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Refer to Interactive Solution \(\underline{8.49}\) at in preparation for this problem. A car is traveling with a speed of \(20.0 \mathrm{~m} / \mathrm{s}\) along a straight horizontal road. The wheels have a radius of \(0.300 \mathrm{~m} .\) If the car speeds up with a linear acceleration of \(1.50 \mathrm{~m} / \mathrm{s}^{2}\) for \(8.00 \mathrm{~s},\) find the angular displacement of each wheel during this period.

Short Answer

Expert verified
The angular displacement of each wheel is 693.33 radians.

Step by step solution

01

Understanding the Relationship

To find the angular displacement, we need to understand the relationship between linear and angular motion. The distance traveled by the car linearly can be converted into the angular displacement of the wheels. The formula connecting linear distance \( s \) to angular displacement \( \theta \) is \( \theta = \frac{s}{r} \), where \( r \) is the radius of the wheel.
02

Calculate Linear Distance

We need to calculate the distance the car travels while accelerating. The formula for distance \( s \) when starting from an initial speed \( v_0 \) with a constant acceleration \( a \) over time \( t \) is: \[ s = v_0 t + \frac{1}{2} a t^2 \]Substitute \( v_0 = 20.0 \, \text{m/s}, \, a = 1.50 \, \text{m/s}^2, \, t = 8.00 \, \text{s} \) into the equation:\[ s = 20.0 \, \times 8.00 + \frac{1}{2} \times 1.50 \times (8.00)^2 \]\[ s = 160 + 0.75 \times 64 \]\[ s = 160 + 48 \]\[ s = 208 \, \text{m} \]
03

Calculate Angular Displacement

Use the linear distance \( s = 208 \, \text{m} \) and the wheel radius \( r = 0.300 \, \text{m} \) to find the angular displacement \( \theta \):\[ \theta = \frac{s}{r} \]\[ \theta = \frac{208}{0.300} \]\[ \theta = 693.33 \, \text{rad} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear and Angular Motion
Linear and angular motion are closely related but refer to different types of movement. Linear motion is the movement along a straight line, characterized by parameters like speed and acceleration. Angular motion, on the other hand, involves rotation around a fixed point or axis. Think of the wheels of a car—they rotate while the car itself moves linearly on the road.
  • Linear motion can be measured in terms of distance and linear speed.
  • Angular motion is all about angles, and we measure it in radians according to how much a wheel spins.

The relationship between these two is crucial. You can convert linear measurements to angular by considering the radius of the circular path. The formula \( \theta = \frac{s}{r} \) connects linear distance \( s \) to angular displacement \( \theta \), with \( r \) being the radius of the wheel. So, the linear distance a car covers can tell us how much each wheel has turned.
Kinematics
Kinematics deals with the motion of objects without considering the forces causing them. It provides us with tools to predict the future position and velocity of moving objects, given initial conditions and accelerations. In the context of the car problem:
  • We start with an initial speed of \( 20.0 \text{ m/s} \).
  • The car accelerates at \( 1.50 \text{ m/s}^2 \) for \( 8.00 \text{ s} \).

To find out how far the car travels, we use the kinematic equation: \[ s = v_0 t + \frac{1}{2} a t^2 \] Here, \( v_0 \) is the initial velocity, \( a \) is the acceleration, and \( t \) is time. This formula allows us to find the linear distance \( s \) covered during this acceleration period, providing a groundwork for understanding the wheel's rotation.
Rotational Motion
In rotational motion, objects rotate around an axis. Each point in the object travels in a circle or a part of a circle. The angular displacement measures how far an object has rotated, and it's often expressed in radians.
  • Angular displacement is the angle through which a point or line has been rotated in a specified sense about a specified axis.
  • It's helpful for describing the motion of wheels, gears, and rotating machinery.

For the car wheel, we calculated the angular displacement using the formula \( \theta = \frac{s}{r} \). With a linear travel distance \( s \) of \( 208 \text{ m} \) and the wheel's radius \( r \) as \( 0.300 \text{ m} \), we find \( \theta \) to be \( 693.33 \text{ rad} \). This figure tells us that each wheel has rotated 693.33 radians as the car accelerated over the given period. Understanding this concept is key to linking linear and angular aspects of motion seamlessly.

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Most popular questions from this chapter

An auto race is held on a circular track. A car completes one lap in a time of \(18.9 \mathrm{~s},\) with an average tangential speed of \(42.6 \mathrm{~m} / \mathrm{s}\). Find (a) the average angular speed and (b) the radius of the track.

An electric fan is running on HIGH. After the LOW button is pressed, the angular speed of the fan decreases to \(83.8 \mathrm{rad} / \mathrm{s}\) in \(1.75 \mathrm{~s}\). The deceleration is \(42.0 \mathrm{rad} / \mathrm{s}^{2}\). Determine the initial angular speed of the fan.

A basketball player is balancing a spinning basketball on the tip of his finger. The angular velocity of the ball slows down from 18.5 to \(14.1 \mathrm{rad} / \mathrm{s} .\) During the slow-down, the angular displacement is 85.1 rad. Determine the time it takes for the ball to slow down.

A person lowers a bucket into a well by turning the hand crank, as the drawing illustrates. The crank handle moves with a constant tangential speed of \(1.20\mathrm{~m} / \mathrm{s}\) on its circular path. Find the linear speed with which the bucket moves down the well.

A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The angular speed of the child has a constant value of \(0.250 \mathrm{rad} / \mathrm{s}\). At the instant the child spots the horse, one-quarter of a turn away, the merry-go-round begins to move (in the direction the child is running) with a constant angular acceleration of \(0.0100 \mathrm{rad} / \mathrm{s}^{2}\). What is the shortest time it takes for the child to catch up with the horse?

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