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What is the atomic number \(Z\), the atomic mass number \(A,\) and the element \(X\) in the reaction \({ }_{5}^{10} \mathrm{~B}(\alpha, p){ }_{Z}^{A} \mathrm{X} ?\)

Short Answer

Expert verified
The element \( X \) is \( {}_{6}^{13} \)C with \( Z = 6 \) and \( A = 13 \).

Step by step solution

01

Understand the Given Reaction

The reaction given is: \( {}_{5}^{10} \mathrm{B}(\alpha, p){}_{Z}^{A} \mathrm{X} \). This notation indicates that a boron atom \( ({}_{5}^{10} \mathrm{B}) \) is interacting with an alpha particle \( \alpha \), producing a proton \( p \) and another element \( {}_{Z}^{A} \mathrm{X} \).
02

Identify Particles Involved

- The alpha particle \( \alpha \) corresponds to helium \( {}_{2}^{4} \mathrm{He} \), and it consists of 2 protons and 4 nucleons.- The proton \( p \) is \( {}_{1}^{1} \mathrm{H} \), with 1 proton and 1 nucleon.
03

Apply Conservation of Atomic Number

The conservation of atomic number requires that the total number of protons (atomic numbers) before the reaction equals the total number of protons after the reaction.\[ 5 + 2 = 1 + Z \] Solving this, \( Z = 5 + 2 - 1 = 6 \).
04

Apply Conservation of Mass Number

The conservation of mass number requires that the total number of nucleons before the reaction equals the total number of nucleons after the reaction.\[ 10 + 4 = 1 + A \] Solving this, \( A = 10 + 4 - 1 = 13 \).
05

Determine the Element (X)

With \( Z = 6 \), we know the element is carbon, as the atomic number of carbon is 6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The atomic number is a fundamental property of an element. It represents the number of protons in the nucleus of an atom. In the context of nuclear reactions, the atomic number is often denoted by the symbol \( Z \). For instance, in a reaction equation, \( {}_{Z}^{A} X \), \( Z \) specifies the number of protons in the element \( X \).

Every element on the periodic table has a unique atomic number, which is a key factor in defining its chemical identity. For example, carbon has an atomic number of 6, meaning it has 6 protons in its nucleus. Understanding the atomic number is crucial because it does not only determine the element type but also influences other properties like the element's position in the periodic table and its chemical behavior.

In nuclear reactions, the law of conservation of atomic number states that the total number of protons before a reaction must equal the total number of protons after the reaction. So when solving a nuclear equation, calculating the sum of the atomic numbers on both sides helps identify the resulting element after a reaction occurs.
Mass Number
The mass number, also known as the atomic mass number and denoted by \( A \), is another key characteristic of an atom. It is the total count of protons and neutrons, collectively known as nucleons, in an atomic nucleus. While the atomic number \( Z \) provides information about the protons, the mass number \( A \) gives a complete picture of the atom’s mass at a nuclear level.

For example, if an atom has 6 protons and 7 neutrons, its mass number \( A \) would be 13. This is because \( A = Z + N \), where \( N \) is the number of neutrons, so here \( 6 + 7 = 13 \). Knowing the mass number is essential in nuclear reactions to adhere to the conservation laws. The total mass number before a nuclear reaction must equal the total mass number after the reaction.

When dealing with nuclear reactions like \( {}_{5}^{10} B(\alpha, p){}_{Z}^{A} X \), conservation of mass number can help determine unknown quantities in the reaction, aiding in the calculation of new isotopes formed during the interaction.
Alpha Particle
An alpha particle is a type of nuclear particle composed of 2 protons and 2 neutrons, making it essentially a helium nucleus, \( {}_{2}^{4} \mathrm{He} \). Due to this composition, an alpha particle has an atomic number of 2 and a mass number of 4. This attribute is crucial in nuclear reactions, as it helps to balance both the atomic numbers and mass numbers on either side of a nuclear equation.

Alpha particles are known for their relatively large mass and positive charge, which influence how they interact with other atoms. In nuclear reactions, such as the one described in the exercise \( {}_{5}^{10} \mathrm{B}(\alpha, p){}_{Z}^A \mathrm{X} \), the alpha particle plays a key role. It interacts with a target nucleus, like boron, often resulting in the emission of other particles and formation of a different element or isotope.

It's important to understand that because they contain 2 protons, when alpha particles participate in reactions, they change the atomic structure significantly, making them crucial players in both natural and artificial nuclear reactions. This kind of reaction is critical in fields like nuclear physics, where understanding and manipulating atomic nuclei are essential.

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Most popular questions from this chapter

The proton-proton cycle thought to occur in the sun consists of the following sequence of reactions : 1\. \(\quad{ }_{1}^{1} \mathrm{H}+{ }_{1}^{1} \mathrm{H} \rightarrow{ }_{1}^{2} \mathrm{H}+{ }_{1}^{0} \mathrm{e}+v\) 2\. \(\quad{ }_{1}^{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H} \rightarrow{ }_{2}^{3} \mathrm{H}+\gamma\) 3\. \({ }_{2}^{3} \mathrm{He}+{ }_{2}^{3} \mathrm{He} \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{1}^{1} \mathrm{H}+{ }_{1}^{1} \mathrm{H}\) In these reactions \(\underset{1}{0}\) e is a positron (mass \(=0.000549 \mathrm{u}), v\) is a neutrino (mass \(\approx 0 \mathrm{u}\) ), and \(\gamma\) is a gamma ray photon (mass \(=0 \mathrm{u}\) ). Note that reaction (3) uses two \(\frac{3}{2} \mathrm{He}\) nuclei, which are formed by two reactions of type (1) and two reactions of type (2). Verify that the proton-proton cycle generates about \(25 \mathrm{MeV}\) of energy. The atomic masses are \(\frac{1}{1} \mathrm{H}\) \((1.007825 \mathrm{u}), \quad{ }_{1}^{2} \mathrm{H}(2.014102 \mathrm{u}),{ }_{2}^{3} \mathrm{He}(3.016030 \mathrm{u}),\) and \({ }_{2}^{4} \mathrm{He}(4.002603 \mathrm{u}) .\) Be sure to account for the fact that there are two electrons in two hydrogen atoms, whereas there is one electron in a single deuterium ( \({ }_{1}^{2} \mathrm{H}\) ) atom. The mass of one electron is 0.000549 u.

The energy consumed in one year in the United States is about \(9.3 \times 10^{19} \mathrm{~J}\). With each Q35 U fission, about \(2.0 \times 10^{2} \mathrm{MeV}\) of energy is released. How many kilograms of \({ }_{92}^{235} \mathrm{U}\) would be needed to generate this energy if all the nuclei fissioned?

A \(20.0\) kiloton atomic bomb releases as much energy as \(20.0\) kilotons of TNT \((1.0\) kiloton of TNT releases about \(5.0 \times 10^{12} \mathrm{~J}\) of energy). Recall that about \(2.0 \times 10^{2} \mathrm{MeV}\) of energy is released when each \({ }_{92}^{235} \mathrm{U}\) nucleus fissions. (a) How many \({ }_{92}^{235} \mathrm{U}\) nuclei are fissioned to produce the bomb's energy? (b) How many grams of uranium are fissioned? (c) What is the equivalent mass (in grams) of the bomb's energy?

When a \({ }_{92}^{235} \mathrm{U}(235.043924 \mathrm{u})\) nucleus fissions, about \(200 \mathrm{MeV}\) of energy is released. What is the ratio of this energy to the rest energy of the uranium nucleus?

A \(75-\mathrm{kg}\) person is exposed to 45 mrem of \(\alpha\) particles \((\mathrm{RBE}=12) .\) How much energy has this person absorbed?

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