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A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1250 Hz. The bird-watcher, however, hears a frequency of 1290 Hz. What is the speed of the bird, expressed as a percentage of the speed of sound?

Short Answer

Expert verified
The bird is flying at approximately 3.10% of the speed of sound.

Step by step solution

01

Understand the Problem

The problem involves the Doppler effect, which causes changes in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. Here, the frequency emitted by the bird is 1250 Hz, but the bird-watcher perceives it as 1290 Hz because the bird is moving toward him.
02

Recall the Doppler Effect Formula

The formula to find the observed frequency when the source is moving towards a stationary observer is: \[ f' = \frac{f}{1 - \frac{v_s}{v}} \] where \( f' \) is the observed frequency, \( f \) is the emitted frequency, \( v_s \) is the speed of the source (the bird), and \( v \) is the speed of sound.
03

Substitute Given Values

Substitute \( f' = 1290 \text{ Hz} \) and \( f = 1250 \text{ Hz} \) into the Doppler effect formula: \[ 1290 = \frac{1250}{1 - \frac{v_s}{v}} \] Here, we need to solve for the speed of the bird, \( v_s \).
04

Solve for Source Speed \( v_s \)

Rearrange the equation to solve for \( v_s \):1. Multiply both sides by \( 1 - \frac{v_s}{v} \): \[ 1290 \left(1 - \frac{v_s}{v}\right) = 1250 \]2. Expand: \[ 1290 - 1290 \frac{v_s}{v} = 1250 \]3. Solve for \( \frac{v_s}{v} \): \[ 1290 - 1250 = 1290 \frac{v_s}{v} \] \[ 40 = 1290 \frac{v_s}{v} \] \[ \frac{v_s}{v} = \frac{40}{1290} \]
05

Calculate Percentage Speed

To express the speed of the bird as a percentage of the speed of sound, multiply the result by 100:\[ \frac{v_s}{v} \times 100 = \frac{40}{1290} \times 100 \approx 3.10 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency
In the context of the Doppler effect, frequency refers to how often a wave occurs within a specific time frame. For sound waves, this is measured in Hertz (Hz), indicating the number of cycles per second.

When a bird emits sound waves at a particular frequency, this is called the emitted frequency. In our exercise, this is 1250 Hz. However, the frequency perceived by an observer, like our bird-watcher, is different due to the movement of the bird, which leads to the heard frequency of 1290 Hz.

This change between the emitted and perceived frequency is the essence of the Doppler effect, providing clues about the speed of the moving source relative to the observer. Understanding how frequency shifts can aid in calculating the speed of objects, similar to how we solve for the bird's speed.
Speed of Sound
The speed of sound is a critical component in understanding the Doppler effect. It is the speed at which sound waves travel through a medium, like air. Different materials can have different speeds of sound. In typical conditions at sea level and at a temperature of 20°C, the speed of sound in air is approximately 343 meters per second.

In calculations involving the Doppler effect, the speed of sound is denoted by the symbol \( v \). This value is essential as it helps determine how wave frequencies observed by a stationary observer change due to the motion of the source.
  • It acts as a baseline for determining how much faster or slower the source is moving compared to the speed of sound.
In our exercise, it is this standard speed of sound that we compare the bird's speed to, allowing us to express the bird's speed as a percentage of this rate.
Wave Source
The wave source is the origin point from which sound waves are emitted. In our exercise, the bird acts as the wave source, sending out sound waves as it flies. The emitted waves have a specific frequency, which is altered when the source moves, as is the case with the bird flying towards the observer.

Due to the motion of the wave source, the waves are compressed, increasing the frequency heard by the bird-watcher and illustrating the concept of the Doppler effect. This compression and change in frequency allow us to deduce the speed of the source itself.
  • Understanding the role of the wave source helps visualize how movement affects wave properties, which is pivotal for students soaking in foundational principles of motion and waves.
Stationary Observer
A stationary observer is someone who remains still while observing changes in wave frequency. In our example, the bird-watcher is stationary, which is crucial because the Doppler effect depends significantly on the relative movement between the source and the observer.

When the source moves towards the stationary observer, the frequency appears higher; conversely, if it moves away, the frequency would seem lower. This perceived frequency shift is precisely what the Doppler effect seeks to describe.
  • Such observations show how the concept of relative velocity functions, providing insights into real-world applications like radar speed detection and astronomy.
Understanding the role of a stationary observer helps clarify how relative movement affects perceived changes without requiring the observer to move.

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Most popular questions from this chapter

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