/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 The nucleus of the hydrogen atom... [FREE SOLUTION] | 91Ó°ÊÓ

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The nucleus of the hydrogen atom has a radius of about \(1 \times 10^{-15} \mathrm{~m} .\) The electron is normally at a distance of about \(5.3 \times 10^{-11} \mathrm{~m}\) from the nucleus. Assuming the hydrogen atom is a sphere with a radius of \(5.3 \times 10^{-11} \mathrm{~m}\) find (a) the volume of the atom, (b) the volume of the nucleus, and (c) the percentage of the volume of the atom that is occupied by the nucleus.

Short Answer

Expert verified
Volume of atom: \(6.24 \times 10^{-31} \text{ m}^3\), volume of the nucleus: \(4.19 \times 10^{-45} \text{ m}^3\), nucleus occupies approximately \(6.71 \times 10^{-13}\%\) of the atom.

Step by step solution

01

Calculate the volume of the hydrogen atom

The atoms are typically modeled as spheres, thus the formula for the volume of a sphere is used: \[ V = \frac{4}{3} \pi r^3 \]Here, the radius \( r \) of the atom is given as \( r = 5.3 \times 10^{-11} \text{ m} \). Plug in this value to calculate the volume:\[ V_{\text{atom}} = \frac{4}{3} \pi (5.3 \times 10^{-11})^3 \]Calculate to find:\[ V_{\text{atom}} \approx 6.24 \times 10^{-31} \text{ m}^3 \]
02

Calculate the volume of the nucleus

Similarly, the nucleus is considered spherical, and we use the same formula for the volume of a sphere:\[ V = \frac{4}{3} \pi r^3 \]The radius \( r \) of the nucleus is \( r = 1 \times 10^{-15} \text{ m} \). Substituting the radius of the nucleus:\[ V_{\text{nucleus}} = \frac{4}{3} \pi (1 \times 10^{-15})^3 \]Calculate to find:\[ V_{\text{nucleus}} \approx 4.19 \times 10^{-45} \text{ m}^3 \]
03

Calculate the percentage of the volume occupied by the nucleus

The percentage of the atom's volume that is occupied by the nucleus can be found by taking the ratio of the nucleus's volume to the atom's volume and multiplying by 100:\[ \text{Percentage} = \left(\frac{V_{\text{nucleus}}}{V_{\text{atom}}}\right) \times 100 \]Substitute the volumes found in Step 1 and Step 2:\[ \text{Percentage} = \left(\frac{4.19 \times 10^{-45}}{6.24 \times 10^{-31}}\right) \times 100 \]Calculate to find:\[ \text{Percentage} \approx 6.71 \times 10^{-13}\% \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Structure
The hydrogen atom, as with all atoms, consists of a nucleus surrounded by electrons. The nucleus is incredibly small, particularly in comparison to the overall size of the atom. This means it makes up only a tiny fraction of the atom's volume, even though it contains the majority of its mass. The structure of atoms has been a crucial area of study in physics and chemistry, helping us to understand how matter forms and interacts.
At the heart of the hydrogen atom is a single proton, which constitutes its nucleus. This proton carries a positive electrical charge. Surrounding the nucleus is a single electron, which carries a negative charge. This electron is usually found in an area around the nucleus known as the electron cloud. The space the electron occupies is vastly larger than the nucleus itself, meaning the atom is predominantly empty space. The behavior and interaction of these subatomic particles define the hydrogen atom's chemical characteristics and interactions.
Volume Calculation
To calculate the volume of spherical objects, such as atoms or nuclei, we use the formula:
  • \( V = \frac{4}{3} \pi r^3 \)
This formula considers the radius of the sphere and gives us the measure of how much space it occupies. For example, when calculating the volume of the hydrogen atom as a whole, we start by using its radius, approximately \( 5.3 \times 10^{-11} \text{m} \). Plugging this value into the formula gives us the atom's volume:
  • \( V_{\text{atom}} \approx 6.24 \times 10^{-31} \text{ m}^3 \)
When calculating for the nucleus, the radius is much smaller, \( 1 \times 10^{-15} \text{ m} \), which when substituted gives:
  • \( V_{\text{nucleus}} \approx 4.19 \times 10^{-45} \text{ m}^3 \)
The vast difference in size highlights how much more space the electron cloud occupies compared to the nucleus. Using these calculations, we also find the percentage of the atom's volume occupied by the nucleus, which is extremely small, indicating the atom's composition being mainly empty space.
Nucleus of Atom
The nucleus of an atom is the core that contains protons and neutrons. In the case of a hydrogen atom, its nucleus is incredibly simple, consisting of just a single proton. This makes hydrogen the simplest chemical element. Despite its small size, the nucleus is dense and carries most of the atom's mass.
In the context of our hydrogen atom, the nucleus’s volume is extremely tiny compared to the atom's overall volume. Even though the radius of the hydrogen atom is around \( 5.3 \times 10^{-11} \text{ m} \), its nucleus is much smaller, around \( 1 \times 10^{-15} \text{ m} \). This means the nucleus occupies a minuscule fraction of the atom's volume. When we calculated using the volume formulas earlier, we found that the nucleus occupies about \( 6.71 \times 10^{-13}\% \) of the atom's total volume. This showcases a fundamental aspect of atomic structure: most of the atom is empty space, with its mass localized in the nucleus. This characteristic is central to understanding the behavior of materials at the atomic level.

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Most popular questions from this chapter

The Bohr model can be applied to singly ionized helium \(\mathrm{He}^{+}(Z=2)\). Using this model, consider the series of lines that is produced when the electron makes a transition from higher energy levels into the \(n_{\mathrm{f}}=4\) level. Some of the lines in this series lie in the visible region of the spectrum \((380-750 \mathrm{~nm})\). What are the values of \(n_{\mathrm{i}}\) for the energy levels from which the electron makes the transitions corresponding to these lines?

The dye laser used in the treatment of the port-wine stain in Figure \(30-30\) (see Section 30.9) has a wavelength of \(585 \mathrm{~nm}\). A carbon dioxide laser produces a wavelength of \(1.06 \times 10^{-5} \mathrm{~m}\). What is the minimum number of photons that the carbon dioxide laser must produce to deliver at least as much or more energy to a target as does a single photon from the dye laser?

A certain species of ionized atoms produces an emission line spectrum according to the Bohr model, but the number of protons \(Z\) in the nucleus is unknown. A group of lines in the spectrum forms a series in which the shortest wavelength is \(22.79 \mathrm{nm}\) and the longest wavelength is \(41.02 \mathrm{nm} .\) Find the next-to-the-longest wavelength in the series of lines.

A hydrogen atom is in its second excited state. Determine, according to quantum mechanics, (a) the total energy (in eV) of the atom, (b) the magnitude of the maximum angular momentum the electron can have in this state, and (c) the maximum value that the \(z\) component \(L_{7}\) of the angular momentum can have.

(a) Derive an expression for the speed of the electron in the \(n\) th Bohr orbit, in terms of \(Z\), \(n,\) and the constants \(k, e,\) and \(h .\) For the hydrogen atom, determine the speed in (b) the \(n=1\) orbit and \((\mathrm{c})\) the \(n=2\) orbit. (d) Generally, when speeds are less than one-tenth the speed of light, the effects of special relativity can be ignored. Are the speeds found in (b) and (c) consistent with ignoring relativistic effects in the Bohr model?

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