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Each of the space shuttle's main engines is fed liquid hydrogen by a high- pressure pump. Turbine blades inside the pump rotate at \(617 \mathrm{rev} / \mathrm{s}\). A point on one of the blades traces out a circle with a radius of \(0.020 \mathrm{~m}\) as the blade rotates. (a) What is the magnitude of the centripetal acceleration that the blade must sustain at this point? (b) Express this acceleration as a multiple of \(g=9.80 \mathrm{~m} / \mathrm{s}^{2}\)

Short Answer

Expert verified
(a) Approximately 300628.32 m/s²; (b) Approximately 30675.34 times g.

Step by step solution

01

Calculate Angular Velocity

The angular velocity \( \omega \) can be calculated using the formula \( \omega = 2\pi f \), where \( f \) is the frequency in revolutions per second. Here, \( f = 617 \mathrm{\ rev/s} \). Thus, \( \omega = 2\pi \times 617 \).
02

Compute Angular Velocity

Substitute the value to compute \( \omega \):\[ \omega = 2\pi \times 617 \]\[ \omega \approx 3874.58 \mathrm{\ rad/s} \]
03

Calculate Centripetal Acceleration

The centripetal acceleration \( a_c \) is given by the formula \( a_c = \omega^2 r \), where \( r = 0.020 \mathrm{\ m} \) is the radius. Substitute the values into the formula:\[ a_c = (3874.58)^2 \times 0.020 \]\[ a_c \approx 300628.32 \mathrm{\ m/s^2} \]
04

Express Centripetal Acceleration as Multiple of g

Divide the centripetal acceleration by the acceleration due to gravity \( g = 9.80 \mathrm{\ m/s^2} \):\[ \frac{300628.32}{9.80} \approx 30675.34 \]Thus, the acceleration is approximately 30675.34 times \( g \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how quickly an object rotates around a central point. It is commonly represented by the Greek letter \( \omega \) and is typically measured in radians per second (rad/s). But what does this mean in the context of rotatory motion?
  • It tells us how much angle, in radians, a rotating object covers in one second.
  • A full circle is \(2\pi\) radians. Therefore, if an object completes one full rotation every second, its angular velocity is \(2\pi \text{ rad/s}\).
For the exercise, the angular velocity is determined using the frequency of rotation in revolutions per second (\( \text{rev/s} \)). The formula \( \omega = 2\pi f \) tells us that we multiply the frequency by \( 2\pi \) to convert it to radians per second. Here, the turbine blades of the pump rotate at \(617 \text{ rev/s}\). This results in a very high angular speed of approximately \(3874.58 \text{ rad/s}\), indicating the fast pace at which the blades spin.
Revolutions Per Second
Revolutions per second (\( \text{rev/s} \)) is a unit of frequency that describes how many full circles or rotations an object completes in one second. It's crucial for understanding rotational speed.
  • One complete revolution equals one full rotation around a central point, similar to how the Earth rotates around its axis.
  • The frequency, denoted as \( f \), provides the number of these complete rotations per second.
In the problem at hand, \( f = 617 \text{ rev/s} \), signifying that each blade of the turbine spins around the central point within the pump 617 times every second. This high frequency of rotation contributes to the remarkable speed at which the blades move, underscoring the efficiency and power of the space shuttle's engine design. A higher \( \text{rev/s} \) means a faster rotating object, which directly impacts the calculations of angular velocity and centripetal forces.
Radius of Rotation
The radius of rotation is the straight-line distance from the center of a circle to any point on its circumference. It plays a significant role in determining the linear speed and centripetal acceleration of rotating objects.
  • Smaller radii result in tighter rotations and often require greater force to maintain high speeds.
  • A larger radius allows the object to cover more distance with each rotation.
In this exercise, a point on the turbine blade traces a circle with a radius of \(0.020 \text{ m}\) as the blade rotates. This value of radius is important for calculating centripetal acceleration, which depends not only on angular velocity but also on this radius. The centripetal acceleration formula \(a_c = \omega^2 r\) shows that both the square of the angular velocity and the radius contribute significantly to the result. In essence, understanding the radius helps in comprehending how far and fast each point on the rotating blade travels.

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Most popular questions from this chapter

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of \(3.2 \mathrm{~m} / \mathrm{s},\) and an \(83-\mathrm{kg}\) person feels a \(560-\mathrm{N}\) force pressing against his back. What is the radius of a chamber?

A motorcycle has a constant speed of \(25.0 \mathrm{~m} / \mathrm{s}\) as it passes over the top of a hill whose radius of curvature is \(126 \mathrm{~m}\). The mass of the motorcycle and driver is \(342 \mathrm{~kg}\). Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.

A car travels at a constant speed around a circular track whose radius is \(2.6 \mathrm{~km} .\) The car goes once around the track in \(360 \mathrm{~s}\). What is the magnitude of the centripetal acceleration of the car?

The moon orbits the earth at a distance of \(3.85 \times 10^{8} \mathrm{~m}\). Assume that this distance is between the centers of the earth and the moon and that the mass of the earth is \(5.98 \times 10^{24} \mathrm{~kg}\). Find the period for the moon's motion around the earth. Express the answer in days and compare it to the length of a month.

Before attempting this problem, review Examples 7 and 8 and 7 and 8 . Two curves on a highway have the same radii. However, one is unbanked and the other is banked at an angle \(\theta\). A car can safely travel along the unbanked curve at a maximum speed \(v_{0}\) under conditions when the coefficient of static friction between the tires and the road is \(\mu_{\mathrm{s}}\). The banked curve is frictionless, and the car can negotiate it at the same maximum speed \(v_{0}\). Find the angle \(\theta\) of the banked curve.

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