/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 A \(5.00 \times 10^{2}-\) kg hot... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(5.00 \times 10^{2}-\) kg hot-air balloon takes off from rest at the surface of the earth. The nonconservative wind and lift forces take the balloon up, doing \(+9.70 \times 10^{4} \mathrm{~J}\) of work on the balloon in the process. At what height above the surface of the earth does the balloon have a speed of \(8.00 \mathrm{~m} / \mathrm{s} ?\)

Short Answer

Expert verified
The balloon reaches a height of approximately 16.51 meters.

Step by step solution

01

Identify Known Values

We have the mass of the balloon, \( m = 500 \) kg, the work done by wind and lift forces, \( W = 9.70 \times 10^4 \) J, and the final speed of the balloon, \( v = 8.00 \) m/s.
02

Use Work-Energy Principle

According to the work-energy principle, the sum of the work done on the system is equal to the change in kinetic energy plus the change in potential energy. It can be expressed as:\[ W = \Delta KE + \Delta PE \]where \( \Delta KE = \frac{1}{2}mv^2 - \frac{1}{2}m(0)^2 = \frac{1}{2}mv^2 \) and \( \Delta PE = mgh \).
03

Set Up Equation for Energies

Using the values in step 1, substitute the known values in the work-energy equation:\[ 9.70 \times 10^4 = \frac{1}{2} \times 500 \times (8.00)^2 + 500 \times 9.81 \times h \]This simplifies to:\[ 9.70 \times 10^4 = 16000 + 4905h \]
04

Solve for the Height, h

Rearrange the equation to solve for height, \( h \):\[ 9.70 \times 10^4 - 16000 = 4905h \]\[ 81000 = 4905h \]\[ h = \frac{81000}{4905} \approx 16.51 \text{ meters} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. It's an essential part of understanding how objects move and interact within a system. In the case of the hot-air balloon, the kinetic energy can be calculated using the formula:\[ KE = \frac{1}{2}mv^2 \]where:
  • \( m \) is the mass of the object,
  • \( v \) is the velocity of the object.
When the balloon reaches a speed of 8.00 m/s, its kinetic energy increases from zero (since it started from rest) to a new value calculated as:\( KE = \frac{1}{2} \times 500 \times (8.00)^2 \).
This increase in kinetic energy is a critical factor in analyzing how work impacts an object's movement.
Potential Energy
Potential energy is the energy stored by an object due to its position in a gravitational field. For the hot-air balloon ascending above the Earth's surface, its potential energy increases as it rises. The formula used to calculate this energy is:\[ PE = mgh \]where:
  • \( m \) is the mass,
  • \( g \) is the acceleration due to gravity, roughly 9.81 m/s²,
  • \( h \) is the height above the surface.
In this exercise, the potential energy change helps us determine how high the balloon rises after work is done by external forces like wind and lift. The change in potential energy, combined with kinetic energy, accounts for the total work done on the balloon, illustrating how energy shifts between kinetic and potential forms.
Conservation of Energy
The principle of conservation of energy states that energy cannot be created or destroyed in an isolated system, it can only change forms. This principle ties directly into the work-energy concept, where total work done is the sum of changes in kinetic and potential energy.
For the hot-air balloon, the energy provided by the wind and lift causes changes in its mechanical energy. The work done on the balloon, \( W = 9.70 \times 10^4 \) J, transforms into both kinetic and potential energy:
  • Kinetic energy increases due to its motion.
  • Potential energy increases due to its elevation.
This conservation ensures that the work done manifests as these energy forms, setting the stage to calculate the balloon's height when it achieves a specific speed.
Mechanical Energy
Mechanical energy is the sum of kinetic and potential energy in a system. It serves as a measure of how energy is stored and transferred within the system. In the balloon exercise, mechanical energy changes as work is performed, transitioning the balloon from rest to motion and height.
The mechanical energy equation is:\[ ME = KE + PE \]Initially, when the balloon is at rest, all mechanical energy comes from work done by external forces. As the balloon gains altitude and speed, its mechanical energy is distributed between kinetic and potential energies. The final mechanical energy consists of:
  • Kinetic energy from its velocity,
  • Potential energy from its height.
Understanding mechanical energy provides a comprehensive view of how energy dynamics and the work-energy principle apply to real-world scenarios, demonstrating the interconnectedness of these core concepts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One kilowatt hour (kWh) is the amount of work or energy generated when one kilowatt of power is supplied for a time of one hour. A kilowatt hour is the unit of energy used by power companies when figuring your electric bill. Determine the number of joules of energy in one kilowatt hour.

A person pushes a \(16.0\) -kg shopping cart at a constant velocity for a distance of \(22.0 \mathrm{~m}\). She pushes in a direction \(29.0^{\circ}\) below the horizontal. A \(48.0\) - \(\mathrm{N}\) frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts? Determine the work done by (b) the pushing force, (c) the frictional force, and (d) the gravitational force.

Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generated by Lance Armstrong \((m=75.0)\) is \(6.50 \mathrm{~W}\) per kilogram of his body mass. (a) How much work does he do during a \(135-\mathrm{km}\) race in which his average speed is \(12.0 \mathrm{~m} / \mathrm{s} ?\) (b) Often, the work done is expressed in nutritional Calories rather than in joules. Express the work done in part (a) in terms of nutritional Calories, noting that 1 joule \(=2.389 \times 10^{-4}\) nutritional Calories.

A \(1.00 \times 10^{2}-\mathrm{kg}\) crate is being pushed across a horizontal floor by a force \(\overrightarrow{\mathrm{P}}\) that makes an angle of \(30.0^{\circ}\) below the horizontal. The coefficient of kinetic friction is \(0.200 .\) What should be the magnitude of \(\overrightarrow{\mathbf{P}},\) so that the net work done by it and the kinetic frictional force is zero?

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals, because it can go from rest to \(27 \mathrm{~m} / \mathrm{s}\) (about 60 \(\mathrm{mi} / \mathrm{h}\) ) in \(4.0 \mathrm{~s}\). If its mass is \(110 \mathrm{~kg}\), determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.