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One way to administer an inoculation is with a 鈥済un鈥 that shoots the vaccine through a narrow opening. No needle is necessary, for the vaccine emerges with sufficient speed to pass directly into the tissue beneath the skin. The speed is high, because the vaccine \(\left(\rho=1100 \mathrm{kg} / \mathrm{m}^{3}\right)\) is held in a reservoir where a high pressure pushes it out. The pressure on the surface of the vaccine in one gun is 4.1 106 Pa above the atmospheric pressure outside the narrow opening. The dosage is small enough that the vaccine鈥檚 surface in the reservoir is nearly stationary during an inoculation. The vertical height between the vaccine鈥檚 surface in the reservoir and the opening can be ignored. Find the speed at which the vaccine emerges.

Short Answer

Expert verified
The vaccine emerges at approximately 86.37 m/s.

Step by step solution

01

Understand the basics of Bernoulli's Equation

Bernoulli's equation states that for an incompressible, non-viscous fluid, the sum of the pressure energy, kinetic energy, and potential energy per unit volume is constant along any streamline. The equation is given by: \[ P_1 + \frac{1}{2} \rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho g h_2 \]where:- \( P \) is the fluid pressure,- \( \rho \) is the fluid density,- \( v \) is the fluid velocity,- \( g \) is the acceleration due to gravity (which can be ignored as per the problem statement), and- \( h \) is the height above a reference point.
02

Simplify Bernoulli's Equation for this situation

Since the vertical height difference is negligible and we assume the reservoir's surface velocity \(v_1\) is nearly zero, we can simplify Bernoulli鈥檚 equation to:\[ P_1 = P_2 + \frac{1}{2} \rho v_2^2 \]Rearranging for \(v_2\), we have:\[ v_2 = \sqrt{\frac{2(P_1 - P_2)}{\rho}} \]
03

Identify the pressures

Here, \(P_1\) is the pressure in the reservoir, and \(P_2\) is atmospheric pressure. The problem states that the pressure difference \(P_1 - P_2 = 4.1 \times 10^6 \) Pa.
04

Calculate the exit speed

Plug in the given values, with \( \rho = 1100 \; \mathrm{kg/m}^3 \):\[ v_2 = \sqrt{\frac{2 \times 4.1 \times 10^6}{1100}} \]Calculate:\[ v_2 = \sqrt{\frac{8.2 \times 10^6}{1100}} \approx \sqrt{7454.545} \approx 86.37 \; \mathrm{m/s} \]
05

Present the final answer

The speed at which the vaccine emerges from the gun is approximately 86.37 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Dynamics
Fluid dynamics is a branch of physics that studies the motion of fluids鈥攍iquids and gases. One of the most significant principles in fluid dynamics is Bernoulli's Equation. It provides a way to understand how fluid flows behave under various conditions. In the context of vaccines delivered through a jet or gun, fluid dynamics helps us predict the speed and pressure changes of the fluid as it moves from a high-pressure reservoir to the atmosphere.
  • Flows in fluid dynamics can be steady or unsteady. Steady flow means that at any given point, the fluid's velocity doesn't change over time.
  • This field analyzes various flow paths called streamlines, which represent the trajectories that particles of a fluid would follow.
Comprehending fluid dynamics helps in designing effective delivery systems for vaccines that require high-speed injections without needles.
Pressure Energy
Pressure energy in a fluid is related to the force the fluid exerts per unit area due to its internal energy. In Bernoulli's Equation, pressure energy is one of the key factors to consider. It describes how fluid pressure can convert to kinetic energy as fluid moves through different points.
  • It's measured in pascals (P) and is a form of potential energy within the fluid.
  • In the context of the vaccine injection, a high pressure of 4.1 x 106 Pa is placed on the vaccine in the reservoir, which supplies the force needed for the vaccine to exit at high speed.
Understanding pressure energy is crucial for designing systems that maintain the right pressure level to ensure the fluid exits at the desired speed.
Kinetic Energy
Kinetic energy refers to the energy a fluid possesses due to its motion. In Bernoulli's equation, it is represented as the term \( \frac{1}{2} \rho v^2 \), where \( \rho \) is the density, and \( v \) is the velocity of the fluid. When a fluid accelerates or decelerates, its kinetic energy changes.
  • When liquid emerges from a nozzle, kinetic energy is maximized at the point of exit because the velocity is highest there.
  • For the vaccine gun, as the vaccine speeds up while passing through the narrow opening, the kinetic energy increases until the maximum exit velocity of 鈮 86.37 m/s is reached.
Kinetic energy is an essential part of understanding how fluids interact with their surroundings as their speed changes.
Potential Energy
Potential energy in fluids is generally related to their position in a gravitational field and is expressed as \( \rho g h \) in Bernoulli's equation. However, in situations like the vaccine delivery system mentioned, the potential energy due to height differences is negligible and often ignored.
  • Potential energy becomes significant when fluid moves between different vertical heights.
  • Since the difference in height is minor in the vaccine scenario, the focus is more on pressure and kinetic energies.
While potential energy is a vital concept in many fluid situations, in this case, it takes a backseat to the overwhelming effects of pressure and kinetic energy changes.

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Most popular questions from this chapter

A siphon tube is useful for removing liquid from a tank. The siphon tube is first filled with liquid, and then one end is inserted into the tank. Liquid then drains out the other end, as the drawing illustrates. (a) Using reasoning similar to that employed in obtaining Torricelli鈥檚 theorem (see Example 16), derive an expression for the speed \(v\) of the fluid emerging from the tube. This expression should give \(v\) in terms of the vertical height \(y\) and the acceleration due to gravity \(g\) . (Note that this speed does not depend on the depth \(d\) of the tube below the surface of the liquid.) (b) At what value of the vertical distance y will the siphon stop working? (c) Derive an expression for the absolute pressure at the highest point in the siphon (point \(A )\) in terms of the atmospheric pressure \(P_{0},\) the fluid density \(\rho, g,\) and the heights \(h\) and \(y\) (Note that the fluid speed at point \(A\) is the same as the speed of the fluid emerging from the tube, because the cross-sectional area of the tube is the same everywhere.)

A hydrometer is a device used to measure the density of a liquid. It is a cylindrical tube weighted at one end, so that it floats with the heavier end downward. The tube is contained inside a large 鈥渕edicine dropper,鈥 into which the liquid is drawn using the squeeze bulb (see the drawing). For use with your car, marks are put on the tube so that the level at which it floats indicates whether the liquid is battery acid (more dense) or antifreeze (less dense). The hydrometer has a weight of \(W=5.88 \times 10^{-2} \mathrm{N}\) and a cross-sectional area of tw \(A=7.85 \times 10^{-5} \mathrm{m}^{2} .\) How far from the bottom of the tube should the mark be put that denotes (a) battery acid \(\left(\rho=1280 \mathrm{kg} / \mathrm{m}^{3}\right)\) and (b) antifreeze \(\left(\rho=1073 \mathrm{kg} / \mathrm{m}^{3}\right) ?\)

blood transfusion is being set up in an emergency room for an accident victim. Blood has a density of 1060 \(\mathrm{kg} / \mathrm{m}^{3}\) and a viscosity of \(4.0 \times 10^{-3}\) Pa\cdots. The needle being used has a length of 3.0 \(\mathrm{cm}\) and an inner radius of 0.25 \(\mathrm{mm}\) . The doctor wishes to use a volume flow rate through the needle of \(4.5 \times 10^{-8} \mathrm{m}^{3} / \mathrm{s}\) . What is the distance \(h\) above the victim's arm where the level of the blood in the transfusion bottle should be located? As an approximation, assume that the level of the blood in the transfusion bottle and the point where the needle enters the vein in the arm have the same pressure of one atmosphere. ( In reality, the pressure in the vein is slightly above atmospheric pressure.)

A log splitter uses a pump with hydraulic oil to push a piston, which is attached to a chisel. The pump can generate a pressure of \(2.0 \times 10^{7}\) Pa in the hydraulic oil, and the piston has a radius of 0.050 \(\mathrm{m}\) . In a stroke lasting 25 \(\mathrm{s}\) s, the piston moves 0.60 \(\mathrm{m} .\) What is the power needed to operate the log splitter's pump?

The Mariana trench is located in the floor of the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of seawater is 1025 \(\mathrm{kg} / \mathrm{m}^{3} .\) (a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius \(=0.10 \mathrm{m} ) ? \quad\) (b) For comparison, determine the weight of a jetliner whose mass is \(1.2 \times 10^{5} \mathrm{kg}\) .

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