/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 In some places, insect "zappers,... [FREE SOLUTION] | 91Ó°ÊÓ

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In some places, insect "zappers," with their blue lights, are a familiar sight on a summer's night. These devices use a high voltage to electrocute insects. One such device uses an ac voltage of \(4320 \mathrm{~V}\), which is obtained from a standard \(120.0\) - \(\mathrm{V}\) outlet by means of a transformer. If the primary coil has 21 turns, how many turns are in the secondary coil?

Short Answer

Expert verified
The secondary coil has 756 turns.

Step by step solution

01

Understand the Transformer Ratio

A transformer changes voltage levels through a ratio involving the number of turns on its primary and secondary coils. The formula is: \( \frac{V_s}{V_p} = \frac{N_s}{N_p} \), where \( V_s \) is the secondary voltage, \( V_p \) is the primary voltage, \( N_s \) is the number of turns in the secondary coil, and \( N_p \) is the number of turns in the primary coil.
02

Plug Known Values into the Formula

From the problem, \( V_s = 4320 \mathrm{~V} \), \( V_p = 120 \mathrm{~V} \), and \( N_p = 21 \). Substitute these values into the relationship: \( \frac{4320}{120} = \frac{N_s}{21} \).
03

Simplify the Voltage Ratio

Calculate \( \frac{4320}{120} \) to simplify the ratio: \( \frac{4320}{120} = 36 \). Therefore, the ratio becomes \( 36 = \frac{N_s}{21} \).
04

Solve for the Secondary Coil Turns

Rearrange the equation to solve for \( N_s \): \( N_s = 36 \times 21 \). Calculate the product to find \( N_s \).
05

Perform the Calculation

Compute \( 36 \times 21 = 756 \). So, \( N_s = 756 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Induction
Electromagnetic induction is a fundamental principle discovered by Michael Faraday, which allows electrical transformers to function. This process occurs when a changing magnetic field inside a coil induces an electromotive force (EMF) in that coil. This means that when a current flows through a primary coil, it creates a magnetic field. If there is a secondary coil within this magnetic field, a voltage is induced in the secondary coil as well.

Electromagnetic induction is the principle behind how transformers increase or decrease voltage levels. It's an amazing discovery that plays a huge role in how we power our homes and gadgets, enabling us to manipulate voltage to make electricity safer and more efficient for various uses. All this happens without having the coils physically connected, purely through changing magnetic fields. This is a natural and efficient way to produce electric currents in devices like the insect zapper mentioned in the original step by step solution.
Voltage Transformation
Voltage transformation forms the core operation of a transformer, which is vital for electrical devices to operate at required voltages. The operation relies on electromagnetic induction to convert electrical energy from one voltage level to another.

The voltage is altered through the ratio of turns between the primary and secondary coils of a transformer. This is expressed in the relation \( \frac{V_s}{V_p} = \frac{N_s}{N_p} \), where the voltage across the secondary coil, \( V_s \), over the voltage across the primary coil, \( V_p \), equals the number of turns in the secondary coil, \( N_s \), over the number of turns in the primary coil, \( N_p \). By manipulating these ratios, transformers can step-up (increase) or step-down (decrease) the voltage.

This is crucial for safely transporting electricity over long distances, reducing power losses by using high voltages. Devices such as the insect zapper manage to operate efficiently because they transform voltage to the level needed.
Coil Turns Calculation
Calculating the number of turns in a coil is an essential aspect when we deal with transformers, to ensure they provide the right voltage transformation. This calculation focuses on maintaining the ratio that allows proper operation in voltage step-up or step-down processes.

Given a transformer, if we know the voltage change needed and the number of turns in the primary coil, we can find the number of turns in the secondary coil using the formula \( \frac{V_s}{V_p} = \frac{N_s}{N_p} \). In the example provided, with a voltage from 120 V to 4320 V, and 21 turns on the primary coil, solving for the unknown secondary turns involves simple algebra:
  • First, find the voltage ratio: \( \frac{4320}{120} = 36 \).
  • Then, use this ratio: \( 36 = \frac{N_s}{21} \).
  • Finally, solve for \( N_s \), which is \( 36 \times 21 = 756 \) turns.

This calculation ensures that any transformer setup accomplishes the intended voltage change accurately and efficiently.

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Most popular questions from this chapter

The resistances of the primary and secondary coils of a transformer are 56 and \(14 \Omega\), respectively. Both coils are made from lengths of the same copper wire. The circular turns of each coil have the same diameter. Find the turns ratio \(N_{\mathrm{s}} / N_{\mathrm{p}}\).

One generator uses a magnetic field of \(0.10 \mathrm{~T}\) and has a coil area per turn of \(0.045 \mathrm{~m}^{2} . \mathrm{A}\) second generator has a coil area per turn of \(0.015 \mathrm{~m}^{2}\). The generator coils have the same number of turns and rotate at the same angular speed. What magnetic field should be used in the second generator so that its peak emf is the same as that of the first generator?

Concept Questions The rechargeable batteries for a laptop computer need a much smaller voltage than what a wall socket provides. Therefore, a transformer is plugged into the wall socket and produces the necessary voltage for charging the batteries. (a) Is the transformer a step-up or a step-down transformer? (b) Is the current that goes through the batteries greater than, equal to, or smaller than the current coming from the wall socket? (c) If the transformer has a negligible resistance, is the electric power delivered to the batteries greater than, equal to, or less than the power coming from the wall socket? In all cases, provide a reason for your answer. Problem The batteries of a laptop computer are rated at \(9.0 \mathrm{~V},\) and a current of \(225 \mathrm{~mA}\) is used to charge them. The wall socket provides a voltage of \(120 \mathrm{~V}\). (a) Determine the turns ratio of the transformer, (b) What is the current coming from the wall socket? (c) Find the power delivered by the wall socket and the power sent to the batteries. Be sure your answers are consistent with your answers to the Concept Questions.

A circular loop of wire rests on a table. A long, straight wire lies on this loop, directly over its center, as the drawing illustrates. The current \(I\) in the straight wire is decreasing. In what direction is the induced current, if any, in the loop? Give your reasoning.

A flat coil of wire has an area \(A\), \(N\) turns, and a resistance \(R\). It is situated in a magnetic field such that the normal to the coil is parallel to the magnetic field. The coil is then rotated through an angle of \(90^{\circ}\), so that the normal becomes perpendicular to the magnetic field. (a) Why is an emf induced in the coil? (b) What determines the amount of induced current in the coil? (c) How is the amount of charge \(\Delta q\) that flows related to the induced current \(I\) and the time interval \(t-t_{0}\) during which the coil rotates? The coil has an area of \(1.5 \times 10^{-3} \mathrm{~m}^{2}, 50\) turns, and a resistance of \(140 \Omega\). During the time when it is rotating, a charge of \(8.5 \times 10^{-5} \mathrm{C}\) flows in the coil. What is the magnitude of the magnetic field?

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