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Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at \(9.1 \mathrm{rad} / \mathrm{s}\). The wheel has a radius of \(0.45 \mathrm{~m}\). If you ride the bike for 35 min, how far would you have gone if the bike could move?

Short Answer

Expert verified
You would have traveled 8599.5 meters.

Step by step solution

01

Convert Time to Seconds

First, convert the time from minutes to seconds to facilitate calculations. Since there are 60 seconds in a minute, multiply the number of minutes by 60: \[ 35 \text{ min} \times 60 \frac{\text{s}}{\text{min}} = 2100 \text{ s} \]
02

Calculate Angular Distance

Next, determine the total angular distance (in radians) the wheel would rotate over the given time period. Angular distance is given by the formula: \[ \text{Angular distance} = \text{Angular velocity} \times \text{Time} \] Plug in the values: \[ 9.1 \ \mathrm{rad/s} \times 2100 \ \mathrm{s} = 19110 \ \mathrm{rad} \]
03

Find Linear Distance

Translate the angular distance to linear distance traveled along the circumference of the wheel. The linear distance is calculated using the relation: \[ \text{Distance} = \text{Angular Distance} \times \text{Radius} \] Substitute the known values: \[ 19110 \ \mathrm{rad} \times 0.45 \mathrm{m} = 8599.5 \mathrm{m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how fast an object rotates around a circular path. When you pedal on a stationary exercise bike, the wheel spins at a certain speed, which is measured in radians per second (rad/s). In the given exercise, the angular velocity is 9.1 rad/s. This means the wheel completes 9.1 radians of rotation every second.

A radian is a unit of angular measure. One complete revolution around a circle corresponds to an angular distance of about 6.28 radians (which equals 2Ï€ radians). Angular velocity helps us understand how rapidly something is spinning, and is crucial when calculating the angular distance covered in a given period.

To get a clear picture, imagine placing a dot on the wheel. As you pedal, the dot continuously rotates around the wheel's center. Angular velocity tells us how quickly this dot is moving around the wheel. When given the angular velocity and time, we can calculate the total angular distance.
Angular Distance
Angular distance is the total rotation in radians that an object makes over a particular time period. In the exercise, we calculate angular distance by multiplying the angular velocity by time:
  • Angular velocity: 9.1 rad/s
  • Time: 2100 seconds (after converting from 35 minutes)
Using the formula:\[ \text{Angular Distance} = \text{Angular Velocity} \times \text{Time} \]we find an angular distance of 19110 radians. This tells us how far the wheel turns within the given 35-minute timeframe.

Understanding angular distance is key to determining how much of a circular path has been traveled. It connects directly to linear distance, which represents the actual path length traveled by a point on the outer edge of the wheel. When you know the angular distance and the wheel's radius, you can calculate how far you would have traveled if the bike could move.
Linear Distance
Linear distance bridges the gap between circular motion and straight-line motion. It describes the actual path traveled by a point if you "unrolled" the wheel into a straight line. For our exercise bike scenario, the linear distance is calculated using the angular distance and the radius of the wheel.

The formula used is:\[ \text{Linear Distance} = \text{Angular Distance} \times \text{Radius} \]Substituting in the values from our exercise:
  • Angular Distance: 19110 radians
  • Radius of the wheel: 0.45 m
we get a linear distance of 8599.5 meters.

This means that if the exercise bike were moving, it would have traveled nearly 8.6 kilometers in a straight line. Understanding linear distance can be particularly useful when trying to relate circular movement, like that of a wheel, to linear concepts, such as miles or kilometers traveled on a map.

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Most popular questions from this chapter

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of \(47 \mathrm{rev} / \mathrm{s},\) and its tip has a tangential speed of \(54 \mathrm{~m} / \mathrm{s}\). What is the length of the rotating string?

Does the tip of a rotating fan blade have a tangential acceleration when the blade is rotating (a) at a constant angular velocity and (b) at a constant angular acceleration? Provide reasons for your answers. Problem A fan blade is rotating with a constant angular acceleration of \(+12.0 \mathrm{rad} / \mathrm{s}^{2}\). At what point on the blade, measured from the axis of rotation, does the magnitude of the tangential acceleration equal that of the acceleration due to gravity?

An auto race is held on a circular track. A car completes one lap in a time of \(18.9 \mathrm{~s},\) with an average tangential speed of \(42.6 \mathrm{~m} / \mathrm{s}\). Find (a) the average angular speed and (b) the radius of the track.

ssm The drawing shows a device that can be used to measure the speed of a bullet. The device consists of two rotating disks, separated by a distance of \(d=0.850 \mathrm{~m}\), and rotating with an angular speed of \(95.0 \mathrm{rad} / \mathrm{s}\). The bullet first passes through the left disk and then through the right disk. It is found that the angular displacement between the two bullet holes is \(\theta=0.240 \mathrm{rad}\). From these data, determine the speed of the bullet.

(a) In general, is the direction of an object's average angular velocity \(\bar{\omega}\) the same as its initial angle \(\theta_{0}\), its final angle \(\theta\), or the difference \(\theta-\theta_{0}\) between its final and initial angles? (b) The table that follows lists four pairs of initial and final angles of a wheel on a moving car. Decide which pairs give a positive average angular velocity and which give a negative average angular velocity. Provide reasons for your answers. $$ \begin{array}{|c|c|c|} \hline & \text { Initial angle } \theta-\theta_{0} & \text { Final angle } \theta \\ \hline \text { (a) } & 0.45 \mathrm{rad} & 0.75 \mathrm{rad} \\ \hline \text { (b) } & 0.94 \mathrm{rad} & 0.54 \mathrm{rad} \\ \hline \text { (c) } & 5.4 \mathrm{rad} & 4.2 \mathrm{rad} \\ \hline \text { (d) } & 3.0 \mathrm{rad} & 3.8 \mathrm{rad} \\ \hline \end{array} $$ Problem The elapsed time for each pair of angles is \(2.0 \mathrm{~s}\). Review the concept of average angular velocity in Section 8.2 and then determine the average angular velocity (magnitude and direction) for each of the four pairs of angles in the table. Check to see that the directions (positive or negative) of the angular velocities agree with the directions found in the Concept Question.

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