/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 The minimum uncertainty \(\Delta... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The minimum uncertainty \(\Delta y\) in the position \(y\) of a particle is equal to its de Broglie wavelength. Determine the minimum uncertainty in the speed of the particle, where this minimum uncertainty \(\Delta v_{y}\) is expressed as a percentage of the particle's speed \(v_{y}\left(\right.\) Percentage \(\left.=\frac{\Delta v_{y}}{v_{y}} \times 100 \%\right)\). Assume that relativistic effects can be ignored.

Short Answer

Expert verified
The minimum uncertainty in speed is approximately 7.96% of the particle's speed.

Step by step solution

01

Understand the Given Information

We know that the minimum uncertainty \( \Delta y \) in the position \( y \) of a particle is equal to its de Broglie wavelength \( \lambda \). We need to find the minimum uncertainty in the speed \( \Delta v_{y} \) as a percentage of the speed \( v_{y} \). We can ignore relativistic effects, implying that the classical physics principles can be applied here.
02

Express de Broglie Wavelength

The de Broglie wavelength \( \lambda \) is given by \( \lambda = \frac{h}{mv_{y}} \), where \( h \) is Planck’s constant, \( m \) is the mass of the particle, and \( v_{y} \) is the speed of the particle.
03

Relate Uncertainty in Position to de Broglie Wavelength

Since \( \Delta y = \lambda \), we have \( \Delta y = \frac{h}{mv_{y}} \).
04

Apply Heisenberg's Uncertainty Principle

According to Heisenberg's uncertainty principle, the uncertainty in position \( \Delta y \) and uncertainty in momentum \( \Delta p_{y} \) can be expressed as \( \Delta y \Delta p_{y} \geq \frac{h}{4\pi} \).
05

Relate Uncertainty in Momentum to Speed

The uncertainty in momentum \( \Delta p_{y} \) is \( m \Delta v_{y} \), where \( m \) is the mass of the particle. Therefore, \( \Delta y \times m \Delta v_{y} \geq \frac{h}{4\pi} \).
06

Substitute \( \Delta y \) and Solve for \( \Delta v_{y} \)

Substitute \( \Delta y = \frac{h}{mv_{y}} \) into the inequality: \[ \frac{h}{mv_{y}} \times m\Delta v_{y} \geq \frac{h}{4\pi} \] \[ \Delta v_{y} \geq \frac{h}{4\pi} \times \frac{1}{\frac{h}{mv_{y}}} \] \[ \Delta v_{y} \geq \frac{v_{y}}{4\pi} \].
07

Calculate the Percentage Uncertainty in Speed

The percentage uncertainty in speed is given by \( \frac{\Delta v_{y}}{v_{y}} \times 100\% \). Substitute \( \Delta v_{y} \geq \frac{v_{y}}{4\pi} \):\[ \text{Percentage} \geq \frac{v_{y}/4\pi}{v_{y}} \times 100\% \].\[ \text{Percentage} \geq \frac{1}{4\pi} \times 100\% \].
08

Simplify to Find Numeric Answer

Calculate \( \frac{1}{4\pi} \times 100\% \): \[ \frac{1}{4\pi} \approx 0.0796 \] so the percentage \( \approx 7.96\% \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

de Broglie Wavelength
The concept of de Broglie Wavelength links wave and particle behaviors. It is used to determine the wavelength of a particle, such as an electron, that is moving. This relationship is defined by the equation \[\lambda = \frac{h}{mv_y}\]where
  • \( \lambda \) is the de Broglie wavelength,
  • \( h \) is Planck’s constant (\( 6.626 \times 10^{-34} \) Js),
  • \( m \) is the mass of the particle, and
  • \( v_y \) is the speed of the particle in the y-direction.
The important point here is that this wavelength is typically significant at the atomic and subatomic levels, like electrons.
It implies that every moving particle or object has a wavelength associated with it. When the speed or mass of a particle changes, so does its de Broglie wavelength. This calculation is more prominent for smaller particles, as their wavelengths become appreciably measurable.
For real-world, macroscopic objects, their calculated wavelengths are negligibly small and often ignored.
Uncertainty in Speed
In the realm of quantum physics, determining the exact speed of a particle is not always possible. This stems from the principle known as Heisenberg's Uncertainty Principle. According to this principle, there is a limit to how precisely we can know both the position and speed (or momentum) of a particle at any given time.
When the uncertainty in the position \(\Delta y\) is equal to the de Broglie wavelength, we can establish that:
  • Uncertainty in momentum \(\Delta p_y = m \Delta v_y\), where \(m\) is the mass and \(\Delta v_y\) is the uncertainty in velocity.
  • The Heisenberg relation \(\Delta y \Delta p_y \geq \frac{h}{4\pi}\).
Given \(\Delta y = \frac{h}{mv_y}\), we derive \(\Delta v_y \geq \frac{v_y}{4\pi}\), showing the inherent limitation imposed by quantifying both position and speed.
Applying this, we find that the minimum uncertainty in speed is roughly 7.96% of the particle's speed. This percentage arises due to the oscillations that make it impossible to pinpoint both properties precisely.
Classical Physics Assumptions
In classical physics, assumptions often do not account for quantum behaviors, yet they provide a practical framework for understanding general mechanics. The exercise assumes that relativistic effects, those considered at speeds approaching the speed of light, can be ignored. This means that classical physics principles like Newton's laws and concepts of momentum are applicable.
In this context:
  • We use non-relativistic equations: Velocity changes, as well as position, are not distorted by high-speed relativity effects.
  • Classical physics assumes continuity and determinism. Outcomes can be precisely forecasted if complete initial conditions are known.
When assessing the uncertainty in speed, classical assumptions allow for straightforward generalization without considering the complex relativistic effects.
This can help bridge understanding from classical to quantum mechanics, highlighting the instances where classical physics begins to fail and quantum mechanics becomes a necessity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The de Broglie wavelength of a proton in a particle accelerator is \(1.30 \times 10^{-14} \mathrm{~m}\) Determine the kinetic energy (in joules) of the proton.

In the lungs there are tiny sacs of air, which are called alveoli. The average diameter of one of these sacs is \(0.25 \mathrm{~mm}\). Consider an oxygen molecule (mass \(=5.3 \times 10^{-26} \mathrm{~kg}\) ) trapped within a sac. What is the minimum uncertainty in the velocity of this oxygen molecule?

Particle \(\mathrm{A}\) is at rest, and particle B collides head-on with it. The collision is completely inelastic, so the two particles stick together and move off after the collision with a common velocity. The masses of the particles are different, and no external forces act on them. (a) What is the total linear momentum of the two-particle system before the collision? Express your answer in terms of the masses and the initial velocities, (b) What is the total linear momentum of the system after the collision? Express your answer in terms of the masses and the final velocity of the particle. (c) No external forces act on the two-particle system during the collision. What does this fact tell you about the total linear momentum of the system? (d) How is the de Broglie wavelength of a particle related to the magnitude of its momentum? The de Broglie wavelength of particle \(\mathrm{B}\) before the collision is \(2.0 \times 10^{-34} \mathrm{~m} .\) What is the de Broglie wavelength of the object that moves off after the collision?

Light is shining perpendicularly on the surface of the earth with an intensity of \(680 \mathrm{~W} / \mathrm{m}^{2}\) Assuming all the photons in the light have the same wavelength (in vacuum) of \(730 \mathrm{nm}\), determine the number of photons per second per square meter that reach the earth.

Concept Question Particle \(\mathrm{A}\) is at rest, and particle \(\mathrm{B}\) collides head-on with it. The collision is completely inelastic, so the two particles stick together and move off after the collision with a common velocity. The masses of the particles are different, and no external forces act on them. (a) What is the total linear momentum of the two-particle system before the collision? Express your answer in terms of the masses and the initial velocities, (b) What is the total linear momentum of the system after the collision? Express your answer in terms of the masses and the final velocity of the particle. (c) No external forces act on the two-particle system during the collision. What does this fact tell you about the total linear momentum of the system? (d) How is the de Broglie wavelength of a particle related to the magnitude of its momentum? Problem The de Broglie wavelength of particle \(\mathrm{B}\) before the collision is \(2.0 \times 10^{-34} \mathrm{~m}\). What is the de Broglie wavelength of the object that moves off after the collision?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.