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Four kilograms of water are heated from \(20.0^{\circ} \mathrm{C}\) to \(60.0{ }^{\circ} \mathrm{C} .\) (a) How much heat is required to produce this change in temperature? [The specific heat capacity of water is \(\left.4186 \mathrm{~J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right) .\right]\) (b) By how much does the mass of the water increase?

Short Answer

Expert verified
(a) 669,760 J of heat. (b) No mass increase.

Step by step solution

01

Understand the Given Information

We have 4 kg of water being heated from an initial temperature of \(20.0^{\circ} \mathrm{C}\) to a final temperature of \(60.0^{\circ} \mathrm{C}\). The specific heat capacity provided is \(4186 \, \mathrm{J} / (\mathrm{kg} \cdot \mathrm{C}^{\circ})\).
02

Use the Formula for Heat Energy

The heat energy required \(Q\) can be calculated using the formula \(Q = mc\Delta T\), where \(m\) is the mass, \(c\) is the specific heat capacity, and \(\Delta T\) is the change in temperature. Here, \(m = 4 \, \mathrm{kg}\), \(c = 4186 \, \mathrm{J} / (\mathrm{kg} \cdot \mathrm{C}^{\circ})\), and \(\Delta T = 60.0^{\circ} \mathrm{C} - 20.0^{\circ} \mathrm{C} = 40.0^{\circ} \mathrm{C}\).
03

Calculate the Heat Energy Required (Part a)

Plug the values into the formula: \[Q = 4 \, \mathrm{kg} \times 4186 \, \mathrm{J} / (\mathrm{kg} \cdot \mathrm{C}^{\circ}) \times 40.0^{\circ} \mathrm{C} = 669,760 \, \mathrm{J}\]Thus, 669,760 joules of heat are required to heat the water.
04

Understand Mass Change in Classical Physics (Part b)

In classical physics, heating water does not change its mass. Mass change due to energy is only considered in relativistic physics (E=mc²), and is negligible here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Energy Calculation
When you want to heat water or any substance, calculating the amount of heat energy required is key. This is where the formula for heat energy comes into play:
  • The formula is: \( Q = mc\Delta T \)
  • Where:
    • \( Q \) is the heat energy in joules (J).
    • \( m \) is the mass of the substance (in kilograms, kg).
    • \( c \) is the specific heat capacity, which is a constant that tells you how much energy is needed to raise the temperature of 1 kg of the substance by 1 degree Celsius (C°).
    • \( \Delta T \) is the change in temperature, which is the final temperature minus the initial temperature.
Let's say you're given 4 kg of water, the formula helps us find out that 669,760 J are required to heat the water from 20°C to 60°C.
Each component of the equation plays an important part in final calculation and the specific heat capacity of water, which is 4186 J/(kg·C°), is crucial in this equation.
Always remember to plug in the units correctly to avoid errors in the calculation.
Temperature Change
Understanding the concept of temperature change is essential when dealing with heat-related processes. Temperature change is represented by \( \Delta T \).
It’s calculated by subtracting the initial temperature from the final temperature. For example:
  • If you have water heated from \(20^{\circ}C\) to \(60^{\circ}C\), the temperature change \( \Delta T \) would be \( 60^{\circ}C - 20^{\circ}C = 40^{\circ}C \).
This change in temperature tells us how much the substance's temperature has risen or fallen.
In real-life applications, knowing \( \Delta T \) helps in calculating not only how much energy is needed, but also in assessing the effectiveness of heating and cooling systems.
As changes in temperature directly relate to energy changes, this concept is pivotal in both academic problems and practical situations related to thermal energy management.
Mass of Water
The mass of water is a straightforward but important concept in thermal physics and various chemistry calculations.
In the realm of classical physics, which excludes relativistic considerations, the mass of water does not change due to heating or cooling.
In our exercise, for instance, the mass of the water remains at 4 kg before and after heating from \(20^{\circ}C\) to \(60^{\circ}C\).

Here are some points to keep in mind:
  • In practical scenarios, mass is conserved despite changes to the physical state of a material.
  • Energy changes might cause minor mass changes only when considering theories like relativity (E=mc²), which are usually insignificant in common classroom or laboratory settings.
So, while the energy input affects the state or temperature of the water, the mass is a fixed quantity in such exercises. Paying attention to mass ensures precision in chemical reactions, heating calculations, and resource management.

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Most popular questions from this chapter

Review Conceptual Example 11 as an aid in answering this question. A person is approaching you in a truck that is traveling very close to the speed of light. This person throws a baseball toward you. Relative to the truck, the ball is thrown with a speed nearly equal to the speed of light, so the person on the truck sees the baseball move away from the truck at a very high speed. Yet you see the baseball move away from the truck very slowly. Why? Use the velocity- addition formula to guide your thinking.

The crew of a rocket that is moving away from the earth launches an escape pod, which they measure to be \(45 \mathrm{~m}\) long. The pod is launched toward the earth with a speed of \(0.55 c\) relative to the rocket. After the launch, the rocket's speed relative to the earth is \(0.75 c\). What is the length of the escape pod as determined by an observer on earth?

Suppose one gallon of gasoline produces \(1.1 \times 10^{8} \mathrm{~J}\) of energy, and this energy is sufficient to operate a car for twenty miles. An as pirin tablet has a mass of \(325 \mathrm{mg}\). If the aspirin could be converted completely into thermal energy, how many miles could the car go on a single tablet?

Interactive LearningWare 28.1 at reviews the concepts that play roles in this problem. The distance from earth to the center of our galaxy is about 23000 ly \(\left(11 \mathrm{y}=1\right.\) light-year \(\left.=9.47 \times 10^{15} \mathrm{~m}\right),\) as measured by an earth-based observer. \(\mathrm{A}\) spaceship is to make this journey at a speed of \(0.9990 c\). According to a clock on board the spaceship, how long will it take to make the trip? Express your answer in years \(\left(1 \mathrm{yr}=3.16 \times 10^{7} \mathrm{~s}\right)\)

A rectangle has the dimensions of \(3.0 \mathrm{~m} \times 2.0 \mathrm{~m}\) when viewed by someone at rest with respect to it. When you move past the rectangle along one of its sides, the rectangle looks like a square. What dimensions do you observe when you move at the same speed along the adjacent side of the rectangle?

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