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A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 240 Calories (1 Calorie 4186 J). What mass of perspiration would one have to lose to get rid of this energy? At body temperature, the latent heat of vaporization of water is \(2.42 \times 10^{6} {J} / {kg}\)

Short Answer

Expert verified
0.415 kg of perspiration must be lost.

Step by step solution

01

Identify the Given Information

We have been given the total energy contained in the yogurt, which is 240 Calories. We also know 1 Calorie is equivalent to 4186 Joules. The latent heat of vaporization of water is given as \(2.42 \times 10^6 \text{ J/kg}\).
02

Convert Calories to Joules

First, convert the energy from Calories to Joules using the conversion factor. \[\text{Energy in Joules} = 240 \times 4186 = 1,004,640 \text{ J}\]
03

Use the Latent Heat Formula

To determine the mass of perspiration required to release this energy, use the formula for latent heat, which is:\[Q = m \cdot L\]where \(Q\) is the energy in Joules, \(m\) is the mass of the perspiration in kg, and \(L\) is the latent heat of vaporization of water.
04

Solve for Mass

Rearrange the latent heat formula to solve for mass:\[m = \frac{Q}{L}\]Substitute the known values:\[m = \frac{1,004,640}{2.42 \times 10^6}\]Calculate the mass:\[m \approx 0.415 \text{ kg}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calories to Joules
When thinking about energy, "Calories" might be one of the first things that come to mind since they are commonly mentioned on food labels. However, in scientific terms, Calories are units of energy. To convert Calories to Joules is a straightforward process, as these two are different units that measure energy.
  • 1 Calorie equals 4186 Joules.
By converting Calories to Joules, we can better analyze energy changes in physics, chemistry, and biology.
Suppose you consumed something that contains 240 Calories. To find this energy in Joules, multiply the number of Calories by 4186.
For our exercise, 240 Calories becomes:\[240 \times 4186 = 1,004,640 \, \text{Joules}\] This conversion is crucial in many scientific calculations where energy needs to be in Joules.
Latent Heat of Vaporization
When a substance changes from a liquid to a gas, it requires energy to break the intermolecular bonds without changing temperature. This energy is known as the latent heat of vaporization.
The latent heat of vaporization of water, particularly at body temperature, is critically important because it determines how much energy is used when water evaporates.
  • The latent heat of vaporization for water is approximately \(2.42 \times 10^6 \text{ J/kg}\).
This means that to completely vaporize 1 kg of water, 2.42 million Joules of energy is needed.
Understanding this concept helps in analyzing processes like sweating, where the human body uses this vaporization property to regulate temperature.
Mass Calculation
To find the mass of perspiration that needs to be lost to release a certain amount of energy, such as the energy gained from eating, we use a simple calculation involving the formula for latent heat.
The formula for latent heat is expressed as:\[Q = m \cdot L\]where
  • \(Q\) is the energy in Joules,
  • \(m\) is the mass, and
  • \(L\) is the latent heat of vaporization.
Rearranging this formula allows us to solve for mass \(m\):\[m = \frac{Q}{L}\]In our exercise, with \(Q\) as 1,004,640 Joules and the latent heat of vaporization \(L\) as \(2.42 \times 10^6 \text{ J/kg}\), we substitute these values:\[m = \frac{1,004,640}{2.42 \times 10^6} \approx 0.415 \text{ kg}\]This calculation shows that losing 0.415 kg of perspiration is necessary to dissipate the energy consumed from eating 240 Calories.
Thermodynamics
Thermodynamics deals with the relationships between different forms of energy and how energy affects matter. It is an integral branch of physics that explains how energy transforms in various processes, like the conversion of food into energy that our bodies use.
In the context of our exercise, understanding thermodynamics allows us to grasp how the energy from the yogurt is metabolized and eventually dissipated by the body as heat through perspiration.
This helps explain:
  • How energy consumption (Calories) must equal energy expenditure (Joules of heat through perspiration) to maintain energy balance within our bodies.
  • The efficiency of bodily processes in converting and using energy.
Grasping the principles of thermodynamics is essential for fields like chemistry, engineering, and biology since it affects everything from fuel efficiency in engines to metabolic rates in living organisms.

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Most popular questions from this chapter

Suppose you are selling apple cider for two dollars a gallon when the temperature is \(4.0^{\circ} \mathrm{C}\). The coefficient of volume expansion of the cider is \(280 \times 10^{-6}\left(\mathrm{C}^{\circ}\right)^{-1} .\) How much more money (in pennies) would you make per gallon by refilling the container on a day when the temperature is \(26^{\circ} \mathrm{C}\) ? Ignore the expansion of the container.

mmh When resting, a person has a metabolic rate of about \(3.0 \times 10^{5}\) joules per hour. The person is submerged neck-deep into a tub containing \(1.2 \times 10^{3}\) kg of water at \(21.00^{\circ} {C}\) . If the heat from the person goes only into the water, find the water temperature after half an hour.

Occasionally, huge icebergs are found floating on the ocean's currents. Suppose one such iceberg is 120 \({km}\) long, 35 \({km}\) wide, and 230 \({m}\) thick. (a) How much heat would be required to melt this iceberg (assumed to be at \(0^{\circ} {C}\) ) into liquid water at \(0^{\circ} {C}\) ? The density of ice is 917 \({kg} / {m}^{3} .\) (b) The annual energy consumption by the United States is about \(1.1 \times 10^{20} {J}\) . If this energy were delivered to the iceberg every year, how many years would it take before the ice melted?

An insulated container is partly filled with oil. The lid of the container is removed, 0.125 kg of water heated to \(90.0^{\circ} {C}\) is poured in, and the lid is replaced. As the water and the oil reach equilibrium, the volume of the oil increases by \(1.20 \times 10^{-5} {m}^{3}\) . The density of the oil is 924 \({kg} / {m}^{3}\) , its specific heat capacity is \(1970{J} /({kg} \cdot {C}^{\circ}),\) and its coefficient of volume expansion is \(721 \times 10^{-6}({C}^{0})^{-1}.\) What is the temperature when the oil and the water reach equilibrium?

When it rains, water vapor in the air condenses into liquid water, and energy is released. (a) How much energy is released when 0.0254 m (one inch) of rain falls over an area of \(2.59 \times 10^{6} {m}^{2}\) (one square mile)? (b) If the average energy needed to heat one home for a year is \(1.50 \times 10^{11} {J}\) , how many homes could be heated for a year with the energy determined in part (a)?

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