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A Carnot engine has an efficiency of \(0.55 .\) If this engine were run backward as a heat pump, what would be the coefficient of performance?

Short Answer

Expert verified
The coefficient of performance is approximately 2.22.

Step by step solution

01

Understand Carnot Engine Efficiency

The efficiency of a Carnot engine is defined as \[\eta = 1 - \frac{T_C}{T_H},\]where \(\eta\) is the efficiency, \(T_C\) is the absolute temperature of the cold reservoir, and \(T_H\) is the absolute temperature of the hot reservoir. Given \(\eta = 0.55\), we know the efficiency of the Carnot engine already.
02

Relate Efficiency to Carnot Cycle

The relationship between Carnot engine efficiency and the temperatures of the reservoirs is given by:\[\eta = \frac{W}{Q_H} = 1 - \frac{T_C}{T_H}.\]Thus, the ratio \(\frac{T_C}{T_H}\) can be calculated as:\[\frac{T_C}{T_H} = 1 - \eta = 1 - 0.55 = 0.45.\]
03

Calculate Coefficient of Performance (COP) of Reverse Carnot Cycle

When the Carnot engine is run in reverse as a heat pump, the coefficient of performance (COP) becomes:\[COP = \frac{1}{\frac{T_C}{T_H} - 1} = \frac{1}{1 - \frac{T_C}{T_H}} = \frac{1}{1 - (1 - 0.55)} = \frac{1}{0.55}.\]
04

Simplify Calculation for COP

Calculate the numerical result for the COP:\[COP = \frac{1}{0.45} \approx 2.22.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is the study of energy, heat, and work, and how they interact within physical systems. It focuses on the principles governing energy transfer and conversion. The wide-ranging implications of thermodynamics are pivotal in understanding engines and refrigeration systems. In thermodynamics, an important concept is the conservation of energy, where energy cannot be created or destroyed, only transformed. This principle applies to all systems, including the Carnot engine, which is a model demonstrating how engines can ideally convert heat into work.
An essential aspect of thermodynamics is the understanding of the laws that guide these processes:
  • First Law: Also known as the conservation of energy principle, it states that the total energy of an isolated system remains constant.
  • Second Law: It introduces the concept of entropy, indicating that energy systems naturally progress towards a state of disorder, or increased entropy.
The Carnot cycle is a theoretical model that operates within these laws, serving as a benchmark for the efficiency of real engines.
Heat Pump
A heat pump is a device that transfers heat energy from one place to another, typically from a cooler area to a warmer one. This mechanism is contrary to the natural heat flow direction, which moves from hot to cold. Heat pumps are commonly used for heating purposes in homes and buildings.
Two main functions of heat pumps include:
  • Heating Mode: The heat pump extracts heat from the outside and releases it indoors.
  • Cooling Mode: The flow is reversed and the device extracts heat from indoors and releases it outside.
By reversing the actions of a heat engine, a heat pump effectively utilizes mechanical work to transfer heat from the cooler region to the warmer one. Relating to the Carnot engine, when run backward, it acts as a heat pump, utilizing its theoretical concepts for higher efficiency in heat transfer.
Heat pumps operate based on a cycle similar to the Carnot cycle, exhibiting the same principle of reversibility within a thermodynamic system.
Coefficient of Performance
The Coefficient of Performance (COP) is a key metric for the efficiency of heat pumps and refrigerators. It measures the effectiveness of a heat pump at transferring thermal energy relative to the input work it requires. For a system working as a heat pump, the COP is given by:
\[ COP = \frac{Q_H}{W}, \]where \( Q_H \) is the amount of heat delivered to the hot reservoir and \( W \) is the work input.
A higher COP indicates greater efficiency, meaning the device uses less energy to achieve the same heating or cooling effect. For Carnot heat pumps, which are idealized systems, the COP is maximally efficient given the defined temperatures of the hot and cold reservoirs.
The COP relationships can be directly calculated using the temperatures of these reservoirs, especially in a reversible cycle like the Carnot cycle, leading to expressions such as the one derived in the exercise where:
\[ COP = \frac{T_H}{T_H - T_C}. \]
Carnot Cycle
The Carnot cycle is a theoretical thermodynamic cycle that serves as a benchmark for the efficiency of engines and heat transfer systems. It is named after the French physicist Sadi Carnot, who introduced it as a model for understanding maximum efficiency possible in heat engines.
The Carnot cycle consists of four reversible stages:
  • Isothermal Expansion: The gas absorbs heat from the hot reservoir and expands at constant temperature.
  • Adiabatic Expansion: The gas continues to expand without exchanging heat, causing its temperature to fall.
  • Isothermal Compression: The gas is compressed at constant temperature, releasing heat to the cold reservoir.
  • Adiabatic Compression: The gas is further compressed with no heat exchange, raising its temperature back to the starting point.
This cycle is reversible and represents the maximum efficiency limit, meaning real engines or refrigerators cannot exceed its efficiency. In practical applications, the Carnot cycle assists in understanding how closely an engine can approach this idealized performance and serves as an essential guide for designing efficient thermodynamic systems.

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Most popular questions from this chapter

The temperatures indoors and outdoors are 299 and \(312 \mathrm{K},\) respectively. A Carnot air conditioner deposits \(6.12 \times 10^{5} \mathrm{J}\) of heat outdoors. How much heat is removed from the house?

When a .22 -caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This pressure causes the force that pushes the bullet through the barrel. The barrel has a length of 0.61 \(\mathrm{m}\) and an opening whose radius is \(2.8 \times 10^{-3} \mathrm{m} . \mathrm{A}\) bullet (mass \(=2.6 \times 10^{-3} \mathrm{kg}\) ) has a speed of 370 \(\mathrm{m} / \mathrm{s}\) after passing through this barrel. Ignore friction and determine the average pressure of the expanding gas.

An engine has an efficiency \(e_{1} .\) The engine takes input heat of magnitude \(\left|Q_{\mathrm{H}}\right|\) from a hot reservoir and delivers work of magnitude \(\left|W_{1}\right|\) The heat rejected by this engine is used as input heat for a second engine, which has an efficiency \(e_{2}\) and delivers work of magnitude \(\left|W_{2}\right| .\) The overall efficiency of this two- engine device is the magnitude of the total work delivered \(\left(\left|W_{1}\right|+\left|W_{2}\right|\right)\) divided by the magnitude \(\left|Q_{\mathrm{H}}\right|\) of the input heat. Find an expression for the overall efficiency \(e\) in terms of \(e_{1}\) and \(e_{2}\)

Five moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 370 to 290 \(\mathrm{K}\) . Determine \(\quad\) (a) the work done (including the algebraic sign) by the gas, and (b) the change in its internal energy.

A Carnot engine operates with a large hot reservoir and a much smaller cold reservoir. As a result, the temperature of the hot reservoir remains constant while the temperature of the cold reservoir slowly increases. This temperature change decreases the efficiency of the engine to 0.70 from \(0.75 .\) Find the ratio of the final temperature of the cold reservoir to its initial temperature.

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