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A dish of lasagna is being heated in a microwave oven. The effective area of the lasagna that is exposed to the microwaves is 2.2 \(\times 10^{-2} \mathrm{m}^{2}\) . The mass of the lasagna is 0.35 kg, and its specific heat capacity is 3200 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{C}^{\circ}\) ). The temperature rises by 72 \(\mathrm{C}^{\circ}\) in 8.0 minutes. What is the intensity of the microwaves in the oven?

Short Answer

Expert verified
The intensity of the microwaves is approximately 7636.36 W/m².

Step by step solution

01

Calculate the Total Energy Gained

First, we need to calculate the total energy gained by the lasagna. This is determined using the formula \( Q = mc\Delta T \), where \( m \) is the mass of the lasagna, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature. Here, \( m = 0.35 \) kg, \( c = 3200 \) \( \mathrm{J} / \mathrm{kg} \cdot \mathrm{C}^{\circ} \), and \( \Delta T = 72 \) \( \mathrm{C}^{\circ} \). So, \( Q = 0.35 \times 3200 \times 72 = 80640 \) J.
02

Determine the Time in Seconds

The heating time is given as 8.0 minutes. We need to convert this time into seconds for our calculations. Since 1 minute is 60 seconds, 8.0 minutes is \( 8.0 \times 60 = 480 \) seconds.
03

Calculate the Power

Power is the rate at which energy is transferred and can be calculated using \( P = \frac{Q}{t} \), where \( Q \) is the total energy and \( t \) is the time in seconds. With \( Q = 80640 \) J and \( t = 480 \) seconds, the power is \( P = \frac{80640}{480} = 168 \) W.
04

Calculate the Intensity of the Microwaves

Intensity \( I \) is defined as the power per unit area, given by \( I = \frac{P}{A} \), where \( P \) is the power, and \( A \) is the effective area exposed to microwaves. With \( P = 168 \) W and \( A = 2.2 \times 10^{-2} \) \( \mathrm{m}^{2} \), the intensity is \( I = \frac{168}{2.2 \times 10^{-2}} = 7636.36 \) \( \mathrm{W} / \mathrm{m}^{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Transfer
When heating food, energy transfer is a fundamental concept. In this process, energy in the form of heat is transferred to the food, increasing its temperature. Let's take an example of heating a lasagna in a microwave:
  • The microwave oven emits microwaves, which interact with the water molecules in the food, causing them to vibrate.
  • This vibration generates heat within the food due to friction between the vibrating molecules, resulting in a temperature increase.
It's essential to understand that the amount of energy transferred depends on three main factors: the mass of the food, its specific heat capacity, and the change in temperature. This relationship is captured with the formula: \[ Q = mc\Delta T \]where \( Q \) is the energy transferred, \( m \) is the mass of the lasagna, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change. Understanding this equation helps in predicting how much energy is required to heat the food to a desired temperature.
Specific Heat Capacity
Specific heat capacity is a property of a material that indicates how much energy is needed to change its temperature. For our lasagna example, the specific heat capacity is given as 3200 J/kg·°C. This means:
  • 3200 Joules of energy are needed to raise the temperature of 1 kilogram of lasagna by 1°C.
  • Conversely, if the lasagna loses energy at this rate, its temperature will drop.
A higher specific heat capacity implies that more energy is required to change the temperature of the substance, which is why some materials take longer to heat up or cool down. Knowing the specific heat capacity allows us to calculate the total energy needed to reach a certain temperature change using the formula mentioned earlier. It is a crucial factor to consider in cooking and various industrial processes.
Intensity of Microwaves
The intensity of microwaves is defined as the power carried by electromagnetic waves per unit area. This concept is particularly important for understanding how effectively a microwave oven heats food. In our lasagna scenario:The formula to calculate intensity is: \[ I = \frac{P}{A} \] where \( I \) is intensity, \( P \) is the power, and \( A \) is the area exposed to microwaves. In the exercise:
  • The power was calculated to be 168 W.
  • The effective area is 2.2 × 10-2 m2.
  • The intensity is found to be 7636.36 W/m2, indicating how concentrated the microwave energy is over the lasagna's surface.
Understanding this intensity can aid in ensuring that microwaves are not too strong or too weak, affecting cooking speed and uniformity.
Power Calculation
Power is a measure of the rate at which energy is used or transferred. In the context of microwave heating, it determines how quickly the energy transferred causes the temperature to rise. To calculate the power used for heating the lasagna, the formula is:\[ P = \frac{Q}{t} \]where \( P \) is power, \( Q \) is the total energy transferred, and \( t \) is the time. In our example:
  • The energy transferred (\( Q \)) was 80640 J.
  • The heating time (\( t \)) was 480 seconds.
  • This results in a power calculation of 168 W.
This tells us that the microwave transfers energy at a rate of 168 Watts. Knowing the power can help in determining the efficiency of the microwave and in setting the correct heating levels for different foods, ensuring optimal cooking results.

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Most popular questions from this chapter

As a prank, someone drops a water-filled balloon out of a window. The balloon is released from rest at a height of 10.0 m above the ears of a man who is the target. Then, because of a guilty conscience, the prankster shouts a warning after the balloon is released. The warning will do no good, however, if shouted after the balloon reaches a certain point, even if the man could react infinitely quickly. Assuming that the air temperature is \(20^{\circ} \mathrm{C}\) and ignoring the effect of air resistance on the balloon, determine how far above the man's ears this point is.

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