/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 ssm The average value of the squ... [FREE SOLUTION] | 91Ó°ÊÓ

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ssm The average value of the squared speed \(\overline{v^{2}}\) does not equal the square of the average speed \((\overline{v})^{2}\) . To verify this fact, consider three particles with the following speeds: \(v_{1}=3.0 \mathrm{m} / \mathrm{s}, v_{2}=7.0 \mathrm{m} / \mathrm{s}\) and \(v_{3}=9.0 \quad \mathrm{m} / \mathrm{s}\) . Calculate \((\mathrm{a}) \quad \overline{v^{2}}=\frac{1}{3}\left(v_{1}^{2}+v_{2}^{2}+v_{3}^{2}\right) \quad\) and (b) \((\overline{v})^{2}=\left[\frac{1}{3}\left(v_{1}+v_{2}+v_{3}\right)\right]^{2}\)

Short Answer

Expert verified
\(\overline{v^{2}} = 46.33 \ m^2/s^2\) and \((\overline{v})^2 = 40.11 \ m^2/s^2\).

Step by step solution

01

Calculate Each Particle's Speed Squared

First, calculate the square of each given speed. For each particle, the formula is as follows:- For particle 1 with speed \(v_1 = 3.0 \ m/s\): \(v_1^2 = (3.0)^2 = 9.0\).- For particle 2 with speed \(v_2 = 7.0 \ m/s\): \(v_2^2 = (7.0)^2 = 49.0\).- For particle 3 with speed \(v_3 = 9.0 \ m/s\): \(v_3^2 = (9.0)^2 = 81.0\).
02

Calculate Average of Squared Speeds

Now, calculate the average of the squared speeds using the formula:\[\overline{v^{2}} = \frac{1}{3}(v_1^2 + v_2^2 + v_3^2) = \frac{1}{3}(9.0 + 49.0 + 81.0)\]This simplifies to:\[\overline{v^{2}} = \frac{1}{3}(139.0) = 46.33 \ m^2/s^2\]
03

Calculate Average Speed

Calculate the average of the speeds directly using the formula:\[\overline{v} = \frac{1}{3}(v_1 + v_2 + v_3) = \frac{1}{3}(3.0 + 7.0 + 9.0)\]This simplifies to:\[\overline{v} = \frac{1}{3}(19.0) = 6.33 \ m/s\]
04

Square the Average Speed

Finally, calculate the square of the average speed found in the previous step:\[(\overline{v})^2 = (6.33)^2 = 40.11 \ m^2/s^2\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed Squared Calculation
When dealing with physics problems, understanding how to calculate the speed squared for an object is crucial. The speed squared of an object signifies how an object's speed, when multiplied by itself, affects its motion.
First, consider a single particle with a given speed, denoted as \( v \). To find the speed squared, we use the equation:
  • \( v^2 = (v)^2 \)
For example, if a particle travels with a speed of 3.0 m/s, then its speed squared would be:
  • \( v^2 = (3.0)^2 = 9.0 \ m^2/s^2 \)
Doing this for each particle and summing these squared speeds leads us to calculate the average speed squared, which helps in understanding the kinetic energy and dynamics of particle systems. This step is fundamental in solving more complex problems that involve energy computations and other related physics laws.
Average Speed Calculation
To find the average speed of several moving particles, you need to sum up the individual speeds and then divide by the number of particles. This gives you a general sense of how fast the system of particles is moving as a group.
To calculate the average speed \( \overline{v} \), use the formula:
  • \( \overline{v} = \frac{1}{n}(v_1 + v_2 + v_3 + \, ... \, + v_n) \)
where \( v_1, v_2, v_3, \) etc., are the speeds of different particles and \( n \) is the total number of particles. For example, if we have particles with speeds 3.0 m/s, 7.0 m/s, and 9.0 m/s, the average speed is:
  • \( \overline{v} = \frac{1}{3}(3.0 + 7.0 + 9.0) = 6.33 \, m/s \)
This shows that the average movement across the entire system can help analyze general trends in particle motion, although it does not capture individual variances or the actual motion energy each particle carries.
Physics Problem Solving
Physics problem solving often brings together various calculations to give insight into a broader concept or principle. In this exercise, verifying the difference between the average of squared speeds and the square of average speeds is key.
This distinction is pivotal because it highlights that averaging is not a simple linear operation. Here, we use two formulas:
  • \( \overline{v^2} = \frac{1}{n}(v_1^2 + v_2^2 + v_3^2 + \, ... \, + v_n^2) \)
  • \( (\overline{v})^2 = \left(\frac{1}{n}(v_1 + v_2 + v_3 + \, ... \, + v_n)\right)^2 \)
The results from these formulas, in our specific example \( \overline{v^2} = 46.33 \, m^2/s^2 \) and \( (\overline{v})^2 = 40.11 \, m^2/s^2 \), illustrate the fact that the average of squared values is different from the square of average values.
These calculations are essential because they shed light on real-world phenomena, like kinetic energy or variance in motion, which depend greatly on the actual distribution of speeds among different particles in a system rather than just their average speed.

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Most popular questions from this chapter

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