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You are sick, and your temperature is 312.0 kelvins. Convert this temperature to the Fahrenheit scale.

Short Answer

Expert verified
312.0 K is equal to 101.93 掳F.

Step by step solution

01

Understanding Kelvin to Celsius Conversion

First, we need to convert the temperature from Kelvin to Celsius. The formula to convert Kelvin to Celsius is:\[ C = K - 273.15 \]Given that the temperature is 312.0 K, substitute K with 312.0.\[ C = 312.0 - 273.15 \]
02

Calculating Celsius Temperature

Now perform the subtraction:\[ C = 312.0 - 273.15 = 38.85 \]Thus, the equivalent temperature in Celsius is 38.85 degrees.
03

Understanding Celsius to Fahrenheit Conversion

Next, convert the temperature from Celsius to Fahrenheit. Use the formula:\[ F = \left( C \times \frac{9}{5} \right) + 32 \]Now, substitute C with 38.85.
04

Calculating Fahrenheit Temperature

Perform the multiplication and addition:\[ F = \left( 38.85 \times \frac{9}{5} \right) + 32 \]\[ F = 69.93 + 32 \]\[ F = 101.93 \]The equivalent temperature in Fahrenheit is 101.93 degrees.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kelvin to Celsius
Temperature scales often require conversions, especially when dealing with scientific measurements and day-to-day weather reports. One important concept to understand is how to convert temperatures from the Kelvin scale to the Celsius scale. The Kelvin scale is an absolute temperature scale, starting at absolute zero where no thermal energy remains. Celsius, on the other hand, is a scale where the freezing point of water is 0 degrees and its boiling point is 100 degrees under standard atmospheric conditions. To convert a temperature from Kelvin to Celsius, you use the formula:
  • \[ C = K - 273.15 \]
Here, 'K' represents the temperature in Kelvin and 'C' is the temperature in Celsius. Simply subtract 273.15 from the Kelvin value to find the corresponding Celsius temperature. For example, a temperature of 312 Kelvin is equivalent to 38.85 degrees Celsius. This straightforward conversion is often a critical first step when dealing with temperature-related calculations.
Celsius to Fahrenheit
Once you have the temperature in Celsius, you might need to convert it to Fahrenheit, especially when communicating in countries that commonly use Fahrenheit for everyday temperatures. The Celsius to Fahrenheit conversion is slightly more complex, using this formula:
  • \[ F = \left( C \times \frac{9}{5} \right) + 32 \]
In this equation, 'C' stands for the Celsius temperature, and 'F' is the desired Fahrenheit temperature. First, multiply the Celsius temperature by \( \frac{9}{5} \), then add 32 to this result. For instance, a temperature of 38.85 掳C converts to 101.93 掳F. This formula captures the historical conversion ratio and accounts for differences in the scale's zero points. Remember that water freezes at 32 掳F and boils at 212 掳F, providing practical points of reference for understanding these temperatures.
Temperature Scales
Temperature scales are systems of measuring heat that are crucial for both everyday life and scientific study. There are several different scales, but the most commonly used ones include Kelvin (K), Celsius (掳C), and Fahrenheit (掳F). Each scale serves a different purpose, often defined by the zero point and scale increments.
  • **Kelvin**: Primarily used in scientific contexts, Kelvin's zero point is absolute zero, the theoretical absence of all thermal energy.
  • **Celsius**: Widely used around the world, Celsius defines 0 as the freezing point and 100 as the boiling point of water at sea level.
  • **Fahrenheit**: Mostly used in the United States, where the water freezing point is 32 掳F and boiling point is 212 掳F.
Understanding these scales helps in converting correctly between them, an essential skill in a range of academic and practical applications. Always keep in mind that while some conversions are straightforward, others, like from Fahrenheit to Celsius or vice versa, require using specific formulas.

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Most popular questions from this chapter

ssm Multiple-Concept Example 11 uses the same physics principles as those employed in this problem. A block of material has a mass of 130 \({kg}\) and a volume of \(4.6 \times 10^{-2} {m}^{3}\) . The material has a specific heat capacity and coefficient of volume expansion, respectively, of 750 \({J} / {kg} \cdot {C}^{9}\) and \(6.4 \times 10^{-5}({C}^{0})^{-1}\) . How much heat must be added to the block in order to increase its volume by \(1.2 \times 10^{-5} {m}^{3} ?\)

One January morning in 1943, a warm chinook wind rapidly raised the temperature in Spearfish, South Dakota, from below freezing to \(12.0^{\circ} {C}\) . As the chinook died away, the temperature fell to \(-20.0^{\circ} {C}\) in 27.0 minutes. Suppose that a 19-m aluminum flagpole were subjected to this temperature change. Find the average speed at which its height would decrease, assuming the flagpole responded instantaneously to the changing temperature.

ssm When the temperature of a coin is raised by 75 \({C}^{\circ}\) , the coin's diameter increases by \(2.3 \times 10^{-5} {m} .\) If the original diameter of the coin is \(1.8 \times 10^{-2} {m},\) find the coefficient of linear expansion.

Three portions of the same liquid are mixed in a container that prevents the exchange of heat with the environment. Portion A has a mass m and a temperature of \(94.0^{\circ} {C},\) portion \({B}\) also has a mass \(m\) but a temperature of \(78.0^{\circ} {C},\) and portion C has a mass \(m_{{C}}\) and a temperature of \(34.0^{\circ} {C}\) . What must be the mass of portion \({C}\) so that the final temperature \(T_{{f}}\) of the three-portion mixture is \(T_{t}=50.0^{\circ} {C} ?\) Express your answer in terms of \(m ;\) for example, \(m_{{C}}=2.20 {m} .\)

When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature \((37^{\circ} {C})\) by warming up the water in your stomach. Could drinking ice water, then, substitute for exercise as a way to 鈥渂urn calories?鈥 Suppose you expend 430 kilocalories during a brisk hour-long walk. How many liters of ice water \((0^{\circ} {C})\)) would you have to drink in order to use up 430 kilocalories of metabolic energy? For comparison, the stomach can hold about 1 liter.

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