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In diving to a depth of \(750 \mathrm{~m}\), an elephant seal also moves \(460 \mathrm{~m}\) due east of his starting point. What is the magnitude of the seal's displacement?

Short Answer

Expert verified
The magnitude of the seal's displacement is approximately 879.88 m.

Step by step solution

01

Understanding Displacement

Displacement is a vector quantity that refers to the change in position of an object. It has both magnitude and direction. When an object moves in two directions, such as vertically and horizontally, the magnitude of its displacement can be found using the Pythagorean theorem.
02

Identify Components

Identify the two components of the elephant seal's movement. One component is vertical, as it dives to a depth of 750 m. The other component is horizontal, moving 460 m due east.
03

Use the Pythagorean Theorem

To find the magnitude of the seal's displacement, apply the Pythagorean theorem for the vertical and horizontal components. The displacement is the hypotenuse of a right triangle formed by these two components: \( d = \sqrt{(750)^2 + (460)^2} \).
04

Calculate the Displacement Magnitude

First, calculate the squares of the individual components: \( 750^2 = 562,500 \) and \( 460^2 = 211,600 \). Then add them: \( 562,500 + 211,600 = 774,100 \). Finally, take the square root of the sum to find the magnitude: \( \sqrt{774,100} \approx 879.88 \).
05

Interpreting the Result

The magnitude of the elephant seal's displacement is approximately 879.88 meters. This represents the direct straight-line distance from its original position to its final position.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Quantity
In physics, a vector quantity is an essential concept to understand motion and forces. Unlike scalar quantities that only have a magnitude, vector quantities have both magnitude and direction. Displacement is a perfect example of a vector quantity. It tells us how far an object has moved and in what direction it has moved from its original position.

To grasp the idea of vector quantities more clearly, consider both the magnitude, which tells us how much or how far, and the direction, which indicates where to or from. This concept is vital in scenarios where an object moves in more than one direction, like the elephant seal that dives and moves east.

When dealing with vector quantities, it's crucial to represent them graphically as arrows. The length of the arrow indicates the magnitude, and the arrowhead points in the direction of the vector. By understanding vector quantities, solving physics problems becomes more intuitive, as it provides a complete picture of the object's motion in space.
Pythagorean Theorem
The Pythagorean theorem is a mathematical tool used to analyze right-angled triangles. It helps determine the length of one side if the other two sides are known. This theorem is particularly useful in physics when dealing with vector quantities in two dimensions.

In the case of the elephant seal, which dives and moves east, its motion forms a right triangle with the ocean floor. The vertical movement represents one leg of the triangle, while the horizontal movement is the other. The displacement is the hypotenuse of this triangle.

The Pythagorean theorem states: for a right triangle, the square of the hypotenuse (\( c \) ) is the sum of the squares of the other two sides (\( a \) and \( b \) ). Mathematically, it can be expressed as:
  • \[ c = \sqrt{a^2 + b^2} \]
For the elephant seal, this means:
  • \[ d = \sqrt{(750)^2 + (460)^2} \]
By utilizing the Pythagorean theorem, the challenge of finding the magnitude of displacement becomes manageable and understandable.
Magnitude of Displacement
The magnitude of displacement is an important concept that refers to the direct, straight-line distance an object moves from its start point to its endpoint. Unlike total distance traveled, displacement considers only the initial and final positions, ignoring the path taken.

For the elephant seal that dove and moved east, its displacement magnitude is calculated using the components of its dive and lateral movement. This approach emphasizes the vector nature of displacement, bringing into account both the eastward and downward paths.

To solve for the magnitude of displacement, first determine the individual movements: diving 750 meters downward and moving 460 meters east. Using the Pythagorean theorem, the calculation becomes:
  • Calculate squares of the components: \(750^2 = 562,500\)
  • \(460^2 = 211,600\)
  • Add them together: \(562,500 + 211,600 = 774,100\)
  • Find the square root: \(\sqrt{774,100} \approx 879.88 \) meters
This result shows how effectively the Pythagorean theorem helps in finding the magnitude of displacement and reinforces understanding of vector analysis in physics.

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Most popular questions from this chapter

The altitude of a hang glider is increasing at a rate of \(6.80 \mathrm{~m} / \mathrm{s}\). At the same time, the shadow of the glider moves along the ground at a speed of \(15.5 \mathrm{~m} / \mathrm{s}\) when the sun is directly overhead. Find the magnitude of the glider's velocity.

(a) A projectile is launched at a speed \(v_{0}\) and at an angle above the horizontal; its initial velocity components are \(v_{0_{x}}\) and \(v_{0_{y}}\). In the absence of air resistance, what is the speed of the projectile at the peak of its trajectory? (b) What is its speed just before it lands at the same vertical level from which it was launched? (c) Consider its speed at a point that is at a vertical level between that in (a) and (b). How does the speed at this point compare with the speeds identified in (a) and (b)? In each case, give your reasoning. A golfer hits a shot to a green that is elevated \(3.0 \mathrm{~m}\) above the point where the ball is struck. The ball leaves the club at a speed of \(14.0 \mathrm{~m} / \mathrm{s}\) at an angle of \(40.0^{\circ}\) above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands. Check to see that your answer is consistent with your answer to part (c) of the Concept Questions.

A car drives straight off the edge of a cliff that is \(54 \mathrm{~m}\) high. The police at the scene of the accident observe that the point of impact is \(130 \mathrm{~m}\) from the base of the cliff. How fast was the car traveling when it went over the cliff?

A speed ramp at an airport is a moving conveyor belt on which you can either stand or walk. It is intended to get you from place to place more quickly. Suppose a speed ramp is \(120 \mathrm{~m}\) long. When you walk at a comfortable speed on the ground, you cover this distance in \(86 \mathrm{~s}\). When you walk on the speed ramp at this same comfortable speed, you cover this distance in 35 s. Determine the speed at which the speed ramp is moving relative to the ground.

A jetliner is moving at a speed of \(245 \mathrm{~m} / \mathrm{s}\). The vertical component of the plane's velocity is \(40.6 \mathrm{~m} / \mathrm{s}\). Determine the magnitude of the horizontal component of the plane's velocity.

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