/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A laser emits a narrow beam of l... [FREE SOLUTION] | 91Ó°ÊÓ

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A laser emits a narrow beam of light. The radius of the beam is \(1.0 \times 10^{-3} \mathrm{~m}\), and the power is \(1.2 \times 10^{-3} \mathrm{~W}\). What is the intensity of the laser beam?

Short Answer

Expert verified
The intensity of the laser beam is approximately 382 W/m².

Step by step solution

01

Understand Intensity Formula

The intensity of a beam of light is defined as the power per unit area. The formula for intensity \( I \) is given by \( I = \frac{P}{A} \) where \( P \) is the power of the laser, and \( A \) is the cross-sectional area of the beam.
02

Calculate the Area of the Beam

The beam has a circular cross-section, so we use the formula for the area of a circle: \( A = \pi r^2 \). The radius \( r \) given is \( 1.0 \times 10^{-3} \) m. Substituting the value of \( r \), we get:\[ A = \pi (1.0 \times 10^{-3})^2 = \pi \times 1.0 \times 10^{-6} = 3.14 \times 10^{-6} \text{ m}^2 \].
03

Calculate the Intensity

Now, substitute the values for power \( P = 1.2 \times 10^{-3} \) W and area \( A = 3.14 \times 10^{-6} \text{ m}^2 \) into the intensity formula:\[ I = \frac{1.2 \times 10^{-3}}{3.14 \times 10^{-6}} \approx 382 \text{ W/m}^2 \].
04

Conclusion

The intensity of the laser beam, which measures how much power is distributed over the area of the beam, is approximately \( 382 \text{ W/m}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power of Laser
The power of a laser represents the rate at which energy is emitted by the laser in the form of light. Power is measured in watts (W) and can be thought of as the total amount of energy transferred per second. In the context of lasers, understanding the power allows us to determine how much energy the beam is delivering over time. For example, in our exercise, the laser has a power of \(1.2 \times 10^{-3}\) W, indicating a relatively low-power beam. This is typical of many laser applications where precision is more critical than raw power.
Area of Beam
When discussing laser beams, the area of the beam pertains to the cross-sectional area through which the beam travels. This is crucial since it helps determine how the power is distributed across the space the beam covers. The beam in our exercise is given a circular cross-section, so we use the formula for the area of a circle, \( A = \pi r^2 \).

This formula requires knowing the radius of the circle, which is provided as \(1.0 \times 10^{-3}\) m. Plugging this into our formula, we calculate \( A = \pi (1.0 \times 10^{-3})^2 = 3.14 \times 10^{-6} \text{ m}^2 \). This small area indicates a tightly focused beam, a common feature of laser technology.
Intensity Formula
The intensity formula is a fundamental equation used to calculate how much power a beam of light carries per unit area. It's given by the formula \( I = \frac{P}{A} \), where \( I \) stands for intensity, \( P \) is the power of the laser, and \( A \) is the area over which the power is spread.
  • This formula helps in understanding how densely packed the energy of the beam is.
  • Intensity is measured in watts per square meter (W/m²), indicating how much power is hitting each square meter of the area.


By using this formula, we can gain insights into the strength of the laser's effect on different materials or surfaces it encounters.
Calculating Intensity
Calculating the intensity of a laser beam involves using the intensity formula discussed earlier. Here, the power of the laser (\( P = 1.2 \times 10^{-3} \) W) and the area of the beam (\( A = 3.14 \times 10^{-6} \text{ m}^2 \)) are substituted into the formula.

These values result in: \[ I = \frac{1.2 \times 10^{-3}}{3.14 \times 10^{-6}} \approx 382 \text{ W/m}^2 \]. This calculation shows how efficiently the laser's power is concentrated in the beam's cross-section. Calculating intensity is vital for applications requiring precise power levels, such as in optical fiber communications or laser cutting technologies. By knowing the intensity, you can predict how the laser will interact with materials and adjust accordingly.

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Most popular questions from this chapter

Equation \(16.3, y=A \sin (2 \pi f t-2 \pi x / \lambda),\) gives the mathematical representation of a wave oscillating in the \(y\) direction and traveling in the positive \(x\) direction. Let \(y\) in this equation equal the electric field of an electromagnetic wave traveling in a vacuum. The maximum electric field is \(A=156 \mathrm{~N} / \mathrm{C},\) and the frequency is \(f=1.50 \times 10^{8} \mathrm{~Hz} .\) Plot a graph of the electric field strength versus position, using for \(x\) the following values: 0 , \(0.50,1.00,1.50,\) and \(2.00 \mathrm{~m} .\) Plot this graph for \((\) a) a time \(t=0 \mathrm{~s}\) and \((\mathrm{b})\) a time \(t\) that is one-fourth of the wave's period.

The drawing shows light incident on a polarizer whose transmission axis is parallel to the \(z\) axis. The polarizer is rotated clockwise through an angle \(\alpha\) between 0 and \(90^{\circ}\). While the polarizer is being rotated, does the intensity of the transmitted light increase, decrease, or remain the same if the incident light is (a) unpolarized, (b) polarized parallel to the \(z\) axis, and (c) polarized parallel to the \(y\) axis? Provide a reason for each of your answers.

A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of \(E_{\mathrm{rms}}=2.0 \times 10^{9} \mathrm{~N} / \mathrm{C} .\) Find the average power of each pulse that passes through a \(1.6 \times 10^{-5}-\mathrm{m}^{2}\) surface that is perpendicular to the laser beam.

Suppose that the transmission axis of the first analyzer is rotated \(27^{\circ}\) relative to the transmission axis of the polarizer, and that the transmission axis of each additional analyzer is rotated \(27^{\circ}\) relative to the transmission axis of the previous one. What is the minimum number of analyzers needed for the light reaching the photocell to have an intensity that is reduced by at least a factor of 100 relative to that striking the first analyzer?

In astronomy, distances are often expressed in light-years. One light-year is the distance traveled by light in one year. The distance to Alpha Centauri, the closest star other than our own sun that can be seen by the naked eye, is 4.3 light-years. Express this distance in meters.

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