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Part \(a\) of the drawing shows a bucket of water suspended from the pulley of a well; the tension in the rope is \(92.0 \mathrm{~N}\). Part \(b\) shows the same bucket of water being pulled up from the well at a constant velocity. What is the tension in the rope in part \(b\) ?

Short Answer

Expert verified
The tension in the rope in part b is 92.0 N.

Step by step solution

01

Understanding the Situation

In part \(a\), the bucket is stationary, which means the tension in the rope equals the gravitational force acting on the bucket. Therefore, \( T = F_g = 92.0 \, \text{N}\).
02

Analyze Part b: Constant Velocity

When the bucket is being pulled up at a constant velocity, there is no net acceleration (Newton's First Law). Thus, the tension in the rope must still balance the gravitational force.
03

Applying Newton's First Law

Since the bucket is moving at a constant velocity in part \(b\), the forces are balanced. Therefore, the tension in the rope, \( T_b \), is equal to the gravitational force \( F_g \).
04

Conclusion: Tension in Part b

The tension in part \(b\) is the same as in part \(a\): \( T_b = 92.0 \, \text{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental concept in physics and plays a crucial role in this exercise. It's the pulling force that attracts two bodies towards each other, especially noticeable between Earth and objects on it. The formula to calculate gravitational force is:\[ F_g = m \cdot g \]where:
  • \( F_g \) is the gravitational force,
  • \( m \) is the mass of the object, and
  • \( g \) is the acceleration due to gravity, approximately \( 9.8 \, \text{m/s}^2 \) on Earth.
In part (a) of the problem, the gravitational force acting on the bucket is equal to the tension in the rope, which is given as \( 92.0 \, \text{N} \). This shows that the force required to hold the bucket stationary (and thus the gravitational force) is \( 92.0 \, \text{N} \). When analyzing real-world scenarios, gravitational force helps determine how much force is needed to lift or support objects. It's essential to consider gravitational force whenever an object is in contact with Earth or near Earth's surface.
Constant Velocity
The term "constant velocity" is pivotal in understanding part (b) of this problem. When an object moves at constant velocity, it means that both the speed and direction are consistent. In simple terms, there's no speeding up or slowing down. At constant velocity, the net force acting on the object is zero.This is because all forces are balanced. In the case of the bucket being pulled up, this balance is between tension in the rope and the gravitational force pulling the bucket down. Using Newton's laws, constant velocity signifies that:
  • The upward tension force is equal to the downward gravitational force.
  • There is no acceleration in the system.
This means the tension in the rope remains \( 92.0 \, \text{N} \), the same as when the bucket is stationary. Any variance in speed or direction would require an additional net force, altering the tension needed.
Newton's First Law
Newton's First Law, also known as the law of inertia, states that an object will remain at rest, or move at a constant velocity, unless acted upon by a net force. It's a fundamental principle that helps explain motion and stability in physics.In the context of this exercise:
  • The bucket remains in motion at constant velocity, meaning no unbalanced force acts on it.
  • This stability is why the tension remains at \( 92.0 \, \text{N} \), as it perfectly counteracts the gravitational pull of the Earth.
When considering real-world applications, Newton's First Law explains why objects in motion stay in motion unless something changes their speed or direction. This concept is central to understanding why, in this exercise, pulling the bucket at constant velocity doesn't alter the tension. The rope's tension perfectly balances the forces, ensuring no acceleration occurs. Hence, equilibrium is maintained, showcasing Newton's First Law in action.

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Most popular questions from this chapter

A \(325-\mathrm{kg}\) boat is sailing \(15.0^{\circ}\) north of east at a speed of \(2.00 \mathrm{~m} / \mathrm{s}\). Thirty seconds later, it is sailing \(35.0^{\circ}\) north of east at a speed of \(4.00 \mathrm{~m} / \mathrm{s}\). During this time, three forces act on the boat: a \(31.0-\mathrm{N}\) force directed \(15.0^{\circ}\) north of east (due to an auxiliary engine), a 23.0-N force directed \(15.0^{\circ}\) south of west (resistance due to the water), and \(\vec{F}_{W}\) (due to the wind). Find the magnitude and direction of the force \(\overrightarrow{\mathrm{F}}_{\mathrm{W}} .\) Express the direction as an angle with respect to due east.

Three uniform spheres are located at the corners of an equilateral triangle. Each side of the triangle has a length of \(1.20 \mathrm{~m}\). Two of the spheres have a mass of \(2.80 \mathrm{~kg}\) each. The third sphere (mass unknown) is released from rest. Considering only the gravitational forces that the spheres exert on each other, what is the magnitude of the initial acceleration of the third sphere?

In a supermarket parking lot, an employee is pushing ten empty shopping carts, lined up in a straight line. The acceleration of the carts is \(0.050 \mathrm{~m} / \mathrm{s}^{2}\). The ground is level, and each cart has a mass of \(26 \mathrm{~kg}\). (a) What is the net force acting on any one of the carts? (b) Assuming friction is negligible, what is the force exerted by the fifth cart on the sixth cart?

Two objects \((45.0\) and \(21.0 \mathrm{~kg})\) are connected by a massless string that passes over a massless, frictionless pulley. The pulley hangs from the ceiling. Find (a) the acceleration of the objects and (b) the tension in the string.

Jupiter is the largest planet in our solar system, having a mass and radius that are, respectively, 318 and 11.2 times that of earth. Suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. Each object falls the same distance before striking the ground. Determine the ratio of the time of fall on Jupiter to that on earth.

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