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After \(10.0 \mathrm{~s},\) a spinning roulette wheel at a casino has slowed down to an angular velocity of \(+1.88 \mathrm{rad} / \mathrm{s}\). During this time, the wheel has an angular acceleration of -5.04 \(\mathrm{rad} / \mathrm{s}^{2}\). Determine the angular displacement of the wheel.

Short Answer

Expert verified
The angular displacement of the wheel is 270.8 rad.

Step by step solution

01

Identify the Known Variables

We know the final angular velocity \( \omega_f = +1.88 \ \text{rad/s} \), the angular acceleration \( \alpha = -5.04 \ \text{rad/s}^2 \), and the time \( t = 10.0 \ \text{s} \).
02

Use Angular Motion Equation

We use the equation of motion for angular displacement:\[\theta = \omega_i t + \frac{1}{2} \alpha t^2\]where \( \theta \) is the angular displacement, \( \omega_i \) is the initial angular velocity, \( \alpha \) is the angular acceleration, and \( t \) is the time.
03

Find Initial Angular Velocity

We can find the initial angular velocity \( \omega_i \) using the equation \( \omega_f = \omega_i + \alpha t \). Rearrange it to get:\[\omega_i = \omega_f - \alpha t\]inserting the values, \( \omega_i = 1.88 \ \text{rad/s} - (-5.04) \cdot 10.0 \ \text{s} \).
04

Calculate Initial Angular Velocity

Now calculate:\[\omega_i = 1.88 + 50.4 = 52.28 \ \text{rad/s}\]
05

Calculate Angular Displacement

Substitute \( \omega_i, \alpha, \) and \( t \) into the equation for \( \theta \):\[\theta = 52.28 \cdot 10.0 + \frac{1}{2} (-5.04) \cdot (10.0)^2\]Calculate this step-by-step.
06

Compute Each Term

First, compute \( \omega_i t \):\[52.28 \times 10.0 = 522.8 \ \text{rad}\]Then, compute \( \frac{1}{2} \alpha t^2 \):\[\frac{1}{2} \times -5.04 \times 100 = -252.0 \ \text{rad}\]
07

Find Total Angular Displacement

Add the computed terms to find \( \theta \):\[\theta = 522.8 - 252.0 = 270.8 \ \text{rad}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how fast something is rotating. It tells us the rate of change of the angular position of a rotating object. Think of a carousel at a playground. As it spins, the angular velocity can be described as how many radians (or degrees) the carousel turns in a given length of time. If it's spinning fast, the angular velocity is high. If it's slowing down, the angular velocity decreases.Angular velocity is denoted by the symbol \( \omega \) (omega) and is usually measured in radians per second (rad/s). It can have a direction, typically indicated as positive for counterclockwise rotation and negative for clockwise rotation. In our scenario with the roulette wheel, the initial angular velocity \( \omega_i \) was determined using the final angular velocity \( \omega_f \), the angular acceleration \( \alpha \), and the time \( t \). The equation \( \omega_f = \omega_i + \alpha t \) allowed us to solve for \( \omega_i \) by rearranging it to find the missing initial velocity before the wheel began slowing down.
Angular Acceleration
Angular acceleration is how quickly an object's angular velocity changes. It's analogous to linear acceleration but for rotating objects. If a car accelerates faster on a straight road, it has a high linear acceleration. Similarly, if a wheel speeds up or slows down quickly, it has a high angular acceleration.In equations, angular acceleration is represented by the symbol \( \alpha \) and is measured in radians per second squared (rad/s²). Positive angular acceleration means the object is speeding up in a counterclockwise direction, whereas negative angular acceleration implies it's slowing down.For the roulette wheel problem, the angular acceleration is negative, indicating the wheel is decelerating or slowing down. Understanding this concept is crucial when working with kinematic equations, as it helps explain how the angular velocity changes over time.
Kinematic Equations for Rotation
Kinematic equations for rotation are similar to those for linear motion but adapted for rotating objects. They help in calculating various aspects like angular displacement, angular velocity, and angular acceleration. Just like with linear motion equations that use displacement, speed, and time, rotational kinematics can predict and describe the motion of spinning objects. One key equation used in our exercise is:\[\theta = \omega_i t + \frac{1}{2} \alpha t^2\]where:
  • \( \theta \) is the angular displacement in radians,
  • \( \omega_i \) is the initial angular velocity,
  • \( \alpha \) is the angular acceleration,
  • \( t \) is the time in seconds.
This equation helped us find the angular displacement of the roulette wheel, determining how many radians the wheel turned while it was decelerating.To use this equation effectively, ensuring all units are consistent and understanding each term's role in the equation is necessary. That way, you can calculate the rotation parameters accurately, just like we did in determining that the wheel rotated 270.8 radians as it slowed down.

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Most popular questions from this chapter

An automobile tire has a radius of \(0.330 \mathrm{~m},\) and its center moves forward with a linear speed of \(v=15.0 \mathrm{~m} / \mathrm{s}\). (a) Determine the angular speed of the wheel. (b) Relative to the axle, what is the tangential speed of a point located \(0.175 \mathrm{~m}\) from the axle?

(a) In general, does the average angular acceleration of a rotating object have the same direction as its initial angular velocity \(\omega_{0}\), its final angular velocity \(\omega,\) or the difference \(\omega-\omega_{0}\) between its final and initial angular velocities? (b) The table that follows lists four pairs of initial and final angular velocities for a rotating fan blade. Determine the direction (positive or negative) of the average angular acceleration for each pair. Provide reasons for your answers. $$ \begin{array}{|c|c|c|} \hline & \text { Initial angular velocity } \omega_{0} & \text { Final angular velocity } \omega \\ \hline \text { (a) } & +2.0 \mathrm{rad} / \mathrm{s} & +5.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (b) } & +5.0 \mathrm{rad} / \mathrm{s} & +2.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (c) } & -7.0 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (d) } & +4.0 \mathrm{rad} / \mathrm{s} & -4.0 \mathrm{rad} / \mathrm{s} \\ \hline \end{array} $$ Problem The elapsed time for each of the four pairs of angular velocities is \(4.0 \mathrm{~s}\). Find the average angular acceleration (magnitude and direction) for each of the four pairs. Be sure that your directions agree with those found in the Concept Question.

The drill bit of a variable-speed electric drill has a constant angular acceleration of \(2.50 \mathrm{rad} / \mathrm{s}^{2} .\) The initial angular speed of the bit is \(5.00 \mathrm{rad} / \mathrm{s}\). After \(4.00 \mathrm{~s},\) (a) what angle has the bit turned through and (b) what is the bit's angular speed?

Refer to Interactive Solution \(\underline{8.31}\) at to review a model for solving this problem. The take-up reel of a cassette tape has an average radius of \(1.4 \mathrm{~cm} .\) Find the length of tape (in meters) that passes around the reel in \(13 \mathrm{~s}\) when the reel rotates at an average angular speed of \(3.4 \mathrm{rad} / \mathrm{s}\)

The sun appears to move across the sky, because the earth spins on its axis. To a person standing on the earth, the sun subtends an angle of \(\theta_{\mathrm{sun}}=9.28 \times 10^{-3} \mathrm{rad}\) (see Conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?

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