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The vapor pressure of water at \(10^{\circ} {C}\) is 1300 \({Pa}\) . (a) What percentage of atmospheric pressure is this? Take atmospheric pressure to be \(1.013 \times 10^{5} {Pa}\) . (b) What percentage of the total air pressure at \(10^{\circ} {C}\) is due to water vapor when the relative humidity is 100\(\% ?\) (c) The vapor pressure of water at \(35^{\circ} {C}\) is 5500 Pa. What is the relative humidity at this temperature if the partial pressure of water in the air has not changed from what it was at \(10^{\circ} {C}\) when the relative humidity was 100\(\% ?\)

Short Answer

Expert verified
(a) 1.28% (b) 1.28% (c) 23.64%

Step by step solution

01

Calculate the Percentage of Atmospheric Pressure

To find the percentage of the vapor pressure of water at \(10^\circ C\) with respect to the atmospheric pressure, divide the vapor pressure of water at \(10^\circ C\) by the atmospheric pressure and multiply by 100:\[\text{Percentage} = \left(\frac{1300 \text{ Pa}}{1.013 \times 10^5 \text{ Pa}}\right) \times 100 = 1.28\%\]
02

Determine Percentage of Total Air Pressure Due to Water Vapor at 100% Humidity

At 100% relative humidity, the partial pressure of water vapor equals the vapor pressure of water. We already have this at \(10^\circ C\) as 1300 Pa. The total air pressure is the atmospheric pressure, given as \(1.013 \times 10^5\, \text{Pa}\). The percentage is thus:\[\text{Percentage} = \left(\frac{1300 \text{ Pa}}{1.013 \times 10^5 \text{ Pa}}\right) \times 100 = 1.28\%\]
03

Calculate the Relative Humidity at 35°C

At \(35^\circ C\), the vapor pressure of water is 5500 Pa. Since the partial pressure of water hasn't changed from 1300 Pa (as at \(10^\circ C\)), the relative humidity is:\[\text{Relative Humidity} = \left(\frac{1300 \text{ Pa}}{5500 \text{ Pa}}\right) \times 100 = 23.64\%\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Humidity
Relative humidity is a measurement of the amount of water vapor present in the air compared to the maximum amount of vapor the air can hold at a given temperature. It is expressed as a percentage.
To calculate relative humidity, you need to understand the concept of saturation. Saturation occurs when the air holds as much water vapor as it can at a specific temperature. This is known as the saturation vapor pressure.
When the relative humidity is 100%, it means the air is fully saturated with water vapor. If the air's temperature decreases or the water vapor increases further, condensation can occur. This is how dew or fog forms.
To calculate relative humidity, use the formula:
  • \( \text{Relative Humidity} = \left(\frac{\text{Actual Vapor Pressure}}{\text{Saturation Vapor Pressure}}\right) \times 100 \) %
In our problem, at \( 35^{\circ} \text{C} \), the saturation vapor pressure is \( 5500 \text{ Pa} \) and the actual vapor pressure remains at \( 1300 \text{ Pa} \), leading to a relative humidity of \( 23.64\% \).
Partial Pressure
Partial pressure refers to the pressure exerted by each individual gas in a mixture of gases. In any mixture, each gas contributes to the total pressure of the mixture based on its own presence or abundance in that mixture.
This concept is crucial in understanding how gases behave when mixed. For example, in our atmosphere, nitrogen, oxygen, water vapor, and other gases each have their own partial pressures.
The total pressure of the air is the sum of all the partial pressures of the gases within it. This is described by Dalton's Law of Partial Pressures, which states:
  • \( P_{\text{total}} = P_{1} + P_{2} + ... + P_{n} \)
For the water vapor, when relative humidity is 100%, its partial pressure equals the vapor pressure of water at that temperature. Therefore, at \( 10^{\circ} C \), the partial pressure of the water vapor is \( 1300 \text{ Pa} \).
Atmospheric Pressure
Atmospheric pressure is the total pressure exerted by the atmosphere at a given point. It is the force per unit area exerted by air on the surface due to gravity.
Measured in pascals (Pa), it varies based on altitude, temperature, and weather conditions, but at sea level, it is generally around \( 101325 \text{ Pa} \), or \( 1.013 \times 10^5 \text{ Pa} \).
This pressure affects weather patterns and influences how we measure other properties of gases, such as vapor pressure.
In our exercise, atmospheric pressure was considered to be \( 1.013 \times 10^5 \text{ Pa} \), providing a basis for comparing vapor pressure and calculating relative humidity.

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Most popular questions from this chapter

ssm Ideally, when a thermometer is used to measure the temperature of an object, the temperature of the object itself should not change. However, if a significant amount of heat flows from the object to the thermometer, the temperature will change. A thermometer has a mass of 31.0 g, a specific heat capacity of \(c=815 {J} /({kg} \cdot {C}^{\circ})\) \(c=815 {J} /({kg} \cdot {C}^{2})\) and a temperature of \(12.0^{\circ} {C}\) . It is immersed in 119 g of water, and the final temperature of the water and thermometer is \(41.5^{\circ} {C}\) . What was the temperature of the water before the insertion of the thermometer?

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