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A jet \(\left(m=2.00 \times 10^{5} \mathrm{~kg}\right)\), flying at \(123 \mathrm{~m} / \mathrm{s}\), banks to make a horizontal circular turn. The radius of the turn is \(3810 \mathrm{~m}\). Calculate the necessary lifting force.

Short Answer

Expert verified
The necessary lifting force is approximately \( 7.93 \times 10^5 \, \text{N} \).

Step by step solution

01

Understand the Problem

We have a jet with mass \( m = 2.00 \times 10^5 \, \text{kg} \), velocity \( v = 123 \, \text{m/s} \), and it makes a horizontal circular turn with radius \( r = 3810 \, \text{m} \). We need to find the necessary lifting force to maintain this turn.
02

Identify the Forces Involved

In a circular motion, the centripetal force is required to keep the jet in circular motion. This force is provided by the lifting force (the upward component of the lift force in a banked turn).
03

Calculate the Centripetal Force

The centripetal force \( F_c \) required for circular motion is given by the formula: \[ F_c = \frac{mv^2}{r} \]Substitute the given values: \[ m = 2.00 \times 10^5 \, \text{kg}, \quad v = 123 \, \text{m/s}, \quad r = 3810 \, \text{m} \]\[ F_c = \frac{(2.00 \times 10^5)(123)^2}{3810} \approx 7.93 \times 10^5 \, \text{N} \]
04

Conclude the Solution

The necessary lifting force to maintain the horizontal circular turn is approximately \( 7.93 \times 10^5 \, \text{N} \). This lifting force ensures that the jet remains in the circular path in a level turn.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
In physics, circular motion refers to the motion of an object traveling around a circular path. When an object is moving in a circle, even though its speed might be constant, its direction is continuously changing. This change in direction means the object is actually accelerating, and this acceleration is called centripetal acceleration.
Centripetal acceleration keeps the object moving in the path of the circle at a specific radius. It is directed towards the center of the circle, ensuring the path is stable. To maintain this circular motion, a force is required, known as the centripetal force. This force acts perpendicular to the object's velocity and points toward the center of the circle.
  • If the circular motion is horizontal, like in the case of our jet, this force comes from other forces, such as tension, friction, or lift, depending on the scenario.
  • Formula for centripetal force: The formula is given by \[ F_c = \frac{mv^2}{r} \] where \(m\) is mass, \(v\) is the velocity, and \(r\) is the radius of the circle.
Horizontal Circular Turn
A horizontal circular turn occurs when an object moves in a circular path parallel to the ground. For a jet, this involves making a turn where the wings are angled slightly to maintain balance and the circular path.
When the jet moves in a horizontal circular turn, it requires a certain amount of force to keep it on that path. This force is provided by the lift force generated by the wings.
The lift force is critical in maintaining the stability and direction of the jet as it travels. This force has to not only counteract gravity but also provide the necessary inward force to maintain the circular trajectory.
Lifting Force
Lifting force is the force generated by the difference in pressure above and below the wings of an aircraft. It acts perpendicular to the relative motion of the aircraft and is crucial for supporting its weight during flight.
  • For maintaining a horizontal circular turn, the lifting force must be adjusted to provide the necessary centripetal force along with supporting the aircraft against gravity.
  • In a banked position, part of this lift acts to counteract gravity, while the rest provides the inward force required for circular motion.
  • The calculation of the required lift is based on balancing these forces to achieve stable flight.
The lifting force is thus slightly modified by the banking angle to ensure both vertical and horizontal stability.
Banked Turn
A banked turn in aviation refers to a maneuver where an aircraft tilts its wings to change direction. This is done by altering the angle of the lift force, enabling the aircraft to execute a turn without slipping sideways.
In a banked turn, the lift from the aircraft's wings is no longer completely vertical but has an inward component. This inward component contributes to the centripetal force needed for circular motion.
  • The banking allows the aircraft to maintain speed and reduce stress on its structure by efficiently applying the lift to help with the turn.
  • For a stable banked turn, pilots need to coordinate both the banking angle and speed.
A successful banked turn not only ensures the jet stays on course but also maintains the balance between inertia and necessary force for the turn.

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Most popular questions from this chapter

Before attempting this problem, review Examples 7 and 8 and 7 and 8 . Two curves on a highway have the same radii. However, one is unbanked and the other is banked at an angle \(\theta\). A car can safely travel along the unbanked curve at a maximum speed \(v_{0}\) under conditions when the coefficient of static friction between the tires and the road is \(\mu_{\mathrm{s}}\). The banked curve is frictionless, and the car can negotiate it at the same maximum speed \(v_{0}\). Find the angle \(\theta\) of the banked curve.

A motorcycle has a constant speed of \(25.0 \mathrm{~m} / \mathrm{s}\) as it passes over the top of a hill whose radius of curvature is \(126 \mathrm{~m}\). The mass of the motorcycle and driver is \(342 \mathrm{~kg}\). Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.

The hammer throw is a track-and-field event in which a \(7.3-\mathrm{kg}\) ball (the "hammer") is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion and eventually returns to earth some distance away. The world record for this distance is \(86.75 \mathrm{~m}\), achieved in 1986 by Yuriy Sedykh. Ignore air resistance and the fact that the ball is released above the ground rather than at ground level. Furthermore, assume that the ball is whirled on a circle that has a radius of \(1.8 \mathrm{~m}\) and that its velocity at the instant of release is directed \(41^{\circ}\) above the horizontal. Find the magnitude of the centripetal force acting on the ball just prior to the moment of release.

A rigid massless rod is rotated about one end in a horizontal circle. There is a mass \(m_{1}\) attached to the center of the rod and a mass \(m_{2}\) attached to the outer end of the rod. The inner section of the rod sustains three times as much tension as the outer section. Find the ratio \(m_{2} / m_{1}\)

The earth orbits the sun once per year at the distance of \(1.50 \times 10^{11} \mathrm{~m}\). Venus orbits the sun at a distance of \(1.08 \times 10^{11} \mathrm{~m} .\) These distances are between the centers of the planets and the sun. How long (in earth days) does it take for Venus to make one orbit around the sun?

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