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A space probe is traveling in outer space with a momentum that has a magnitude of \(7.5 \times 10^{7} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of \(2.0 \times 10^{6} \mathrm{~N}\) and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases to fire.

Short Answer

Expert verified
The momentum after the retrorocket fires is \(5.1 \times 10^7 \, \text{kg} \cdot \text{m/s}\).

Step by step solution

01

Understand the Problem

The space probe initially has a momentum of \(7.5 \times 10^7 \, \text{kg} \cdot \text{m/s}\). A retrorocket applies a force of \(2.0 \times 10^6 \, \text{N}\) in the opposite direction for \(12\, \text{s}\). We need to find the momentum of the probe after the retrorocket stops.
02

Calculate the Change in Momentum

Impulse is the product of force and time, and it causes a change in momentum. Calculate the impulse using the formula: \[ \text{Impulse} = F \times \Delta t \]where \(F = 2.0 \times 10^6 \, \text{N}\) and \(\Delta t = 12 \, \text{s}\). Substitute the values:\[ \text{Impulse} = 2.0 \times 10^6 \, \text{N} \times 12 \, \text{s} = 2.4 \times 10^7 \, \text{kg} \cdot \text{m/s} \]
03

Determine the Final Momentum

The change in momentum is equal and opposite to the impulse. Since the impulse acts in the opposite direction of the initial momentum:\[ \text{Final Momentum} = \text{Initial Momentum} - \text{Impulse} \]Substituting the known values:\[ \text{Final Momentum} = 7.5 \times 10^7 \, \text{kg} \cdot \text{m/s} - 2.4 \times 10^7 \, \text{kg} \cdot \text{m/s} \]\[ \text{Final Momentum} = 5.1 \times 10^7 \, \text{kg} \cdot \text{m/s} \]
04

Verify the Direction

The initial momentum was positive (arbitrary direction choice), and the impulse was in the opposite direction. Therefore, the sign and magnitude in the calculation are correct, confirming that the final momentum is still in the initial direction but reduced by the impulse value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse
Impulse is a key concept in physics that relates force to the motion of a body. Imagine a scenario where a force is applied for a certain amount of time. This effect is what we call impulse. It can be calculated by multiplying the force applied by the duration for which it is applied.
  • Formula: \[ \text{Impulse} = F \times \Delta t \]
Here, \( F \) represents the force in Newtons, and \( \Delta t \) is the time in seconds over which the force acts. The result is given in \( \, \text{kg} \cdot \text{m/s} \), which are the units of momentum.
Impulse indicates how much the force can change the object's momentum. In this exercise, the retrorocket force creates an impulse that slows down the space probe. This change is critical for redirecting or slowing things, especially in fields like aerospace.
Change in Momentum
Momentum, a fundamental concept in mechanics, is the product of an object's mass and its velocity. A change in momentum occurs when a force is applied over a time period, known as impulse. This principle is grounded in Newton's second law of motion, which connects force, mass, and acceleration.
  • Change in Momentum Formula: \[ \text{Change in Momentum} = \text{Impulse} \]
When a force acts in the opposite direction of the motion, it reduces the initial momentum.
In this exercise, the initial momentum of the space probe was significant before the retrorocket force was applied. When the applied impulse was calculated, it provided the exact change in momentum, highlighting the mathematical relationship between these concepts.
Retrorocket Force
Retrorocket force is a specific application of force in the opposite direction to slow down or decelerate an object, commonly used in spacecraft. This force, typically significant in magnitude, acts directly counter to the object's current velocity.Retrorockets are essential for managing a space probe's trajectory, enabling precise adjustments to speed and direction in the vacuum of space.
In this scenario, the retrorocket generated a force of \(2.0 \times 10^6 \, \text{N}\), working against the space probe's momentum. This huge force, applied over a specific timeframe, created an impulse that directly altered the probe's path by decreasing its speed.
Space Probe
A space probe is an unmanned spacecraft designed to explore and transmit data about space or celestial bodies. These probes are equipped for long-term missions to gather and send back valuable scientific data. The space probe in this exercise was initially moving with significant momentum due to its velocity and mass.
By using retrorockets, scientists can carefully control its speed and direction, crucial for achieving mission objectives. As the probe travels through outer space, it must adjust course or speed, relying on applied forces like retrorocket bursts to meet its goals. These adjustments ensure that probes remain on track to explore new frontiers.

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Most popular questions from this chapter

Multiple-Concept Example 7 presents a model for solving problems such as this one. A \(1055-\mathrm{kg}\) van, stopped at a traffic light, is hit directly in the rear by a \(715-\mathrm{kg}\) car traveling with a velocity of \(+2.25 \mathrm{~m} / \mathrm{s}\). Assume that the transmission of the van is in neutral, the brakes are not being applied, and the collision is elastic. What is the final velocity of (a) the car and (b) the van?

At illustrates the physics principles in this problem. An astronaut in his space suit and with a propulsion unit (empty of its gas propellant) strapped to his back has a mass of \(146 \mathrm{~kg}\). During a space-walk, the unit, which has been completely filled with propellant gas, ejects some gas with a velocity of \(+32 \mathrm{~m} / \mathrm{s}\). As a result, the astronaut recoils with a velocity of \(-0.39 \mathrm{~m} / \mathrm{s}\). After the gas is ejected, the mass of the astronaut (now wearing a partially empty propulsion unit) is \(165 \mathrm{~kg}\). What percentage of the gas propellant in the completely filled propulsion unit was depleted?

At provides a review of the concepts that are involved in this problem. A \(62.0-\mathrm{kg}\) person, standing on a diving board, dives straight down into the water. Just before striking the water, her speed is \(5.50 \mathrm{~m} / \mathrm{s}\). At a time of \(1.65 \mathrm{~s}\) after she enters the water, her speed is reduced to \(1.10 \mathrm{~m} / \mathrm{s}\). What is the net average force (magnitude and direction) that acts on her when she is in the water?

A \(55-\mathrm{kg}\) swimmer is standing on a stationary \(210-\mathrm{kg}\).oating raft. The swimmer then runs off the raft horizontally with a velocity of \(+4.6 \mathrm{~m} / \mathrm{s}\) relative to the shore. Find the recoil velocity that the raft would have if there were no friction and resistance due to the water.

At illustrates how to model a problem similar to this one. An automobile has a mass of \(2100 \mathrm{~kg}\) and a velocity of \(+17 \mathrm{~m} / \mathrm{s}\). It makes a rear-end collision with a stationary car whose mass is \(1900 \mathrm{~kg} .\) The cars lock bumpers and skid off together with the wheels locked. (a) What is the velocity of the two cars just after the collision? (b) Find the impulse (magnitude and direction) that acts on the skidding cars from just after the collision until they come to a halt. (c) If the coefficient of kinetic friction between the wheels of the cars and the pavement is \(\mu_{k}=0.68,\) determine how far the cars skid before coming to rest.

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