/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 ssm A tiny ball (mass \(=0.012 \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

ssm A tiny ball (mass \(=0.012 \mathrm{kg}\) ) carries a charge of \(-18 \mu \mathrm{C}\) . What clectric ficld (magnitude and dircction) is nceded to cause the ball to float above the ground?

Short Answer

Expert verified
E = 6533.33 N/C, directed downward.

Step by step solution

01

Analyze the Forces

To make the ball float, the electric force acting on it must balance the gravitational force. The gravitational force is calculated using the formula: \( F_g = mg \), where \( m = 0.012 \text{ kg} \) is the mass and \( g = 9.8 \text{ m/s}^2 \) is the acceleration due to gravity.
02

Calculate Gravitational Force

Calculate the gravitational force: \[F_g = 0.012 \text{ kg} \times 9.8 \text{ m/s}^2 = 0.1176 \text{ N}\]
03

Use Coulomb's Law for Electric Force

To find the electric field that balances this force, use the equation: \( F_e = qE \), where \( q = -18 \times 10^{-6} \text{ C} \) is the charge and \( E \) is the electric field. Set \( F_e \) equal to \( F_g \) for equilibrium.
04

Solve for the Electric Field

Set the magnitudes of the forces equal and solve for \( E \): \[qE = mg \ E = \frac{mg}{q} = \frac{0.1176 \text{ N}}{18 \times 10^{-6} \text{ C}}\] Calculate this to find \( E \): \[E = 6533.33 \text{ N/C}\]
05

Determine the Direction of the Electric Field

The electric field must exert an upward force to counteract gravity. Since the charge is negative, the electric field must be directed downward (opposite to the force direction for a negative charge) to create an upward force.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is the natural phenomenon by which all things with mass attract each other. This force is one of the fundamental forces of nature and is responsible for the attraction objects experience from the Earth. It is mathematically expressed as:
  • \( F_g = mg \)
where:
  • \( F_g \) is the gravitational force (in Newtons),
  • \( m \) is the mass of the object (in kilograms), and
  • \( g \) is the acceleration due to gravity, approximately equal to \( 9.8 \, \text{m/s}^2 \) near the Earth's surface.
For the tiny ball in this exercise, the gravitational force can be calculated as \( 0.1176 \, \text{N} \). This indicates the force with which the Earth pulls on the ball. Understanding gravitational force is crucial for solving problems related to objects in the Earth’s gravitational field, such as determining the conditions needed to make an object float or levitate.
Coulomb's Law
Coulomb's Law describes the force between two charged objects. It is a cornerstone of electrostatics and helps explain how electric forces operate. The force between two charges is directly proportional to the product of the magnitude of the charges and inversely proportional to the square of the distance between them. The formula for Coulomb’s law is:
  • \( F = k \frac{|q_1 q_2|}{r^2} \)
where:
  • \( F \) is the electric force,
  • \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),
  • \( q_1 \) and \( q_2 \) are the point charges, and
  • \( r \) is the distance between the charges.
In the context of this exercise, the electric field \( E \) causing the ball to float can be viewed as the influence of an electric force to counteract gravity. The electric force \( F_e \) is modeled as \( qE \), where \( q \) is the charge on the ball. Calculating \( E = 6533.33 \, \text{N/C} \) gives the necessary electric field to balance the gravitational force on the charged ball.
Equilibrium of Forces
Equilibrium occurs when all forces acting on an object are balanced, resulting in no net force and thus no acceleration. This means the object will remain at rest or move at constant velocity. In the case of our floating charged ball, equilibrium is achieved when the upwards electric force due to the electric field precisely offsets the downwards gravitational force.

For equilibrium in our specific scenario, the key equations used were:
  • Gravitational force: \( F_g = mg \)
  • Electric force: \( F_e = qE \)
Setting these two equations equal, \( mg = qE \), allows us to solve for the electric field \( E \) needed to make the ball hover. It's crucial to note that the direction of the electric field must be such that it provides an upward force. Since the charge is negative, the field must be directed downward to achieve this effect. This concept ensures that all acting forces are in perfect balance, allowing for the ball to float.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose you want to determine the electric field in a certainregion of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of 20.0 C and the instrument indicates that the electric force exerted on it is 40.0 N, due east. What are the magnitude and direction of the electric field? (b) What are the magnitude and direction of the electric field if the object has a charge of 10.0 C and the instrument indicates that the force is 20.0 N, due west?

ssm mmh Two tiny spheres have the same mass and carry charges of the same magnitude. The mass of each sphere is \(2.0 \times 10^{-6} \mathrm{kg}\) . The gravitational force that each sphere exerts on the other is balanced by the electric force. (a) What alyebraic signs can the charges have? (b) Determine the charge magnitude.

Two small objects, A and B, are fixed in place and separated by 3.00 cm in a vacuum. Object A has a charge of 2.00 C, and object B has a charge of 2.00 C. How many electrons must be removed from object A and put onto object B to make the electrostatic force that acts on each object an attractive force whose magnitude is 68.0 N?

A charge \(Q\) is located inside a rectangular box. The electric flux through each of the six surfaces of the box is: \(\Phi_{1}=+1500 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}\) \(\Phi_{2}=+2200 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}, \Phi_{3}=+4600 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}, \Phi_{4}=-1800 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}\) \(\Phi_{5}=-3500 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C},\) and \(\Phi_{6}=-5400 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C} .\) What is \(Q ?\)

Two identical small insulating balls are suspended by separate \(0.25-\mathrm{m}\) threads that are attached to a common point on the ceiling. Each ball has a mass of \(8.0 \times 10^{-4} \mathrm{kg}\) . Initially the balls are uncharged and hang straight down. They are then given identical positive charges and, as a result, spread apart with an angle of \(36^{\circ}\) betwcen the threads. Dctermine (a) the charge on cach ball and (b) the tension in the threads.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.