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You are riding your bicycle directly away from a stationary source of sound and hear a frequency that is 1.0% lower than the emitted frequency. The speed of sound is 343 m/s. What is your speed?

Short Answer

Expert verified
Your speed is 3.43 m/s.

Step by step solution

01

Understand Doppler Effect Concept

The Doppler effect explains the change in frequency of a wave in relation to an observer moving relative to the wave source. When you move away from the source, the frequency you hear is lower than the emitted frequency.
02

Define Parameters and Formula

Let \( f' \) be the observed frequency, \( f \) be the emitted frequency, \( v_s \) be the speed of sound (343 m/s), \( v_o \) be your speed as the observer. The formula for frequency observed due to the Doppler effect when moving away from the source is: \[ f' = \left( \frac{v_s - v_o}{v_s} \right) f \]
03

Relate Observed and Emitted Frequency

We are given that the observed frequency is 1.0% lower than the emitted frequency. This means \( f' = 0.99f \). Substitute this into the formula: \[ 0.99f = \left( \frac{343 - v_o}{343} \right) f \]
04

Simplify Equation

Cancel \( f \) from both sides of the equation since it is non-zero: \[ 0.99 = \frac{343 - v_o}{343} \]
05

Solve for Observer's Speed

Multiply both sides by 343 to solve for \( v_o \): \[ 0.99 \times 343 = 343 - v_o \] \[ 339.57 = 343 - v_o \] Subtract 339.57 from 343: \[ v_o = 343 - 339.57 = 3.43 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sound Frequency
Sound frequency refers to the number of sound wave vibrations that occur in a second. It is measured in hertz (Hz). Simply put, frequency determines the pitch of the sound: higher frequencies mean higher pitches and lower frequencies mean deeper sounds. In everyday life, this is what allows us to distinguish between different musical notes or vocal tones.

How does frequency affect what we hear when we move? Imagine you are drifting away from someone playing a flute. As you move, you might notice the tone or pitch seems to decrease slightly. This is due to changes in the frequency that you actually perceive. The source emits a steady frequency, but your movement alters how often those sound waves hit your ear, modifying the frequency you "hear."

This concept is crucial to understanding phenomena like the Doppler Effect, which explains how motion influences perceived sound frequencies.
Explaining the Speed of Sound
The speed of sound is the rate at which sound waves travel through a medium, such as air. It's typically around 343 m/s in dry air at 20°C (68°F). However, it can vary based on factors like temperature, humidity, and altitude.

Why does the speed of sound matter? Knowing this speed is essential for calculating changes in perceived frequency when an observer or the source is moving. In physics problems like the one in the original exercise, the speed of sound acts as a constant to solve for variables like the observer's speed.

Understanding the speed of sound helps us make sense of how sound waves travel and interact with the environment. It also provides a basis for further calculations and analyses, especially when dealing with sound waves and their impacts on observations.
Analyzing Observed Frequency Change
The change in observed frequency due to motion is a core aspect of the Doppler Effect. If you move away from a sound source, the frequency you hear decreases. In the original problem, the observed frequency was 1.0% lower than the emitted frequency.

This change is represented mathematically by the formula:
  • \[ f' = \left( \frac{v_s - v_o}{v_s} \right) f \], where \( f' \) is the observed frequency, \( v_s \) is the speed of sound, and \( v_o \) is the observer's speed.

By plugging in the given frequencies and the speed of sound, you solve for the observer's speed. This method allows you to determine how fast you are moving based on how much the frequency changes.

Real-life applications of observed frequency change include radar and sonar technologies, which use frequency changes to determine the speed and direction of objects.
Approaching Physics Problem-Solving
Physics problems often require a systematic approach. The original exercise demonstrates this nicely with a focus on the Doppler Effect.

Here's a handy guide to problem-solving in physics:
  • Understand the core concept or phenomenon, like the Doppler Effect.
  • Identify and define all parameters and variables involved in the problem.
  • Use the correct mathematical formula that relates these variables.
  • Simplify and arrange the equation, making it easier to solve for the unknowns.
  • Carefully solve the equation, checking each step for potential errors.

This exercise emphasizes the importance of clear, logical thinking and structured problem-solving, which are invaluable skills not only in physics but in everyday life as well.

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Most popular questions from this chapter

A recording engineer works in a soundproofed room that is 44.0 \(\mathrm{dB}\) quieter than the outside. If the sound intensity that leaks into the room is \(1.20 \times 10^{-10} \mathrm{W} / \mathrm{m}^{2},\) what is the intensity outside?

A rocket, starting from rest, travels straight up with an acceleration of 58.0 \(\mathrm{m} / \mathrm{s}^{2}\) . When the rocket is at a height of \(562 \mathrm{m},\) it produces sound that eventually reaches a ground-based monitoring station directly below. The sound is emitted uniformly in all directions. The monitoring station measures a sound intensity I. Later, the station measures an intensity \(\frac{1}{3} I\) There are no reflections. Assuming that the speed of sound is \(343 \mathrm{m} / \mathrm{s},\) find the time that has elapsed between the two measurements.

Sound is passing perpendicularly through an open window whose dimensions are 1.1 \(\mathrm{m} \times 0.75 \mathrm{m}\) . The sound intensity level is 95 \(\mathrm{dB}\) above the threshold of hearing. How much sound energy comes through the window in one hour?

At a distance of 3.8 \(\mathrm{m}\) from a siren, the sound intensity is \(3.6 \times 10^{-2} \mathrm{W} / \mathrm{m}^{2}\) . Assuming that the siren radiates sound uniformly in all directions, find the total power radiated.

A wave traveling along the \(x\) axis is described mathematically by the equation \(y=0.17 \sin (8.2 \pi t+0.54 \pi x),\) where \(y\) is the displacement (in meters), \(t\) is in seconds, and \(x\) is in meters. What is the speed of the wave?

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