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A microscope for viewing blood cells has an objective with a focal length of 0.50 \(\mathrm{cm}\) and an eyepiece with a focal length of \(2.5 \mathrm{~cm} .\) The distance between the objective and eyepiece is \(14.0 \mathrm{~cm} .\) If a blood cell subtends an angle of \(2.1 \times 10^{-5}\) rad when viewed with the naked eye at a near point of \(25.0 \mathrm{~cm}\), what angle (magnitude only) does it subtend when viewed through the microscope?

Short Answer

Expert verified
The angle is approximately \(5.88 \times 10^{-3}\) rad.

Step by step solution

01

Identify the Formula for Angular Magnification

To determine the angle subtended by the object when viewed through the microscope, we first need to identify the formula for angular magnification of a microscope, which is given by \(M = \frac{d}{f_e} \cdot \frac{L}{f_o}\), where \(d\) is the near point (in this context, \(25\, \mathrm{cm}\)), \(f_e\) is the focal length of the eyepiece, \(L\) is the tube length (distance between the objective and eyepiece), and \(f_o\) is the focal length of the objective.
02

Substitute Known Values into the Formula

Substituting the given values into the formula: \(d = 25\, \mathrm{cm}\), \(f_e = 2.5\, \mathrm{cm}\), \(L = 14.0\, \mathrm{cm}\), and \(f_o = 0.5\, \mathrm{cm}\). Thus, \(M = \frac{25}{2.5} \cdot \frac{14}{0.5}\).
03

Calculate the Angular Magnification

First, calculate \(\frac{25}{2.5} = 10\) and \(\frac{14}{0.5} = 28\). Now multiply these two results: \(10 \times 28 = 280\). Therefore, the angular magnification \(M\) is \(280\).
04

Calculate the New Subtended Angle

The angle subtended when viewed through the microscope, \(\theta_{\text{microscope}}\), is the product of the magnification \(M\) and the naked eye angle \(\theta_{\text{naked eye}} = 2.1 \times 10^{-5} \text{ rad}\). Therefore, \(\theta_{\text{microscope}} = 280 \times 2.1 \times 10^{-5}\).
05

Final Computation

Compute the final angle: \(280 \times 2.1 \times 10^{-5} = 5.88 \times 10^{-3} \text{ rad}\). This is the angle subtended by the blood cell when viewed through the microscope.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Microscope Optics
Understanding microscope optics is key to grasping how these powerful magnifying devices work. At the core of a microscope's design are two lenses: the objective lens and the eyepiece. These lenses work together to magnify tiny objects such as blood cells.
The objective lens, located very close to the specimen, initially magnifies the image. This image is then further magnified by the eyepiece, which presents the enlarged image to the viewer's eye. This dual-lens system results in a highly magnified image that can show details not visible to the naked eye.
Key Points:
  • The objective lens is closer to the specimen and has a shorter focal length.
  • The eyepiece lens, also known as the ocular lens, is used to view the enlarged image.
Together, these components allow the microscope to achieve the high levels of magnification needed for detailed observation.
Focal Length
Focal length is an essential concept in microscope optics and plays a crucial role in how microscopes function. It's the distance from the lens to the point where light rays converge to form a sharp image. With microscopes, both the objective and eyepiece lenses have specific focal lengths that determine the device's magnification power.
The shorter the focal length of the objective lens, the larger the initial magnification. Similarly, the focal length of the eyepiece affects the total magnification you observe. In practice, short focal lengths in lenses lead to powerful magnification capabilities.
Remember:
  • Objective lenses often have very short focal lengths to achieve high initial magnification.
  • Eyepiece lenses contribute to the total magnification and usually have a longer focal length than the objective.
Subtended Angle
The subtended angle is the angle formed between the lines of sight from your eyes to the edges of the object being viewed. In this context, it's the angle measured when looking at an object like a blood cell through a microscope.
When looking at small objects through a microscope, the goal is often to increase this subtended angle so that the object appears larger and more detailed. This is achieved through the magnifying power of the microscope.
Key Details:
  • A larger subtended angle results in a magnified view of the object.
  • Microscopes are designed to maximize the subtended angle for viewing tiny specimens in detail.
Naked Eye Observation
Naked eye observation refers to the process of viewing objects without any magnification aid like a microscope. In such observations, the subtended angle is naturally limited by the distance and size of the object.
Our eyes have a near point typically around 25 centimeters, which is the closest an object can be while still being in focus for most people. This near point sets the benchmark for comparing magnified views with naked eye observation.
Important Points:
  • The naked eye observes smaller subtended angles compared to what is seen through a microscope.
  • The near point of 25 cm is often used in calculations to understand how microscopes will transform observations.
Tube Length
The tube length of a microscope is the distance between the objective lens and the eyepiece lens. This measurement is crucial because it affects how significantly the image is magnified.
In the given exercise, the tube length was specified as 14.0 cm. This length influences the angular magnification of the microscope. The tube length, along with the focal lengths of the lenses, determines the clarity and size of the image.
Key Considerations:
  • A longer tube length can increase magnification, but it may also require adjustments to maintain image focus.
  • The tube length is integral in the formula for calculating angular magnification.
Understanding tube length and its role helps in making precise adjustments to obtain clearer images through a microscope.

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Most popular questions from this chapter

Mars subtends an angle of \(8.0 \times 10^{-5}\) rad at the unaided eye. An astronomical telescope has an eyepiece with a focal length of \(0.032 \mathrm{~m}\). When Mars is viewed using this telescope, it subtends an angle of \(2.8 \times 10^{-3}\) rad. Find the focal length of the telescope's objective lens.

A ray of light impinges from air onto a block of ice \((n=1.309)\) at a \(60.0^{\circ}\) angle of incidence. Assuming that this angle remains the same, find the difference \(\theta_{2, \text { ice }}-\theta_{2, \text { water }}\) water in the angles of refraction when the ice turns to water \((n=1.333)\).

The back wall of a home aquarium is a mirror that is a distance \(L\) away from the front wall. The walls of the tank are negligibly thin. A fish, swimming midway between the front and back walls, is being viewed by a person looking through the front wall. (a) Does the fish appear to be at a distance greater than, less than, or equal to \(\frac{1}{2} L\) from the front wall? (b) The mirror forms an image of the fish. How far from the front wall is this image located? Express your answer in terms of \(L\). (c) Assume that your answer to Question (b) is a distance \(D\). Does the image of the fish appear to be at a distance greater than, less than, or equal to \(D\) from the front wall? (d) Could the image of the fish appear to be in front of the mirror if the index of refraction of water were different than it actually is, and, if so, would the index of refraction have to be greater than or less than its actual value? Explain each of your answers. The distance between the back and front walls of the aquarium is \(40.0 \mathrm{~cm} .\) (a) Calculate the apparent distance between the fish and the front wall. (b) Calculate the apparent distance between the image of the fish and the front wall. Verify that your answers are consistent with your answers to the Concept Questions.

Bill is farsighted and has a near point located \(125 \mathrm{~cm}\) from his eyes. Anne is also farsighted, but her near point is \(75.0 \mathrm{~cm}\) from her eyes. Both have glasses that correct their vision to a normal near point \((25.0 \mathrm{~cm}\) from the eyes), and both wear the glasses 2.0 \(\mathrm{cm}\) from the eyes. Relative to the eyes, what is the closest object that can be seen clearly (a) by Anne when she wears Bill's glasses and (b) by Bill when he wears Anne's glasses?

A nearsighted person wears contacts to correct for a far point that is only \(3.62 \mathrm{~m}\) from his eyes. The near point of his unaided eyes is \(25.0 \mathrm{~cm}\) from his eyes. If he does not remove the lenses when reading, how close can he hold a book and see it clearly?

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