/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 108 As part \(a\) of the drawing sho... [FREE SOLUTION] | 91Ó°ÊÓ

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As part \(a\) of the drawing shows, two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of \(412 \mathrm{~N},\) and the other has a weight of \(908 \mathrm{~N}\). The rope and the pulleys are massless and there is no friction. (a) What is the acceleration of the lighter block? (b) Suppose that the heavier block is removed, and a downward force of \(908 \mathrm{~N}\) is provided by someone pulling on the rope, as part \(b\) of the drawing shows. Find the acceleration of the remaining block. (c) Explain why the answers in (a) and (b) are different.

Short Answer

Expert verified
(a) The acceleration is approximately 3.68 m/s². (b) The acceleration is approximately 21.61 m/s². (c) Acceleration differs due to the distribution of force over different masses.

Step by step solution

01

Identify Forces

Identify the weights acting on both blocks. The lighter block has a weight of \( W_1 = 412 \mathrm{~N} \) and the heavier block has a weight of \( W_2 = 908 \mathrm{~N} \). The masses can be calculated using \( W = mg \).
02

Calculate Masses

Determine the masses of the blocks. For the lighter block, \( m_1 = \frac{W_1}{g} = \frac{412}{9.8} \approx 42.04 \mathrm{~kg} \). For the heavier block, \( m_2 = \frac{W_2}{g} = \frac{908}{9.8} \approx 92.65 \mathrm{~kg} \).
03

Set Up Equations of Motion

Using Newton's second law, set up equations of motion for the system of the two blocks connected over pulleys: \( m_2 g - m_1 g = (m_1 + m_2) a \).
04

Solve for Acceleration (a)

Substitute the known values into the equation: \( 908 - 412 = (42.04 + 92.65) a \) which simplifies to \( 496 = 134.69 a \). Solve for \( a \) to get \( a \approx 3.68 \mathrm{~m/s^2} \).
05

Adjust Model for Scenario (b)

When the heavier block is removed, there's a force of \( 908 \mathrm{~N} \) acting directly on the lighter block. Use \( F = ma \) for the block: \( 908 = m_1 a \).
06

Solve for Acceleration (b)

Using \( m_1 = 42.04 \mathrm{~kg} \), substitute into the equation: \( 908 = 42.04 a \), yielding \( a \approx 21.61 \mathrm{~m/s^2} \).
07

Compare Scenarios (c)

In case (a), two blocks are interconnected, creating a system where the net force is distributed across both masses. In case (b), the force directly accelerates the lighter block, resulting in higher acceleration due to the absence of the second block's inertia.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pulley System
A pulley system consists of one or more wheels and a rope that allows forces to be redirected and usually make lifting or moving objects easier. In the exercise, a pulley system is used to connect two blocks of different weights.

In this setup, one block's gravitational force helps to lift the other block, taking advantage of the mechanical advantage of pulleys. The pulleys used here are described as massless and frictionless, meaning they do not add extra forces to the system, allowing us to calculate the movement solely based on the weights of the blocks.

Pulley systems are fundamental in understanding how forces can be redistributed, and they illustrate a practical application of Newton's Laws of Motion in mechanical engineering and physics.
Force and Acceleration
According to Newton's Second Law of Motion, the acceleration of an object depends on the net force acting upon it and the mass of the object, described by the formula:

\[ F = ma \]

This relationship highlights that if more force is applied to a mass, it will accelerate faster. Conversely, for the same force, a larger mass will accelerate more slowly.

In the given exercise, the force acting on the blocks is due to their weights, with each block's acceleration calculated based on the total force in the system and the combined mass of the blocks.
  • Scenario (a): With both blocks in the system, the forces are shared, leading to moderate acceleration.
  • Scenario (b): With the heavier block removed, the same force is applied directly to the lighter block, resulting in higher acceleration.
Understanding how different setups and forces affect acceleration helps in designing systems that efficiently manage force and motion.
Mass and Weight
Mass and weight are related yet distinct concepts. Mass measures the amount of matter in an object and is typically measured in kilograms. Weight, however, is the force exerted by gravity on that mass, calculated as:

\[ W = mg \]

where \( g \) is the acceleration due to gravity (approximately 9.8 m/s² on Earth).

In this exercise, the weights given are converted into their respective masses to determine how these masses will behave in the pulley system.

Recognizing the difference between mass and weight is crucial for solving physics problems, as it directly impacts calculations involving forces and motion.
Frictionless Systems
Frictionless systems are idealized models used to simplify calculations by eliminating the force of friction, which usually resists motion between contacting surfaces. By assuming no friction, we can focus on other forces without additional opposing forces complicating the analysis.

In the context of the exercise, the rope and pulleys are considered massless and frictionless, meaning they do not contribute any additional forces that alter the motion of the blocks. This allows us to apply Newton's laws more straightforwardly, looking only at the gravitational forces and resulting accelerations.

While real-world systems always include some friction, studying frictionless models provides a baseline to better understand the dynamics of forces in more complex scenarios.

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Most popular questions from this chapter

Refer to Multiple-Concept Example 10 for help in solving problems like this one. An ice skater is gliding horizontally across the ice with an initial velocity of \(+6.3 \mathrm{~m} / \mathrm{s}\). The coefficient of kinetic friction between the ice and the skate blades is \(0.081,\) and air resistance is negligible. How much time elapses before her velocity is reduced to \(+2.8 \mathrm{~m} /\) s?

At a time when mining asteroids has become feasible, astronauts have connected a line between their 3500 -kg space tug and a 6200 -kg asteroid. Using their ship's engine, they pull on the asteroid with a force of \(490 \mathrm{~N}\). Initially the tug and the asteroid are at rest, \(450 \mathrm{~m}\) apart. How much time does it take for the ship and the asteroid to meet?

Concept Simulation 4.1 at reviews the concepts that are important in this problem. The speed of a bobsled is increasing because it has an acceleration of \(2.4 \mathrm{~m} / \mathrm{s}^{2}\). At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total \(450 \mathrm{~N}\). The mass of the bobsled and its riders is \(270 \mathrm{~kg}\). (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

A bicyclist is coasting straight down a hill at a constant speed. The mass of the rider and bicycle is \(80.0 \mathrm{~kg},\) and the hill is inclined at \(15.0^{\circ}\) with respect to the horizontal. Air resistance opposes the motion of the cyclist. Later, the bicyclist climbs the same hill at the same constant speed. How much force (directed parallel to the hill) must be applied to the bicycle in order for the bicyclist to climb the hill?

A stuntman is being pulled along a rough road at a constant velocity by a cable attached to a moving truck. The cable is parallel to the ground. The mass of the stuntman is 109 \(\mathrm{kg},\) and the coefficient of kinetic friction between the road and him is \(0.870 .\) Find the tension in the cable.

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