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An \(81-\mathrm{kg}\) baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is \(0.49 .\) (a) What is the magnitude of the frictional force? (b) If the player comes to rest after \(1.6 \mathrm{~s}\), what was his initial velocity?

Short Answer

Expert verified
(a) 389.962 N (b) 7.702 m/s.

Step by step solution

01

Determine the Normal Force

The normal force, \( F_n \), acting on the player is equal to the gravitational force because the player is sliding horizontally. This force can be calculated using the formula: \[ F_n = m \cdot g \] where \( m = 81\, kg \) is the mass of the player and \( g = 9.8\, m/s^2 \) is the acceleration due to gravity. Thus, \[ F_n = 81 \cdot 9.8 = 793.8\, N \].
02

Calculate the Frictional Force

The frictional force, \( F_f \), is given by the formula: \[ F_f = \mu_k \cdot F_n \] where \( \mu_k = 0.49 \) is the coefficient of kinetic friction. Substituting the known values gives: \[ F_f = 0.49 \cdot 793.8 = 389.962\, N \].
03

Calculate Acceleration Due to Friction

Using Newton's second law, the acceleration can be calculated by \[ F_f = m \cdot a \] where \( a \) is the acceleration. Solving for \( a \), \[ a = \frac{F_f}{m} = \frac{389.962}{81} \approx 4.814\, m/s^2 \].
04

Determine Initial Velocity

To find the initial velocity, use the kinematic equation:\[ v_f = v_i + a \cdot t \], where \( v_f = 0\, m/s \) (final velocity), \( a = -4.814\, m/s^2 \) (deceleration), and \( t = 1.6\, s \). Rearrange to solve for \( v_i \):\[ v_i = v_f - a \cdot t = 0 - (-4.814) \cdot 1.6 \approx 7.702\, m/s \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
When objects slide against each other, they experience a force opposing their motion, known as kinetic friction. This force acts parallel to the surfaces in contact. In the case of the sliding baseball player, kinetic friction slows him down as he moves towards second base. Kinetic friction occurs because of microscopic interactions between surface irregularities.
The magnitude of kinetic friction depends on two factors:
  • The coefficient of kinetic friction (\( \mu_k \)) - This is a dimensionless constant that describes how sticky or slippery the surfaces are relative to each other. In this exercise, the coefficient is given as 0.49.
  • The normal force (\( F_n \)) - This is the force perpendicular to the surfaces in contact. For the baseball player, the normal force is simply his weight, calculated by multiplying his mass by the gravitational acceleration.
Using the formula \( F_f = \mu_k \cdot F_n \), we can find the frictional force acting on the player. This friction serves to steadily decelerate the player until he comes to a stop.
Newton's Second Law
Newton's Second Law provides a fundamental insight into how forces influence motion. It states that the acceleration (\( a \)) of an object is directly proportional to the net force (\( F \)) acting on it and inversely proportional to its mass (\( m \)). This relationship is expressed by the formula:\[ F = m \cdot a \]In practical terms, this means an object's acceleration depends on both the magnitude of the force applied and its mass. For our sliding baseball player, this law helps us calculate the negative acceleration caused by kinetic friction.Here’s how it works in our scenario:
  • The net force acting on the player is the kinetic friction force. This is because the other forces (such as gravity and the normal force) cancel each other out.
  • By rearranging the formula to \( a = \frac{F_f}{m} \), we compute the player's deceleration due to friction.
Newton's Second Law thus elegantly allows us to transform the frictional force data into an acceleration value, which is crucial for further analyzing the player's motion.
Kinematic Equations
Kinematic equations describe the motion of objects without considering the forces causing the motion. They are potent tools when dealing with problems involving time, velocity, acceleration, and displacement.One of the core kinematic equations used in this exercise is:\[ v_f = v_i + a \cdot t \]This equation links the final velocity (\( v_f \)), initial velocity (\( v_i \)), acceleration (\( a \)), and time (\( t \)). Here’s how each piece fits into the baseball player's solution:
  • Our final velocity (\( v_f \)) is zero because the player comes to a stop.
  • We calculated the acceleration (\( a \)) due to friction as negative, representing deceleration.
  • The time (\( t \)) over which this deceleration happens is given as 1.6 seconds.
Solving for the initial velocity (\( v_i \)) provides us with the speed at which the player was sliding as he started the slide. This demonstrates how kinematic equations are practically applied to unravel the mysteries of motion just from some basic initial conditions and measurements.

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