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ssm A young male adult takes in about \(5.0 \times 10^{-4} \mathrm{m}^{3}\) of fresh air during a normal breath. Fresh air contains approximately 21\(\%\) oxygen. Assuming that the pressure in the lungs is \(1.0 \times 10^{5} \mathrm{Pa}\) and that air is an ideal gas at a temperature of \(310 \mathrm{K},\) find the number of oxygen molecules in a normal breath.

Short Answer

Expert verified
The number of oxygen molecules in a normal breath is approximately \(2.47 \times 10^{21}\).

Step by step solution

01

Determine the volume of oxygen inhaled

First, calculate the volume of oxygen in a single breath. Since 21% of the air is oxygen, multiply the total volume of air inhaled by 0.21: \[ V_{O_2} = 0.21 \times 5.0 \times 10^{-4} \, \text{m}^{3} = 1.05 \times 10^{-4} \, \text{m}^3. \]
02

Use the Ideal Gas Law

Apply the ideal gas law: \( PV = nRT \), to solve for the number of moles \( n \) of oxygen. Here, \( P = 1.0 \times 10^5 \, \text{Pa} \), \( V = 1.05 \times 10^{-4} \, \text{m}^3 \), \( R = 8.314 \, \text{J/mol K} \), and \( T = 310 \, \text{K} \):\[ n = \frac{PV}{RT} = \frac{(1.0 \times 10^5)(1.05 \times 10^{-4})}{8.314 \cdot 310}. \]
03

Calculate the moles of oxygen

Substitute the known values into the equation:\[ n = \frac{1.0 \times 10^5 \times 1.05 \times 10^{-4}}{8.314 \times 310} \approx 0.0041 \, \text{moles}. \]
04

Convert moles to molecules

Use Avogadro's number \( 6.022 \times 10^{23} \) molecules/mole to find the total number of oxygen molecules:\[ N = n \times 6.022 \times 10^{23} = 0.0041 \times 6.022 \times 10^{23} \approx 2.47 \times 10^{21} \, \text{molecules}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxygen Inhalation
Every time you take a breath, you're inhaling a mix of gases, where oxygen plays a crucial role. Inhaling oxygen is vital for our bodies because it enables cellular respiration, allowing our cells to produce energy. When you breathe in, approximately 21% of the air is composed of oxygen. This is why, in the exercise, only 21% of the total volume inhaled is considered for oxygen calculations.
The volume of air inhaled in the exercise is specified as 0.0005 cubic meters. To find out the volume of oxygen, you multiply this by 0.21, which gives 0.000105 cubic meters of oxygen per breath. This step is essential as it isolates the component of air we are interested in. Understanding how the proportion of oxygen in inhaled air affects the calculations helps in physics and chemistry exercises, as well as in real-world applications such as medical and environmental fields.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry, represented by the symbol \( N_A \), which equals \( 6.022 \times 10^{23} \) molecules per mole. It's named after the scientist Amedeo Avogadro, who first proposed the concept that equal volumes of gases, at the same temperature and pressure, contain the same number of particles.
This large number signifies how many atoms or molecules are present in one mole of a substance. In the context of the problem, once we determine the moles of oxygen using the Ideal Gas Law, Avogadro's number helps us convert this into a count of molecules. By multiplying the moles of oxygen (0.0041) by \( 6.022 \times 10^{23} \), we obtain the total number of oxygen molecules inhaled. This allows us to translate between the macroscopic amounts (like grams or liters) and the microscopic world (individual atoms or molecules), providing a bridge between chemistry and physics.
Mole Concept
The mole concept is a central unit in chemistry, serving as the bridge between the atomic world and the macroscopic quantities we can observe and measure. In simple terms, a mole is a specific quantity of substance that contains the same number of entities (atoms, molecules, etc.) as there are in 12 grams of carbon-12. This number of entities is Avogadro's number, \( 6.022 \times 10^{23} \).
The exercise involves determining the number of moles of oxygen, which is calculated using the Ideal Gas Law \( PV = nRT \). Here, \( P \) is pressure, \( V \) is volume, \( R \) is the gas constant, and \( T \) is temperature. Solving for \( n \) (moles of oxygen) involves substituting the known values to find the amount—not in individual molecules, but in moles. This approach simplifies dealing with enormous numbers typical in chemistry, allowing us to handle substances on a quantity basis that scales up from individual atoms to practical lab or industrial levels.

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Most popular questions from this chapter

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