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The reactance of a capacitor is \(68 \Omega\) when the ac frequency is \(460 \mathrm{~Hz}\). What is the reactance when the frequency is \(870 \mathrm{~Hz} ?\)

Short Answer

Expert verified
The reactance at 870 Hz is approximately 35.95 Ω.

Step by step solution

01

Understanding Capacitive Reactance Formula

The reactance of a capacitor is given by the formula \( X_c = \frac{1}{2\pi f C} \), where \( X_c \) is the capacitive reactance, \( f \) is the frequency, and \( C \) is the capacitance. We know \( X_c \) at a specific frequency and want to find it at another frequency.
02

Express Capacitive Reactance Ratio

We can relate the change in reactance to the change in frequency as \( \frac{X_{c1}}{X_{c2}} = \frac{f_2}{f_1} \), where \( X_{c1} \) is the reactance at \( f_1 \) and \( X_{c2} \) is the reactance at \( f_2 \). This comes from rearranging the formula for reactance.
03

Substitute Known Values for Ratio

Using the values provided: \( X_{c1} = 68 \Omega \), \( f_1 = 460 \) Hz, and \( f_2 = 870 \) Hz. Substituting into the ratio gives \( \frac{68}{X_{c2}} = \frac{870}{460} \).
04

Solve for Unknown Reactance

First, calculate the frequency ratio: \( \frac{870}{460} \approx 1.891 \). Then rearrange the equation to find \( X_{c2} \): \( X_{c2} = \frac{68}{1.891} \). Calculating this gives \( X_{c2} \approx 35.95 \Omega \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capacitance
Capacitance is a fundamental concept when dealing with AC circuits. It refers to a capacitor's ability to store electrical energy in the form of an electric field. Capacitors can be thought of as small batteries that charge and discharge rapidly. They are usually made of two conductive plates separated by an insulating material, known as the dielectric. When a voltage is applied across the plates, an electric field develops, with energy stored within the field.

In the context of AC circuits, capacitance doesn't just store energy but also impacts current flow. The measure of this ability is expressed in farads (F). When dealing with AC circuits, capacitance plays a pivotal role in determining the behavior of the circuit, especially how it interacts with alternating current. A higher capacitance means more energy can be stored, affecting the overall reactance in the circuit.
AC Frequency
AC frequency tells us how often the current changes direction per second and is measured in hertz (Hz). Alternating current (AC) is characterized by current flowing back and forth periodically, as opposed to direct current which flows in one direction.

The frequency of an AC circuit has a direct impact on various components, including capacitors. The higher the frequency, the more often current changes direction each second. Consequently, this quick switching affects how capacitors charge and discharge. This frequency change, therefore, alters how the capacitor reacts in the circuit, known as its reactance.
  • Higher frequency: Faster charge and discharge cycle for capacitors.
  • Lower frequency: Slower charge and discharge cycle for capacitors.
Reactance Formula
The concept of reactance comes into play significantly when we examine capacitors in AC circuits. Capacitive reactance (\(X_c\) ) is a measure of a capacitor's opposition to the change in voltage in an AC circuit. It is calculated using the formula:\[ X_c = \frac{1}{2\pi f C} \]where \(X_c\) is the reactance in ohms, \(f\) is the frequency in hertz, and \(C\) is the capacitance in farads.

The formula highlights how reactance is inversely proportional to both frequency and capacitance:
  • If frequency increases, reactance decreases.
  • If capacitance increases, reactance decreases.
This inverse relationship means that higher frequencies will lead to less opposition from the capacitor, allowing more current to pass through.
AC Circuits
An AC circuit is a type of electrical circuit in which the current alternates direction periodically. This is in contrast to a direct current (DC) where the flow is unidirectional. Understanding AC circuits involves appreciating how components such as resistors, capacitors, and inductors interact with alternating current.

Capacitors in AC circuits have a unique behavior: they resist changes in voltage rather than in current. This is different from resistors that oppose current directly. The capacitive reactance comes into play, influencing how much voltage drop occurs across the capacitor for a given frequency. In practical AC circuits:
  • The total impedance of the circuit is affected by the reactance of capacitors within it.
  • This impedance influences the current flow through the circuit.
Understanding how capacitors behave in AC circuits is essential for designing effective electronic systems.

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Most popular questions from this chapter

Multiple-Concept Example 3 reviews some of the basic ideas that are pertinent to this problem. A circuit consists of a \(215-\Omega\) resistor and a 0.200 -H inductor. These two elements are connected in series across a generator that has a frequency of \(106 \mathrm{~Hz}\) and a voltage of \(234 \mathrm{~V}\). (a) What is the current in the circuit? (b) Determine the phase angle between the current and the voltage of the generator.

A series RCL circuit has a resonant frequency of \(1500 \mathrm{~Hz}\). When operating at a frequency other than \(1500 \mathrm{~Hz}\), the circuit has a capacitive reactance of \(5.0 \Omega\) and an inductive reactance of \(30.0 \Omega .\) What are the values of (a) \(L\) and (b) \(C ?\)

A \(10.0-\Omega\) resistor, a \(12.0-\mu \mathrm{F}\) capacitor, and a \(17.0\) -mH inductor are connected in series with a 155-V generator. (a) At what frequency is the current a maximum? (b) What is the maximum value of the rms current?

Part \(a\) of the drawing shows a resistor and a charged capacitor wired in series. When the switch is closed, the capacitor discharges as charge moves from one plate to the other. Part \(b\) shows a plot of the amount of charge remaining on each plate of the capacitor as a function of time. (a) What does the time constant \(\tau\) of this resistor-capacitor circuit physically represent? (b) How is the time constant related to the resistance \(R\) and the capacitance \(C ?(\mathrm{c})\) In part \(c\) of the drawing, the switch has been removed and an ac generator has been inserted into the circuit. What is the impedance \(Z\) of this circuit? Express your answer in terms of the resistance \(R\), the time constant \(\tau\), and the frequency \(f\) of the generator. Problem The circuit elements in the drawing have the following values: \(R=18 \Omega\) \(V_{\mathrm{rms}}=24 \mathrm{~V}\) for the generator, and \(f=380 \mathrm{~Hz}\). The time constant for the circuit is \(\tau=3.0 \times 10^{-4} \mathrm{~s}\). What is the rms current in the circuit?

When a resistor is connected by itself to an ac generator, the average power delivered to the resistor is \(1.000 \mathrm{~W}\). When a capacitor is added in series with the resistor, the power delivered is \(0.500 \mathrm{~W}\). When an inductor is added in series with the resistor (without the capacitor), the power delivered is \(0.250 \mathrm{~W}\). Determine the power delivered when both the capacitor and the inductor are added in series with the resistor. Section 23.4 Resonance in Electric Circuits

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