Chapter 31: Problem 29
The isotope \({ }_{88}^{224}\) Ra of radium has a decay constant of \(2.19 \times 10^{-6} \mathrm{~s}^{-1}\). What is the halflife (in days) of this isotope?
Short Answer
Expert verified
The half-life of the isotope is approximately 3.66 days.
Step by step solution
01
Understanding decay constant and half-life relationship
The decay constant \( \lambda \) is related to the half-life \( t_{1/2} \) of a radioactive substance by the formula \( t_{1/2} = \frac{\ln(2)}{\lambda} \). This equation derives from the exponential decay law and the definition of half-life, which is the time taken for the substance to reduce to half its initial amount.
02
Calculate the half-life in seconds
Substitute the given decay constant \( \lambda = 2.19 \times 10^{-6} \mathrm{~s}^{-1} \) into the formula. \[t_{1/2} = \frac{\ln(2)}{2.19 \times 10^{-6}}\]Calculate \( \ln(2) \approx 0.693 \) and solve:\[t_{1/2} = \frac{0.693}{2.19 \times 10^{-6}} \approx 3.163 \times 10^5 \text{ seconds}\]
03
Convert seconds to days
Now convert the half-life from seconds to days. There are 86400 seconds in one day (60 seconds per minute, 60 minutes per hour, 24 hours per day).\[t_{1/2} = \frac{3.163 \times 10^5}{86400} \approx 3.66 \text{ days}\]
04
Final Calculation and Solution
The half-life of the isotope \({ }_{88}^{224}\) Ra is calculated to be approximately 3.66 days.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-life Calculation
A core concept in radioactive decay is calculating the half-life of an isotope, which is crucial for understanding the time it takes for half of a radioactive substance to transform. The half-life is symbolized as \( t_{1/2} \) and can be determined using the formula:
To calculate the half-life in seconds, you plug the decay constant given into the formula. For example, with a decay constant of \( 2.19 \times 10^{-6} \) s\(^{-1}\), inputting this value provides the half-life in seconds.
Finally, converting seconds to more manageable units like days helps illustrate how quickly or slowly a substance decays, particularly if it involves human timescales.
- \( t_{1/2} = \frac{\ln(2)}{\lambda} \)
To calculate the half-life in seconds, you plug the decay constant given into the formula. For example, with a decay constant of \( 2.19 \times 10^{-6} \) s\(^{-1}\), inputting this value provides the half-life in seconds.
Finally, converting seconds to more manageable units like days helps illustrate how quickly or slowly a substance decays, particularly if it involves human timescales.
Decay Constant
The decay constant, represented as \( \lambda \), is a vital parameter in the mathematics of radioactive decay. It reveals the probability per unit time that a nucleus will decay. A higher decay constant means the isotope decays more quickly. The decay constant is measured in units of inverse time, such as s\(^{-1}\).
Here's how it's used:
Here's how it's used:
- Linked to half-life by the formula \( t_{1/2} = \frac{\ln(2)}{\lambda} \)
- Provides insight into the stability of the isotope, with larger constants indicating rapid decay.
Exponential Decay
Exponential decay is a mathematical concept used to describe processes where quantities decrease at a rate proportional to their current value. In the context of radioactivity, it is used to illustrate how radioactive substances reduce over time. This process can be expressed with the equation:
- \( N(t) = N_0 e^{-\lambda t} \)
- \( N(t) \) is the quantity of substance that still remains after time \( t \)
- \( N_0 \) is the initial quantity
- \( e \) is the base of the natural logarithm
- \( \lambda \) is the decay constant