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A coil carries a current and experiences a torque due to a magnetic field. The value of the torque is \(80.0 \%\) of the maximum possible torque. (a) What is the smallest angle between the magnetic field and the normal to the plane of the coil? (b) Make a drawing, showing how this coil would be oriented relative to the magnetic field. Be sure to include the angle in the drawing.

Short Answer

Expert verified
The angle is approximately \(53.13^\circ\).

Step by step solution

01

Understand the relationship between torque and angle

The torque \( \tau \) experienced by a coil in a magnetic field is given by \( \tau = \tau_{max} \sin \theta \), where \( \tau_{max} \) is the maximum possible torque and \( \theta \) is the angle between the normal to the plane of the coil and the magnetic field. In this problem, \( \tau = 0.8 \times \tau_{max} \).
02

Set up the equation

Since \( \tau = 0.8 \tau_{max} \), we can set the equation \( 0.8 = \sin \theta \). We need to find the angle \( \theta \) such that this equation holds true.
03

Solve for the angle \( \theta \)

To find \( \theta \), take the inverse sine (arcsine) of both sides: \[ \theta = \arcsin(0.8) \]Calculate \( \theta \) using a calculator to find:\[ \theta \approx 53.13^\circ \]
04

Create a diagram

Draw the coil as a flat loop or circle. Draw a line perpendicular to the plane of the coil to represent the normal. Then, show the magnetic field as a vector. The angle formed between the normal and the magnetic field vector should be \( 53.13^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coil in Magnetic Field
When a coil carrying an electric current is placed in a magnetic field, it experiences a force known as magnetic torque. This torque can cause the coil to rotate. The fundamental idea is that as current flows through the coil, a magnetic moment is generated, interacting with the external magnetic field. This creates a push or pull effect on the coil.
The torque (\( \tau \)) applied to the coil is determined by three main factors:
  • The strength of the magnetic field (\( B \)).
  • The current (\( I \)) flowing through the coil.
  • The area of the coil (\( A \)).
The formula for calculating the torque is given by: \( \tau = nIAB \sin \theta \), where \( n \) is the number of turns in the coil and \( \theta \) is the angle between the normal to the coil and the magnetic field. This highlights the dependence of torque on both physical dimensions and orientation of the coil relative to the field.
The coil will experience maximum torque when the plane of the coil is perpendicular to the magnetic field, which occurs when the angle \( \theta \) is \( 90^\circ \). Understanding these principles is crucial for applications like electric motors and generators, where precise control of coil orientation in magnetic fields is required.
Angle in Magnetic Fields
The angle between the magnetic field and the normal to the plane of the coil plays a critical role in determining the magnetic torque experienced by the coil. This angle, \( \theta \), dictates how effectively the magnetic field can interact with the coil's magnetic moment.
The equation for torque, \( \tau = \tau_{max} \sin \theta \), demonstrates this relationship. Here, \( \tau_{max} \) represents the maximum possible torque, achieved when \( \theta = 90^\circ \).
In the given exercise, the torque experienced is 80% of the maximum torque, implying that \( \sin \theta = 0.8 \). To find \( \theta \), use the inverse sine function (arcsine):
  • \( \theta = \arcsin(0.8) \approx 53.13^\circ \)
This calculated angle indicates the inclination required for the normal of the coil relative to the magnetic field to achieve the specified torque. Within an educational setting, it's helpful to sketch this setup to visualize the angle clearly.
Maximum Torque
Maximum torque occurs when the coil is perfectly aligned such that its plane is perpendicular to the magnetic field. At this point, the angle \( \theta \) between the normal to the coil and the magnetic field is \( 90^\circ \). Hence, the sine of this angle is 1, maximizing the torque in the equation:\( \tau = \tau_{max} \sin \theta \).
For practical purposes, achieving maximum torque is critical in devices such as electric motors. When the orientation of the coil is perpendicular to the magnetic field, the device performs efficiently since all available magnetic force is utilized to produce motion.
To adjust a coil for maximum torque, consider:
  • Rotating the coil until its plane aligns perpendicularly to the magnetic field.
  • Ensuring no slippage or misalignment occurs, which could reduce torque.
By comprehending the conditions for maximum torque, one gains valuable insights into the optimal operation of various electromagnetic devices used in technology and engineering.

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Most popular questions from this chapter

A positively charged particle of mass \(7.2 \times 10^{-8} \mathrm{~kg}\) is traveling due east with a speed of \(85 \mathrm{~m} / \mathrm{s}\) and enters a 0.31 -T uniform magnetic field. The particle moves through onequarter of a circle in a time of \(2.2 \times 10^{-3} \mathrm{~s}\), at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge.

At a certain location, the horizontal component of the earth's magnetic field is \(2.5 \times 10^{-5} \mathrm{~T}\), due north. A proton moves eastward with just the right speed, so the magnetic force on it balances its weight. Find the speed of the proton.

In the model of the hydrogen atom due to Niels Bohr, the electron moves around the proton at a speed of \(2.2 \times 10^{6} \mathrm{~m} / \mathrm{s}\) in a circle of radius \(5.3 \times 10^{-11} \mathrm{~m}\). Considering the orbiting electron to be a small current loop, determine the magnetic moment associated with this motion. (Hint: The electron travels around the circle in a time equal to the period of the motion.)

One component of a magnetic field has a magnitude of \(0.048 \mathrm{~T}\) and points along the \(+x\) axis, while the other component has a magnitude of \(0.065 \mathrm{~T}\) and points along the \(-y\) axis. A particle carrying a charge of \(+2.0 \times 10^{-5} \mathrm{C}\) is moving along the \(+z\) axis at a speed of \(4.2 \times 10^{3} \mathrm{~m} / \mathrm{s}\). (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the \(+x\) axis.

At for help with problems like this one. A very long, hollow cylinder is formed by rolling up a thin sheet of copper. Electric charges flow along the copper sheet parallel to the axis of the cylinder. The arrangement is, in effect, a hollow tube of current \(I\). Use Ampère's law to show that the magnetic field (a) is \(\mu_{0} I /(2 \pi r)\) outside the cylinder at a distance \(r\) from the axis and \((\mathrm{b})\) is zero at any point within the hollow interior of the cylinder. (Hint: For closed paths, use circles perpendicular to and centered on the axis of the cylinder.)

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