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A 9.5-kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of \(85 \mathrm{~cm}\) between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of \(2.8 \mathrm{~m} / \mathrm{s}\). Find (a) the magnitude of the centripetal force acting on the monkey and (b) the magnitude of the tension in the monkey's arm.

Short Answer

Expert verified
Centripetal force is 87.29 N; tension in the arm is 180.39 N.

Step by step solution

01

Understand the given quantities

The mass of the monkey is 9.5 kg, the radial distance is 85 cm (which is 0.85 m when converted to meters), and the speed at the lowest point is 2.8 m/s. We'll find (a) the magnitude of the centripetal force and (b) the tension in the monkey's arm.
02

Calculate the centripetal force

Use the formula for centripetal force: \( F_c = \frac{mv^2}{r} \), where \( m = 9.5 \text{ kg} \), \( v = 2.8 \text{ m/s} \), and \( r = 0.85 \text{ m} \). Thus, \( F_c = \frac{9.5 \times (2.8)^2}{0.85} \approx 87.29 \text{ N} \).
03

Analyze forces at the lowest point

At the lowest point, the tension in the monkey's arm needs to balance out the gravitational force and also supply the centripetal force. The tension \( T \) can be calculated using \( T = F_c + mg \), where \( mg \) is the weight of the monkey (\( mg = 9.5 \times 9.8 = 93.1 \text{ N} \)).
04

Calculate the tension in the monkey's arm

Add the centripetal force and the weight to find the tension: \( T = 87.29 + 93.1 \approx 180.39 \text{ N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is a fundamental concept in understanding how objects move in a circle. It's the force that keeps an object moving in a circular path, always directed towards the center of the circle. This force is essential because, according to Newton's First Law, an object will continue in a straight line unless acted upon by an external force. For circular motion, this external force is the centripetal force.In our monkey problem, the centripetal force is the force that pulls the monkey toward the center of the circle as it swings. We calculate it using the formula: \[ F_c = \frac{mv^2}{r} \] where \( m \) is the mass of the monkey, \( v \) is its speed, and \( r \) is the radial distance. Understanding this formula helps us see how the mass, speed, and radius together determine how strong the centripetal force needs to be to keep the monkey on its path.
Tension in Physics
Tension is another important force to consider, especially in scenarios involving ropes, cables, or, in this case, the monkey's arm. Tension can be understood as the force that is transmitted through a string, rope, or arm when it is pulled tight by forces acting from opposite ends.For the monkey swinging from a branch, the tension in its arm not only supports its weight against gravity but also contributes to the centripetal force needed to maintain its circular motion. At the lowest point in its swing, the tension is the largest, as it has to counterbalance both the gravitational force pulling the monkey down and the centripetal force pulling it toward the center of the swing.The tension can be calculated by adding the centripetal force and the gravitational force (i.e., the weight of the monkey): \[ T = F_c + mg \] where \( mg \) represents the gravitational force. This shows how tension in physics takes into account multiple forces acting on an object.
Circular Motion
Circular motion refers to an object's movement along a circular path. This can be uniform (constant speed) or non-uniform (changing speed). For uniform circular motion, the speed is constant, though the velocity is not, given that velocity is a vector with both magnitude and direction. The monkey is experiencing circular motion because it travels in a circular arc as it swings from the branch. The centripetal force is what keeps the monkey moving along this path, while the direction of the monkey's velocity continuously changes to be tangent to the circular path. Understanding circular motion is fundamental to grasping how objects move in different types of paths, and it has wide applications, from amusement park rides to planetary orbits.
Newton's Laws of Motion
Newton's Laws of Motion are crucial for analyzing the motion of objects, including cases involving centripetal force and tension. The first law, known as the law of inertia, explains that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force, like the centripetal force in circular motion.Newton's Second Law of Motion, \( F = ma \), helps us understand how the forces involved cause the monkey's acceleration. In our case, the "a" is the centripetal acceleration, directed towards the center of the circle.Finally, Newton's Third Law tells us that for every action, there is an equal and opposite reaction. While the monkey pulls on the branch with a force due to tension, the branch exerts an equal and opposite force back on the monkey.Together, these laws provide a comprehensive framework for understanding the dynamics of the monkey's swing and many other physical situations.

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Most popular questions from this chapter

A block is hung by a string from the inside roof of a van. When the van goes straight ahead at a speed of \(28 \mathrm{~m} / \mathrm{s}\), the block hangs vertically down. But when the van maintains this same speed around an unbanked curve (radius \(=150 \mathrm{~m}\) ), the block swings toward the outside of the curve. Then the string makes an angle \(\theta\) with the vertical. Find \(\theta\).

A rigid massless rod is rotated about one end in a horizontal circle. There is a mass \(m_{1}\) attached to the center of the rod and a mass \(m_{2}\) attached to the outer end of the rod. The inner section of the rod sustains three times as much tension as the outer section. Find the ratio \(m_{2} / m_{1}\)

Multiple-Concept Example 7 and Concept Simulation \(5.2\) at review the concepts that play a role in this problem. Car A uses tires for which the coefficient of static friction is \(1.1\) on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is \(25 \mathrm{~m} / \mathrm{s}\). Car B uses tires for which the coefficient of static friction is \(0.85\) on the same curve. What is the maximum speed at which car \(\mathrm{B}\) can negotiate the curve?

Before attempting this problem, review Examples 7 and 8 and 7 and 8 . Two curves on a highway have the same radii. However, one is unbanked and the other is banked at an angle \(\theta\). A car can safely travel along the unbanked curve at a maximum speed \(v_{0}\) under conditions when the coefficient of static friction between the tires and the road is \(\mu_{\mathrm{s}}\). The banked curve is frictionless, and the car can negotiate it at the same maximum speed \(v_{0}\). Find the angle \(\theta\) of the banked curve.

A satellite is in a circular orbit around an unknown planet. The satellite has a speed of \(1.70 \times 10^{4} \mathrm{~m} / \mathrm{s}\), and the radius of the orbit is \(5.25 \times 10^{6} \mathrm{~m}\). A second satellite also has a circular orbit around this same planet. The orbit of this second satellite has a radius of \(8.60 \times 10^{6} \mathrm{~m}\). What is the orbital speed of the second satellite?

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