because they contain different dielectric materials. The dielectric constant of the material between the square plates has a value of \(\kappa_{\text { square }}=3.00 .\) What is the dielectric constant \(\kappa_{\text { circle of the material between the circular plates? }}\)

Short Answer

Expert verified
The dielectric constant \( \kappa_{\text{circle}} \) is approximately 3.82.

Step by step solution

01

Determine the Area of Each Capacitor's Plate

For the square capacitor, the area of one plate is given by \( A_{ ext{square}} = L^2 \). For the circular capacitor, the diameter is \( L \), so the radius \( r \) is \( \frac{L}{2} \). Therefore, the area of the circular plate is \( A_{ ext{circle}} = \pi r^2 = \pi \left(\frac{L}{2}\right)^2 = \frac{\pi L^2}{4} \).
02

Apply the Capacitance Formula

The capacitance of a parallel plate capacitor is given by \( C = \frac{\kappa \varepsilon_0 A}{d} \), where \( \varepsilon_0 \) is the permittivity of free space, \( A \) is the area of the plates, and \( d \) is the separation distance. Both capacitors have equal capacitance \( C \) and separation \( d \). So, we have: \( C = \frac{\kappa_{ ext{square}} \varepsilon_0 L^2}{d} = \frac{\kappa_{ ext{circle}} \varepsilon_0 \frac{\pi L^2}{4}}{d} \).
03

Set the Capacitance Equations Equal

To solve for the unknown dielectric constant \( \kappa_{\text{circle}} \), set the expressions for capacitance equal to each other: \( \frac{\kappa_{ ext{square}} L^2}{d} = \frac{\kappa_{ ext{circle}} \frac{\pi L^2}{4}}{d} \). Since both sides are multiplied by \( \varepsilon_0 \), it cancels out, and \( d \) also cancels out.
04

Solve for the Dielectric Constant \( \kappa_{\text{circle}} \)

We simplify by canceling out common terms and solving for \( \kappa_{\text{circle}} \): \( \kappa_{ ext{square}} L^2 = \kappa_{\text{circle}} \frac{\pi L^2}{4} \). Cancel \( L^2 \) and rearrange: \( \kappa_{ ext{circle}} = \frac{4 \kappa_{ ext{square}}}{\pi} \). Substitute \( \kappa_{ ext{square}} = 3.00 \) to find \( \kappa_{ ext{circle}} = \frac{4 \times 3.00}{\pi} \approx 3.82 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capacitance Formula
The capacitance formula is a fundamental concept in physics, especially when dealing with capacitors. Capacitance, denoted by \( C \), is a measure of a capacitor's ability to store charge. The formula used to calculate the capacitance of a parallel plate capacitor is:\[ C = \frac{\kappa \varepsilon_0 A}{d} \]where:
  • \( \kappa \) is the dielectric constant of the material between the plates
  • \( \varepsilon_0 \) is the permittivity of free space
  • \( A \) is the area of the plates
  • \( d \) is the separation distance between the plates
The capacitance formula shows that the ability of the capacitor to store charge is directly proportional to both the dielectric constant and the area of the plates. It is inversely proportional to the distance between the plates. This means if you increase the dielectric constant or plate area, the capacitance increases. Conversely, increase the distance, and capacitance decreases. Understanding this relationship helps when designing capacitors for specific electrical applications.
Parallel Plate Capacitors
A parallel plate capacitor is a simple yet crucial component in electric circuits. It comprises two conductive plates separated by a small distance, with a dielectric material between them. This setup allows the capacitor to store electric charge and energy.### Characteristics of Parallel Plate Capacitors
  • **Structure**: Two plates of conductive material, most often of the same size.
  • **Separation**: The plates are kept at a distance \( d \), which is usually much smaller than their length and width.
  • **Dielectric Material**: Used to increase the effectiveness of the capacitor by raising its capacitance. The dielectric constant \( \kappa \) of the material is crucial here.
A parallel plate capacitor's functionality depends heavily on the dielectric material and the distance between the plates. It is widely used in various electronic devices for applications such as filtering, tuning circuits, and energy storage. By manipulating the dielectric constant and separation distance, the capacitor's performance can be finely tuned to meet specific needs.
Permittivity of Free Space
Permittivity of free space, often represented as \( \varepsilon_0 \), is a fundamental physical constant that plays a key role in electromagnetism. It signifies the capability of a vacuum to permit electric field lines. The value of \( \varepsilon_0 \) is approximately \( 8.854 \times 10^{-12} \text{ F/m} \) (farads per meter).### Importance of \( \varepsilon_0 \)
  • **Role in Capacitance**: It is used in the formula for the capacitance of a parallel plate capacitor, directly affecting how much charge the capacitor can store for a given voltage.
  • **Dielectric Influence**: When a dielectric material fills the space between the plates, its dielectric constant \( \kappa \) alters the permittivity inside the capacitor, effectively increasing it to \( \varepsilon = \kappa \varepsilon_0 \).
Permittivity of free space is a cornerstone concept in electromagnetic theory, influencing how electric and magnetic fields interact. It is essential for understanding how capacitors function and how they are applied in electronic components. The interplay between \( \varepsilon_0 \) and material properties leads to various practical applications in electronics and electrical engineering.

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Most popular questions from this chapter

An electron and a proton, starting from rest, are accelerated through an electric potential difference of the same magnitude. In the process, the electron acquires a speed \(v_{\mathrm{e}},\) while the proton acquires a speed \(v_{\mathrm{p}} .\) Find the ratio \(v_{\mathrm{c}} / v_{\mathrm{p}}\) .

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