/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 96 An electronic flash attachment f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An electronic flash attachment for a camera produces a flash by using the energy stored in a \(150-\mu \mathrm{F}\) capacitor. Between flashes, the capacitor recharges through a resistor whose resistance is chosen so the capacitor recharges with a time constant of \(3.0 \mathrm{~s}\). Determine the value of the resistance.

Short Answer

Expert verified
The resistance is 20,000 Ω.

Step by step solution

01

Understand the Time Constant Formula

The time constant \( \tau \) for an RC (resistor-capacitor) circuit is given by the formula \( \tau = R \cdot C \), where \( R \) is the resistance and \( C \) is the capacitance. We must use this formula to find the resistance \( R \).
02

Identify Known Values

We know the time constant \( \tau \) is \( 3.0 \text{ s} \) and the capacitance \( C \) is \( 150 \mu\text{F} \), or \( 150 \times 10^{-6} \text{ F} \).
03

Substitute Values into Time Constant Formula

Substitute the known values into the formula: \( 3.0 = R \times 150 \times 10^{-6} \).
04

Solve for Resistance \( R \)

Rearrange the equation to solve for \( R \): \( R = \frac{3.0}{150 \times 10^{-6}} \).
05

Calculate the Resistance

Perform the calculation: \( R = \frac{3.0}{150 \times 10^{-6}} = 20,000 \Omega \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Time Constant
The time constant, denoted as \( \tau \), is a fundamental concept in the study of RC (resistor-capacitor) circuits. This constant tells us how quickly the capacitor charges or discharges in the circuit. Specifically, the time constant is the time it takes for the charge (on charging) or the voltage (on discharging) to reach approximately 63.2% of its final value.
In an RC circuit, the time constant is calculated using the formula \( \tau = R \cdot C \), where \( R \) represents resistance and \( C \) stands for capacitance.
- A larger time constant means the circuit charges or discharges more slowly.- Conversely, a smaller time constant means the circuit charges or discharges more quickly.
Understanding this concept is crucial for designing circuits that function within desired time frames.
Resistor-Capacitor Circuit
A resistor-capacitor (RC) circuit is one of the simplest kinds of electronic circuits and is widely used for various applications.
An RC circuit consists of two main components: a resistor and a capacitor. The behavior of the circuit depends on how these components interact.
- When a voltage source is applied to an RC circuit, the capacitor begins to charge through the resistor. - The resistor regulates how fast the capacitor charges and discharges.
This charging and discharging process is characterized by the time constant, which defines how quickly the circuit responds to changes. RC circuits are often used in timing and filtering applications because of their predictable time-based response.
Capacitance
Capacitance is the ability of a system to store an electric charge. In simple terms, it indicates how much charge a capacitor can hold per unit voltage. The unit of capacitance is the farad (F), named after the scientist Michael Faraday.
A capacitor with a larger capacitance can store more charge compared to one with a smaller capacitance when subjected to the same voltage.
  • Capacitance is determined by the physical characteristics of the capacitor, specifically the area of the plates, the distance between them, and the dielectric material used.
  • In the RC circuit equation, the capacitance value \( C \) together with resistance \( R \) helps determine the time constant \( \tau \).
Many electronic devices, from small gadgets to large power systems, rely on capacitors for energy storage.
Electronic Flash
An electronic flash employs a high-voltage operation to produce brief and intense bursts of light, commonly used in photography. In the context of RC circuits, such an electronic flash unit often consists of a capacitor that stores energy and discharges it rapidly to generate the flash.
When the camera's shutter is pressed, the capacitor releases its stored energy, powering the flash bulb for a split second. This process benefits enormously from capacitors because:
  • They can release stored energy almost instantaneously, creating a bright and short-lived light.
  • Capacitors help in recharging quickly, allowing for successive flashes in a short time.
The RC circuit in an electronic flash regulates the time it takes for the capacitor to recharge, ensuring the flash is ready for the next photo. Hence, the time constant is crucial for determining how quickly the flash can be reused after firing.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

To save on heating costs, the owner of a greenhouse keeps \(660 \mathrm{~kg}\) of water around in barrels. During a winter day, the water is heated by the sun to \(10.0^{\circ} \mathrm{C}\). During the night the water freezes into ice at \(0.0^{\circ} \mathrm{C}\) in nine hours. What is the minimum ampere rating of an electric heating system \((240 \mathrm{~V})\) that would provide the same heating effect as the water does?

The average power used by a stereo speaker is \(55 \mathrm{~W}\). Assuming that the speaker can be treated as a \(4.0-\Omega\) resistance, find the peak value of the ac voltage applied to the speaker.

A battery delivering a current of 55.0 A to a circuit has a terminal voltage of \(23.4 \mathrm{~V}\). The electric power being dissipated by the internal resistance of the battery is \(34.0 \mathrm{~W}\). Find the emf of the battery,

A toaster uses a Nichrome heating wire. When the toaster is turned on at \(20^{\circ} \mathrm{C}\), the initial current is \(1.50 \mathrm{~A}\). A few seconds later, the toaster warms up and the current now has a value of \(1.30 \mathrm{~A}\). The average temperature coefficient of resistivity for Nichrome wire is \(4.5 \times 10^{-4}\left(\mathrm{C}^{0}\right)^{-1} .\) What is the temperature of the heating wire?

An electric heater is used to boil small amounts of water and consists of a \(15-\Omega\) coil that is immersed directly in the water. It operates from a \(120-\mathrm{V}\) socket. How much time is required for this heater to raise the temperature of \(0.50 \mathrm{~kg}\) of water from \(13^{\circ} \mathrm{C}\) to the normal boiling point?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.