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ssm It takes 0.16 \(\mathrm{g}\) of helium (He) to fill a balloon. How many grams of nitrogen \(\left(\mathrm{N}_{2}\right)\) would be required to fill the balloon to the same pressure, volume, and temperature?

Short Answer

Expert verified
1.12 g of nitrogen is needed to fill the balloon.

Step by step solution

01

Understand the Ideal Gas Law

The ideal gas law is given by the formula \( PV = nRT \), where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature. This equation states that for a given amount of gas and conditions, \( PV \) is directly proportional to \( nT \). For this problem, \( P \), \( V \), and \( T \) are constant for helium and nitrogen.
02

Calculate Moles of Helium

To find the number of moles of helium, \( n \), in 0.16 grams, use the molar mass of helium. Helium has a molar mass of 4.00 g/mol. The number of moles is calculated by \( n = \frac{m}{M} \), where \( m \) is mass and \( M \) is molar mass.\[ n_{He} = \frac{0.16 \text{ g}}{4.00 \text{ g/mol}} = 0.04 \text{ mol} \]
03

Apply Moles to Nitrogen

Using the ideal gas law and the conditions that are constant (pressure, volume, temperature), the moles of nitrogen needed will also be 0.04 mol, because the amount of gas that will fill the balloon under the same conditions depends only on the number of moles, not the type of gas.
04

Calculate Grams of Nitrogen

Calculate the grams of nitrogen required using the moles calculated in Step 3 and nitrogen's molar mass. The molar mass of nitrogen \((N_2)\) is 28.02 g/mol. Use the equation \( m = n \times M \).\[ m_{N_2} = 0.04 \text{ mol} \times 28.02 \text{ g/mol} = 1.12 \text{ g} \]
05

Conclusion

Thus, 1.12 grams of nitrogen \((N_2)\) is required to fill the balloon under the same conditions of pressure, volume, and temperature set for helium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Molar mass is a critical concept in chemistry, especially when dealing with gases like helium or nitrogen. It refers to the mass of one mole of a substance, usually expressed in grams per mole (g/mol). This quantity allows us to relate the mass of a substance to the amount of substance present in moles. For elements and simple molecules, you can find their molar mass from the periodic table or molecular weight calculations.
For instance, helium (He), a noble gas, has a molar mass of 4.00 g/mol. This means that one mole of helium weighs 4.00 grams. Similarly, nitrogen gas ( N_2 ) has a molar mass of 28.02 g/mol. Knowing these values helps us convert between mass and moles, which is crucial for applying the Ideal Gas Law in calculating conditions for gases under specified circumstances.
Understanding molar mass is essential for tasks such as determining how much a specific gas is needed to reach a desired state or condition, as seen in the exercise where we compare helium and nitrogen in a balloon.
Moles Calculation
Calculating the number of moles is a foundational step in many chemistry problems and exercises. Moles give us a measure of the amount of a substance in terms of its elementary entities, like atoms or molecules. To calculate moles, use the formula: \( n = \frac{m}{M} \) where \( n \) is the number of moles, \( m \) is the mass of the substance in grams, and \( M \) is the molar mass in grams per mole.
For example, in the exercise with helium, we found 0.16 grams of helium, and using its molar mass of 4.00 g/mol, we calculated the moles as: \[ n_{He} = \frac{0.16 \, \text{g}}{4.00 \, \text{g/mol}} = 0.04 \, \text{mol} \] This calculation was essential for determining how much nitrogen would be needed when filling the balloon to the same conditions. The same number of moles signifies the same amount of gas under constant conditions, making these calculations vital in such applications.
Gas Properties
Understanding the properties of gases is central to working with equations like the Ideal Gas Law and solving exercises involving different gases under similar conditions. The Ideal Gas Law, expressed as \( PV = nRT \), summarizes how gases behave. The pressure (\( P \)), volume (\( V \)), temperature (\( T \)), and number of moles (\( n \)) of a gas relate with the Ideal Gas Constant (\( R \)). They help predict how a gas will react under different scenarios if the other variables are held constant.
Gases have unique properties such as occupying the volume of their container and exerting pressure proportionate to their number of particles. This is why, in our exercise, both helium and nitrogen can fill the balloon to the same conditions if they are present in the same number of moles.
By understanding these properties, you can predict outcomes like the necessary mass of nitrogen to match helium's conditions in the balloon. The behavior of gases follows these rules strictly, making it possible to accurately manipulate variables like pressure, volume, and temperature for experiments and calculations.

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