/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A \(15-\mathrm{g}\) bullet is fi... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(15-\mathrm{g}\) bullet is fired from a rifle. It takes \(2.50 \times 10^{-3} \mathrm{~s} \mathrm{~s}\) for the bullet to travel the length of the barrel, and it exits the barrel with a speed of \(715 \mathrm{~m} / \mathrm{s}\). Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

Short Answer

Expert verified
The average net force on the bullet is 4,290 N.

Step by step solution

01

Understand the Problem

We are asked to find the average net force exerted on a bullet as it travels through a rifle barrel. The given values are the mass of the bullet (15 g or 0.015 kg), the time the bullet is in the barrel (\(2.50 \times 10^{-3}\) s), and its exit speed (715 m/s). We assume constant acceleration over this time period.
02

Convert Units (if necessary)

Although the mass is given in grams, we need to convert it to kilograms to use standard SI units in our calculations. The mass of the bullet is 15 g, which is 0.015 kg.
03

Calculate Acceleration Using Kinematic Equation

We use the kinematic equation for constant acceleration: \(v = u + at\), where \(v\) is the final velocity (715 m/s), \(u\) is the initial velocity (0 m/s since the bullet starts from rest), \(a\) is the acceleration, and \(t\) is the time (\(2.50 \times 10^{-3}\) s). Solving for \(a\), we get:\[a = \frac{v - u}{t} = \frac{715}{2.50 \times 10^{-3}} = 286,000\ \text{m/s}^2\]
04

Calculate Net Force Using Newton's Second Law

Newton's Second Law states that force \(F\) is the product of mass \(m\) and acceleration \(a\): \(F = ma\). We substitute the known values:\[F = 0.015\ \text{kg} \times 286,000\ \text{m/s}^2 = 4,290\ \text{N}\]
05

Box the Final Answer

The average net force exerted on the bullet can be found using all calculations above. The force is 4,290 N, which represents the force exerted by the rifle on the bullet to achieve its speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
In physics, kinematic equations are essential for understanding motion. They describe how objects move under constant acceleration. These equations allow us to solve various motion problems by relating variables like velocity, acceleration, time, and displacement.
Kinematic equations assume no change in the rate of acceleration, making them highly applicable in controlled environments like a rifle barrel, where a bullet accelerates at a steady rate. One of the most common kinematic equations is \(v = u + at\). Here, \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(t\) is the time. In the case of a fired bullet, even though it starts at rest with an initial velocity \(u = 0\), it reaches a final velocity of 715 m/s as it exits the barrel. By using the time in the barrel (\(2.50 \times 10^{-3}\) s), we can directly calculate the bullet's constant acceleration. This flexibility makes kinematic equations powerful tools in physics problems related to constant acceleration.
Constant Acceleration
Constant acceleration refers to a steady increase in the velocity of an object over time. This means that the object's speed changes uniformly, making calculations more predictable and straightforward.
When a bullet is fired, the constant acceleration assumption simplifies the math we need. The bullet undergoes a constant force applied by the expanding gases from the rifle, which allows it to accelerate until it leaves the barrel. Since the same force acts constantly over the entire time until exit, it results in a uniform acceleration. In reality, many factors can cause variability, but for simplicity and to focus on fundamental principles, constant acceleration is assumed in most basic physics problems.
In this context, once we have calculated the acceleration using the kinematic equation, constant acceleration makes it easy to deduce other aspects of the bullet's motion, including the force exerted on it by the rifle.
Net Force Calculations
Net force calculations are critical in understanding how forces affect motion. According to Newton's Second Law, the net force acting on an object is equal to the product of its mass and acceleration. This is expressed as \(F = ma\).
This formula helps us determine the total force needed to accelerate an object. In the exercise, the mass of the bullet is 0.015 kg. Given the acceleration from our kinematic calculations is 286,000 \(\mathrm{m/s^2}\), we multiply these two to find the net force. Doing so gives us a figure of 4,290 N.
This net force represents the average force exerted on the bullet by the gases within the barrel of the rifle as it is fired. Understanding these calculations is vital for many real-world applications, like designing firearms or understanding ballistics.

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Most popular questions from this chapter

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