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Doubly ionized lithium \(\mathrm{Li}^{2+}(Z=3)\) and triply ionized beryllium \(\mathrm{Be}^{3+}(Z=4)\) each emit a line spectrum. For a certain series of lines in the lithium spectrum, the shortest wavelength is \(40.5 \mathrm{~nm}\). For the same series of lines in the beryllium spectrum, what is the shortest wavelength?

Short Answer

Expert verified
The shortest wavelength for beryllium is approximately 22.8 nm.

Step by step solution

01

Understanding the Rydberg Formula

The Rydberg formula is used to calculate the wavelengths of spectral lines in many chemical elements: \[ \frac{1}{\lambda} = R Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where \( \lambda \) is the wavelength, \( R \) is the Rydberg constant (approximately \( 1.097 \times 10^7 \, \mathrm{m^{-1}} \)), \( Z \) is the atomic number, and \( n_1 \) and \( n_2 \) are the principal quantum numbers with \( n_2 > n_1 \). The shortest wavelength occurs when \( n_2 \to \infty \).
02

Calculate for Lithium

For doubly ionized lithium \( \mathrm{Li}^{2+} \), the atomic number \( Z = 3 \), and the shortest wavelength is given as \( 40.5 \) nm. Using the Rydberg formula: \[ \frac{1}{\lambda_{\text{Li}}} = R \times 3^2 \times \frac{1}{n_1^2} \] We need this for later comparison with beryllium.
03

Determine Shortest Wavelength for Beryllium

For triply ionized beryllium \( \mathrm{Be}^{3+} \), with \( Z = 4 \), and solving the Rydberg formula for shortest wavelength: \[ \frac{1}{\lambda_{\text{Be}}} = R \times 4^2 \times \frac{1}{n_1^2} \] To compare the two, keep in mind \( R \) and \( n_1 \) are constant, so: \[ \frac{1}{\lambda_{\text{Li}}} / \frac{1}{\lambda_{\text{Be}}} = \left( \frac{3}{4} \right)^2 \] since only \( Z \/ \) differs.
04

Solving for Beryllium's Wavelength

Using the ratio, rearrange to find \( \lambda_{\text{Be}} \): \[ \lambda_{\text{Be}} = \lambda_{\text{Li}} \times \left( \frac{3}{4} \right)^2 \] Substituting \( \lambda_{\text{Li}} = 40.5 \, \mathrm{nm} \): \[ \lambda_{\text{Be}} = 40.5 \, \mathrm{nm} \times \left( \frac{9}{16} \right) = 22.78125 \, \mathrm{nm} \] Therefore, the shortest wavelength in the beryllium spectrum is approximately \( 22.8 \, \mathrm{nm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spectral Lines
Spectral lines are unique signatures of elements and ions, appearing when atoms emit or absorb light at specific wavelengths. These lines are an essential tool in spectroscopy, allowing scientists to identify the composition of different materials, including distant stars and galaxies. They originate from the transitions of electrons between different energy levels within an atom. When an electron moves to a lower energy level, it releases energy in the form of light, resulting in an emission spectral line. Conversely, when an electron absorbs energy to jump to a higher energy level, an absorption line is formed.

Each element has a unique pattern of spectral lines, much like a fingerprint. This uniqueness is due to the difference in electron arrangements and nuclear charge among elements. The Rydberg formula is particularly crucial in predicting these spectral lines' wavelengths in hydrogen-like ions, which helps in identifying various ionized states like doubly ionized lithium (\( \mathrm{Li}^{2+} \)) and triply ionized beryllium (\( \mathrm{Be}^{3+} \)). This understanding aids in determining different characteristics of the atoms involved, such as their ionization states and energy transitions.
Atomic Number
The atomic number \( Z \) of an element is fundamental, representing the number of protons in the nucleus of an atom. It not only defines the identity of the element but also significantly influences the element's placement in the periodic table. The Rydberg formula incorporates the atomic number as a critical factor, as it directly impacts the energy levels and, consequently, the spectral lines of ions.
  • For example, in the case of doubly ionized lithium \( \mathrm{Li}^{2+} \), the atomic number \( Z \) is 3.
  • On the other hand, for triply ionized beryllium \( \mathrm{Be}^{3+} \), the atomic number \( Z \) is 4.
The higher the atomic number, the greater the nuclear charge, which affects how tightly electrons are bound to the nucleus. This results in changes in the wavelengths of the spectral lines. Specifically, as seen with the Rydberg formula \( \frac{1}{\lambda} = R Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \), the square of the atomic number \( Z^2 \) has a direct influence on the wavelength \( \lambda \). Consequently, it illustrates why triply ionized beryllium exhibits a shorter wavelength than doubly ionized lithium for the same spectral line series.
Quantum Numbers
Quantum numbers are fundamental in quantum mechanics, serving to specify the properties of atomic orbitals and the properties of electrons in these orbitals. They play a crucial role in determining the energy levels of electrons, which in turn affect the spectral lines of an element.

The principal quantum number \( n \) is particularly significant among the four quantum numbers. It denotes the main energy level occupied by an electron and essentially quantifies the electron's energy. In the calculation of spectral lines using the Rydberg formula, two principal quantum numbers \( n_1 \) and \( n_2 \) are involved:
  • \( n_1 \) is the lower energy level, to which an electron transitions.
  • \( n_2 \), would theoretically go to infinity, signifying the highest energy state possible.
As \( n_2 \rightarrow \infty \), it simplifies the Rydberg equation and allows for the determination of shortest wavelengths for given series of spectral lines. Understanding these concepts allows us to predict and calculate the spectral lines, which is essential for applications in fields such as astrophysics, chemistry, and other sciences that require material identification at the atomic level.

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Most popular questions from this chapter

Concept Simulation 30.1 at reviews the concepts on which the solution to this problem depends. The electron in a hydrogen atom is in the first excited state, when the electron acquires an additional \(2.86 \mathrm{eV}\) of energy. What is the quantum number \(n\) of the state into which the electron moves?

A singly ionized helium atom (He \(^{+}\) ) has only one electron in orbit about the nucleus. What is the radius of the ion when it is in the second excited state?

When an electron makes a transition between energy levels of an atom, there are no restrictions on the initial and final values of the principal quantum number \(n\). According to quantum mechanics, however, there is a rule that restricts the initial and final values of the orbital quantum number \(\ell\). This rule is called a selection rule and states that \(\Delta \ell=\pm 1 .\) In other words, when an electron makes a transition between energy levels, the value of \(\ell\) can only increase or decrease by one. The value of \(\ell\) may not remain the same nor increase or decrease by more than one. According to this rule, which of the following energy level transitions are allowed: (a) \(2 \mathrm{~s} \rightarrow 1 \mathrm{~s}\), (b) \(2 \mathrm{p} \rightarrow 1 \mathrm{~s}\), (c) \(4 \mathrm{p} \rightarrow 2 \mathrm{p}\), (d) \(4 \mathrm{~s} \rightarrow 2 \mathrm{p}\), and (e) \(3 \mathrm{~d} \rightarrow 3 \mathrm{~s} ?\)

The Bohr model can be applied to singly ionized helium \(\mathrm{He}^{+}(Z=2)\). Using this model, consider the series of lines that is produced when the electron makes a transition from higher energy levels into the \(n_{\mathrm{f}}=4\) level. Some of the lines in this series lie in the visible region of the spectrum \((380-750 \mathrm{~nm})\). What are the values of \(n_{\mathrm{i}}\) for the energy levels from which the electron makes the transitions corresponding to these lines?

A pulsed laser emits light in a series of short pulses, each having a duration of \(25.0 \mathrm{~ms}\). The average power of each pulse is \(5.00 \mathrm{~mW}\), and the wavelength of the light is \(633 \mathrm{~nm}\). Find (a) the energy of each pulse and (b) the number of photons in each pulse.

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